1 00:00:00,030 --> 00:00:02,400 The following content is provided under a Creative 2 00:00:02,400 --> 00:00:03,780 Commons license. 3 00:00:03,780 --> 00:00:06,020 Your support will help MIT OpenCourseWare 4 00:00:06,020 --> 00:00:10,100 continue to offer high quality educational resources for free. 5 00:00:10,100 --> 00:00:12,670 To make a donation or to view additional materials 6 00:00:12,670 --> 00:00:16,405 from hundreds of MIT courses, visit MIT OpenCourseWare 7 00:00:16,405 --> 00:00:17,030 at ocw.mit.edu. 8 00:00:31,205 --> 00:00:32,650 QIQI WANG: Welcome to 16.90. 9 00:00:32,650 --> 00:00:35,180 I'm Professor Qiqi Wang and this is Professor Wilcox. 10 00:00:38,990 --> 00:00:44,600 So we are going to be together teaching 16.90 this year. 11 00:00:44,600 --> 00:00:47,730 So 16.90 is Introduction to Computation Methods 12 00:00:47,730 --> 00:00:49,930 for Engineering Aerospace Engineering. 13 00:00:52,500 --> 00:00:54,590 So what I'm going to do today is [INAUDIBLE] 14 00:01:02,590 --> 00:01:08,600 But before that let's go over about what this class is about. 15 00:01:08,600 --> 00:01:09,100 [INAUDIBLE] 16 00:01:12,060 --> 00:01:12,990 OK. 17 00:01:12,990 --> 00:01:16,060 So I'm first going to go over the syllabus. 18 00:01:16,060 --> 00:01:18,502 And then professor Willcox is going 19 00:01:18,502 --> 00:01:21,720 to show you something new this semester that 20 00:01:21,720 --> 00:01:23,720 is very exciting for you to-- actual a great way 21 00:01:23,720 --> 00:01:26,830 to guide yourself to learn the material yourself. 22 00:01:26,830 --> 00:01:29,042 Because this lecture is really-- this class 23 00:01:29,042 --> 00:01:33,532 is really taking advantage of the [INAUDIBLE] 24 00:01:33,532 --> 00:01:36,176 classroom structure, we really want you to learn the material 25 00:01:36,176 --> 00:01:38,180 before you come to class. 26 00:01:38,180 --> 00:01:40,700 And in class we are going to be assuming 27 00:01:40,700 --> 00:01:42,660 you have read the material and we 28 00:01:42,660 --> 00:01:46,750 are going to be solving problems together. 29 00:01:46,750 --> 00:01:51,080 So this is really not a new style. 30 00:01:51,080 --> 00:01:54,900 This style has been practiced in this department for a while. 31 00:01:54,900 --> 00:01:55,650 So lecture one. 32 00:01:59,049 --> 00:02:01,090 We are now using computers to do a lot of things. 33 00:02:01,090 --> 00:02:03,730 Every one of you are using computers 34 00:02:03,730 --> 00:02:05,230 checking email [INAUDIBLE]. 35 00:02:09,220 --> 00:02:12,410 The reason we have computers is because of things we 36 00:02:12,410 --> 00:02:15,150 are going to be talking about in this class. 37 00:02:15,150 --> 00:02:17,790 So the first real computer is designed 38 00:02:17,790 --> 00:02:25,260 not for checking emails but for computational simulation 39 00:02:25,260 --> 00:02:28,440 to help engineers solve problems in ballistics. 40 00:02:28,440 --> 00:02:32,050 And these are really aero problems. 41 00:02:32,050 --> 00:02:35,310 So we are going to see something very similar 42 00:02:35,310 --> 00:02:39,755 to the world's first computer applications in this subject. 43 00:02:43,520 --> 00:02:44,020 OK. 44 00:02:44,020 --> 00:02:48,710 So let's fast forward in time and come to today. 45 00:02:48,710 --> 00:02:51,480 Today's computer simulations are-- 46 00:02:51,480 --> 00:02:54,770 haven't become less important but increasingly important 47 00:02:54,770 --> 00:02:56,940 for studying, interpreting, and predicting 48 00:02:56,940 --> 00:02:59,320 many different processes. 49 00:02:59,320 --> 00:03:01,530 And we are in aerospace engineering 50 00:03:01,530 --> 00:03:04,228 so I'm just going to be talking about aerospace examples. 51 00:03:04,228 --> 00:03:07,100 But outside aerospace you can find 52 00:03:07,100 --> 00:03:11,820 even a lot of broad application for computational simulation. 53 00:03:11,820 --> 00:03:17,590 So this is a class even though you not end up doing aerospace, 54 00:03:17,590 --> 00:03:21,380 it is going to be also [INAUDIBLE] 55 00:03:21,380 --> 00:03:24,300 --related to either science or engineering. 56 00:03:24,300 --> 00:03:26,450 This is going to be useful. 57 00:03:26,450 --> 00:03:33,250 So two examples are simulation of spacecraft reentry. 58 00:03:33,250 --> 00:03:37,660 And this is a real thing. [INAUDIBLE] Another example 59 00:03:37,660 --> 00:03:44,462 is designing [INAUDIBLE] this is the simulation. 60 00:03:44,462 --> 00:03:47,494 And we're going to be talking about how to perform 61 00:03:47,494 --> 00:03:48,535 this kind of simulations. 62 00:03:48,535 --> 00:03:51,270 And these are [? PD's ?] because you 63 00:03:51,270 --> 00:03:55,440 have multiple spacial dimensions where you have x, y, and z. 64 00:03:55,440 --> 00:03:58,420 And if you are unsteady you also have a fourth dimension 65 00:03:58,420 --> 00:04:02,380 which is time. 66 00:04:02,380 --> 00:04:06,430 So, to solve problems using numerical methods some problems 67 00:04:06,430 --> 00:04:08,060 like that. 68 00:04:08,060 --> 00:04:10,990 It really involves two steps. 69 00:04:10,990 --> 00:04:13,620 So this subject we are going to be spending 70 00:04:13,620 --> 00:04:17,008 a lot of money talking about how to solve differential 71 00:04:17,008 --> 00:04:17,956 equations. 72 00:04:17,956 --> 00:04:21,120 But let's not forget the first step. 73 00:04:21,120 --> 00:04:25,355 That is how you would actually get this differential equation. 74 00:04:25,355 --> 00:04:28,530 OK, so the first really is to reduce a real system 75 00:04:28,530 --> 00:04:33,310 or process or [INAUDIBLE] into a mathematical model. 76 00:04:33,310 --> 00:04:35,310 And in a lot of times you are going 77 00:04:35,310 --> 00:04:37,590 to find out the mathematical model is going 78 00:04:37,590 --> 00:04:39,790 to be a differential equation. 79 00:04:39,790 --> 00:04:44,240 So to figure out what kind of mathematical model 80 00:04:44,240 --> 00:04:48,816 is suitable for the system or process you are studying you 81 00:04:48,816 --> 00:04:53,424 have to first know what are the quantities of interest. 82 00:04:53,424 --> 00:04:56,844 [INAUDIBLE] What do you want to know? 83 00:04:56,844 --> 00:04:58,140 OK. 84 00:04:58,140 --> 00:05:01,690 And what are the key processes involved? 85 00:05:01,690 --> 00:05:05,920 What approximations can we reasonably make 86 00:05:05,920 --> 00:05:11,720 that is going to lead you to [INAUDIBLE] 87 00:05:11,720 --> 00:05:14,336 And the model we are going to derive 88 00:05:14,336 --> 00:05:15,710 [INAUDIBLE] from the differential 89 00:05:15,710 --> 00:05:20,620 equation-- [INAUDIBLE] it can be linear or non-linear. 90 00:05:20,620 --> 00:05:23,170 Or you could look at the [? method outcomes, ?] 91 00:05:23,170 --> 00:05:26,360 distinguished between linear and non-linear equations-- 92 00:05:26,360 --> 00:05:31,580 [INAUDIBLE] It can be deterministic or probabilistic. 93 00:05:31,580 --> 00:05:34,700 At the end of this chapter we are going 94 00:05:34,700 --> 00:05:37,810 to be looking at [INAUDIBLE]. 95 00:05:37,810 --> 00:05:43,660 It can be static or dynamic, involve time or [INAUDIBLE]. 96 00:05:43,660 --> 00:05:46,410 It can be discrete or continuous, either based 97 00:05:46,410 --> 00:05:49,020 on [INAUDIBLE] principle [INAUDIBLE] 98 00:05:49,020 --> 00:05:56,280 of math, --of momentum, [INAUDIBLE] --or empirical. 99 00:06:01,414 --> 00:06:03,580 And once you have that you design a computation code 100 00:06:03,580 --> 00:06:05,980 and solve the mathematical model. 101 00:06:05,980 --> 00:06:08,650 So let's take a look at an example 102 00:06:08,650 --> 00:06:10,690 of a computational model. 103 00:06:10,690 --> 00:06:13,200 The model is a thermal problem. 104 00:06:13,200 --> 00:06:17,232 So this is really-- this guy is a [INAUDIBLE] 105 00:06:17,232 --> 00:06:18,190 thermodynamics problem. 106 00:06:20,980 --> 00:06:23,460 Problems like this [INAUDIBLE] where 107 00:06:23,460 --> 00:06:26,490 you have something spinning up. 108 00:06:26,490 --> 00:06:30,180 Different parts are going to heat up at different rates 109 00:06:30,180 --> 00:06:31,680 and expand at different rates. 110 00:06:31,680 --> 00:06:33,960 You want during the entire process 111 00:06:33,960 --> 00:06:36,220 of different parts expanding at different rates, 112 00:06:36,220 --> 00:06:38,761 nothing is going to heat another part. 113 00:06:38,761 --> 00:06:39,260 Right? 114 00:06:39,260 --> 00:06:42,010 You know on the spinning-- spinning [INAUDIBLE] 115 00:06:42,010 --> 00:06:45,590 or turbines which actually expands-- 116 00:06:45,590 --> 00:06:48,960 heats up faster than the outside of the turbine engine 117 00:06:48,960 --> 00:06:51,070 to actually keep the outside safe. 118 00:06:51,070 --> 00:06:52,830 So you need to really predict well 119 00:06:52,830 --> 00:06:58,740 how fast different parts heat up during the process. 120 00:06:58,740 --> 00:07:01,170 So our model problem is this. 121 00:07:01,170 --> 00:07:03,390 This is aluminum. 122 00:07:03,390 --> 00:07:10,130 It's a 3.89 cm cube, initially at room temperature. 123 00:07:10,130 --> 00:07:13,940 It is going to be heated up by this [INAUDIBLE]. 124 00:07:13,940 --> 00:07:17,400 starting at time equals t0. 125 00:07:17,400 --> 00:07:22,030 We're going to be turning off our air at time equals t1. 126 00:07:22,030 --> 00:07:25,370 So here comes the quality [INAUDIBLE] 127 00:07:25,370 --> 00:07:27,156 the measured temperature. 128 00:07:27,156 --> 00:07:31,790 So you see here it's a thermocouple basically stuck 129 00:07:31,790 --> 00:07:43,560 inside [INAUDIBLE] how this thing heats up. 130 00:07:43,560 --> 00:07:46,110 No, what I want you to do is form 131 00:07:46,110 --> 00:07:48,708 a team of either two or three. 132 00:07:52,596 --> 00:07:58,280 [INAUDIBLE] And answer this question. 133 00:08:00,840 --> 00:08:04,020 I've already given you what is the quantity of interest, 134 00:08:04,020 --> 00:08:06,820 the temperature in the middle of the cube. 135 00:08:06,820 --> 00:08:09,980 Now the question is what are the important [INAUDIBLE], 136 00:08:09,980 --> 00:08:14,400 and how to model the [INAUDIBLE] mathematically. 137 00:08:14,400 --> 00:08:15,120 OK. 138 00:08:15,120 --> 00:08:18,286 And last, I'm actually going to show you 139 00:08:18,286 --> 00:08:20,522 because this is what you are going 140 00:08:20,522 --> 00:08:21,730 to be learning in this class. 141 00:08:21,730 --> 00:08:23,340 How to use the mathematical model 142 00:08:23,340 --> 00:08:25,970 to make the prediction which means how to solve 143 00:08:25,970 --> 00:08:28,680 this equation [INAUDIBLE]. 144 00:08:28,680 --> 00:08:33,390 So, when we're here and start with these two questions, 145 00:08:33,390 --> 00:08:37,034 at the same time as you form a team 146 00:08:37,034 --> 00:08:39,234 I'm going to start [INAUDIBLE]. 147 00:08:39,234 --> 00:08:40,858 The last time we actually had more time 148 00:08:40,858 --> 00:08:44,430 for you to solve these so this time 149 00:08:44,430 --> 00:08:46,540 we are running out of time. 150 00:08:46,540 --> 00:08:52,010 I know a lot of you haven't gotten to the bottom yet. 151 00:08:52,010 --> 00:08:55,220 A lot of you I think given more time is 152 00:08:55,220 --> 00:08:58,140 going to derive the equation, especially some of you 153 00:08:58,140 --> 00:09:01,760 are looking up online and taking a lot of time to calculate. 154 00:09:01,760 --> 00:09:09,110 So here I think I'm just going to wrap up by telling you 155 00:09:09,110 --> 00:09:11,170 how I would model. 156 00:09:11,170 --> 00:09:15,200 There is no single way of modeling this. 157 00:09:15,200 --> 00:09:31,330 But, my way is just a-- OK. 158 00:09:31,330 --> 00:09:32,240 All right. 159 00:09:32,240 --> 00:09:36,660 So, what is the physical process that 160 00:09:36,660 --> 00:09:38,720 determines the quantity of interest which 161 00:09:38,720 --> 00:09:42,037 is the temperature of the cube? 162 00:09:42,037 --> 00:09:43,620 I'm saying the temperature of the cube 163 00:09:43,620 --> 00:09:48,550 because aluminum is very good conductor of heat. 164 00:09:48,550 --> 00:09:52,160 So If there is uneven heat in the temperature 165 00:09:52,160 --> 00:09:56,310 distribution inside the cube, it is going to even out very fast. 166 00:09:56,310 --> 00:09:59,506 Especially for a cube of this small size. 167 00:09:59,506 --> 00:10:01,240 All right? 168 00:10:01,240 --> 00:10:04,080 So one can assume that the temperature 169 00:10:04,080 --> 00:10:06,395 distribution inside the aluminum is 170 00:10:06,395 --> 00:10:09,410 basically uniform throughout. 171 00:10:09,410 --> 00:10:11,240 When you look at the time history 172 00:10:11,240 --> 00:10:17,050 it heats up slowly over the course of many minutes. 173 00:10:17,050 --> 00:10:20,780 The temperature-- the conduction inside the aluminum 174 00:10:20,780 --> 00:10:22,680 is actually much faster than that. 175 00:10:22,680 --> 00:10:33,790 So we can say that the temperature-- [INAUDIBLE] 176 00:10:33,790 --> 00:10:36,200 OK the temperature of the aluminum 177 00:10:36,200 --> 00:10:38,540 is only a function of time. 178 00:10:41,120 --> 00:10:48,440 So this is the temperature of the cube. 179 00:10:48,440 --> 00:10:48,974 OK. 180 00:10:48,974 --> 00:10:50,640 Now we have the temperature of the cube. 181 00:10:50,640 --> 00:10:54,250 So what governs the temperature of the cube? 182 00:10:54,250 --> 00:10:57,986 What makes the temperature of the cube change? 183 00:10:57,986 --> 00:10:59,550 Heat convection. 184 00:10:59,550 --> 00:11:00,400 OK. 185 00:11:00,400 --> 00:11:03,988 So we have heat convection. 186 00:11:07,060 --> 00:11:07,880 OK? 187 00:11:07,880 --> 00:11:09,850 We have heat convection that makes 188 00:11:09,850 --> 00:11:14,290 the delta of the internal energy of the cube. 189 00:11:14,290 --> 00:11:15,510 Right? 190 00:11:15,510 --> 00:11:16,460 Equal to what? 191 00:11:16,460 --> 00:11:21,500 So let's say that been two time points 192 00:11:21,500 --> 00:11:25,002 the change of the energy of the cube 193 00:11:25,002 --> 00:11:29,560 is equal to what-- what has contributed to the energy 194 00:11:29,560 --> 00:11:30,990 change? 195 00:11:30,990 --> 00:11:34,500 Yes, what I'm looking for is the change in the energy 196 00:11:34,500 --> 00:11:41,560 is really equal to the heat that goes into the cube plus what's 197 00:11:41,560 --> 00:11:42,630 done to the cube. 198 00:11:42,630 --> 00:11:43,560 Right? 199 00:11:43,560 --> 00:11:46,510 And nobody did any work to the cube. 200 00:11:46,510 --> 00:11:47,010 Right? 201 00:11:47,010 --> 00:11:49,800 I didn't, I don't know if you did. 202 00:11:49,800 --> 00:11:54,466 So it is only equal to the heat convection into the cube. 203 00:11:54,466 --> 00:11:56,330 All right? 204 00:11:56,330 --> 00:12:00,305 So this is how you start putting the physical process 205 00:12:00,305 --> 00:12:03,040 into equations. 206 00:12:03,040 --> 00:12:06,390 Now let's look at how do we relate 207 00:12:06,390 --> 00:12:11,450 both sides of the equation to the temperature of the cube. 208 00:12:11,450 --> 00:12:12,150 OK? 209 00:12:12,150 --> 00:12:16,240 How do you relate the delta in the internal energy 210 00:12:16,240 --> 00:12:18,600 to the temperature of the cube? 211 00:12:18,600 --> 00:12:20,610 So the change in the energy relates 212 00:12:20,610 --> 00:12:22,000 to the change in temperature. 213 00:12:22,000 --> 00:12:22,240 Right? 214 00:12:22,240 --> 00:12:24,240 How does it relate to the change in temperature? 215 00:12:26,630 --> 00:12:27,870 Delta t times what? 216 00:12:30,591 --> 00:12:31,090 C? 217 00:12:34,803 --> 00:12:35,302 Cp? 218 00:12:38,120 --> 00:12:42,280 Times the mass. 219 00:12:42,280 --> 00:12:43,070 Right? 220 00:12:43,070 --> 00:12:47,030 OK and the mass we-- although we don't know exactly what it is, 221 00:12:47,030 --> 00:12:51,070 we can look up for the density of the aluminum 222 00:12:51,070 --> 00:12:57,850 and the size of the cube. 223 00:12:57,850 --> 00:12:58,610 Right? 224 00:12:58,610 --> 00:13:02,460 So this is going to give us the changing energy. 225 00:13:02,460 --> 00:13:08,420 And what is the-- what determines how much heat 226 00:13:08,420 --> 00:13:09,956 has convected it into the cube? 227 00:13:09,956 --> 00:13:10,456 [INAUDIBLE] 228 00:13:15,380 --> 00:13:15,880 OK. 229 00:13:15,880 --> 00:13:19,260 So I think I should write it like this. 230 00:13:19,260 --> 00:13:20,990 What determines Q? 231 00:13:20,990 --> 00:13:25,400 What determines the heat that goes through the surface 232 00:13:25,400 --> 00:13:27,780 of the cube into the cube? 233 00:13:27,780 --> 00:13:33,680 So that is Q from the gun minus Q-- 234 00:13:33,680 --> 00:13:36,250 so this is gun to cube right? 235 00:13:36,250 --> 00:13:40,060 So this is cube to air. 236 00:13:40,060 --> 00:13:43,850 So this is gun to cube minus cube to air. 237 00:13:43,850 --> 00:13:48,600 Now how do you model-- how does the rate of heat 238 00:13:48,600 --> 00:13:50,130 transfer from the gun to the cube 239 00:13:50,130 --> 00:13:54,060 depends on the temperature. 240 00:13:54,060 --> 00:13:57,900 And how does the rate of-- how does the heat 241 00:13:57,900 --> 00:14:01,420 convect from the cube to the air? 242 00:14:01,420 --> 00:14:01,920 [INAUDIBLE] 243 00:14:16,300 --> 00:14:18,540 Yeah, they linearly depend on the difference 244 00:14:18,540 --> 00:14:19,840 in the temperature. 245 00:14:19,840 --> 00:14:23,880 So if you look back on unit five notes-- OK. 246 00:14:23,880 --> 00:14:27,310 So this is-- these are heat convection right? 247 00:14:27,310 --> 00:14:28,870 Heat convection. 248 00:14:28,870 --> 00:14:32,220 And the way you blow air from the gun to the cube 249 00:14:32,220 --> 00:14:34,930 is forced convection. 250 00:14:34,930 --> 00:14:35,660 OK. 251 00:14:35,660 --> 00:14:39,470 So this is C-- the rate of the forced convection, 252 00:14:39,470 --> 00:14:42,210 it is proportional to the temperature 253 00:14:42,210 --> 00:14:46,310 of the hot air minus the temperature of the cube 254 00:14:46,310 --> 00:14:48,150 times the coefficient. 255 00:14:48,150 --> 00:14:53,610 And the coefficient is the forced convection coefficient 256 00:14:53,610 --> 00:14:58,237 in the air times the area of the convection. 257 00:14:58,237 --> 00:14:59,403 And for example, [INAUDIBLE] 258 00:15:10,170 --> 00:15:14,720 So maybe we can just say 2 times the square is 259 00:15:14,720 --> 00:15:17,090 the temperature of the heat. 260 00:15:17,090 --> 00:15:25,810 And maybe the cube to air is C free convection times now 261 00:15:25,810 --> 00:15:29,612 four [INAUDIBLE] now is T minus T air. 262 00:15:33,050 --> 00:15:35,590 All right? 263 00:15:35,590 --> 00:15:42,190 And this is the rate of heat conversion. 264 00:15:42,190 --> 00:15:47,280 Now we time the delta of time. 265 00:15:47,280 --> 00:15:52,355 We are going to get the amount of heat that went into the cube 266 00:15:52,355 --> 00:15:56,170 during a small time unit. 267 00:15:56,170 --> 00:16:00,410 Now this is going to give us a differential equation. 268 00:16:00,410 --> 00:16:03,520 Because if we let the delta T, the amount 269 00:16:03,520 --> 00:16:06,590 of time we are looking at goes to zero, 270 00:16:06,590 --> 00:16:11,340 we are going to get to the equation of Cp times rho d 271 00:16:11,340 --> 00:16:15,870 cubed dT/dt. 272 00:16:15,870 --> 00:16:20,740 So this is the rate of change in the temperature 273 00:16:20,740 --> 00:16:29,185 equal to C force times 2 d squared T H minus T minus C 274 00:16:29,185 --> 00:16:35,871 free, 4 d squared T minus T air. 275 00:16:35,871 --> 00:16:36,370 right 276 00:16:36,370 --> 00:16:38,310 So this is the differential equation we get. 277 00:16:41,750 --> 00:16:45,630 Now what changes when we turn off the heat gun? 278 00:16:45,630 --> 00:16:49,850 C force is gone and the C free becomes [INAUDIBLE]. 279 00:16:49,850 --> 00:16:50,550 Right. 280 00:16:50,550 --> 00:16:51,980 So that's the difference. 281 00:16:51,980 --> 00:16:57,990 And let's go to Matlab, and I wrote a code 282 00:16:57,990 --> 00:17:03,220 for simulating this. 283 00:17:03,220 --> 00:17:04,819 So here is the parameters. 284 00:17:04,819 --> 00:17:06,530 Ambient temperature we said today 285 00:17:06,530 --> 00:17:11,480 is a little bit colder than I thought. 286 00:17:11,480 --> 00:17:15,560 And the hot air temperature, if we look at this, 287 00:17:15,560 --> 00:17:17,530 I think is like 106 or something. 288 00:17:17,530 --> 00:17:22,730 Let's put 106. 289 00:17:22,730 --> 00:17:28,860 And the start time in seconds I actually don't know, so let's 290 00:17:28,860 --> 00:17:30,580 just put 0 here. 291 00:17:30,580 --> 00:17:33,630 And the T stopped in seconds. 292 00:17:33,630 --> 00:17:36,470 What time is it like 11 minutes? 293 00:17:36,470 --> 00:17:40,490 What is 11 minutes in-- so this is 11 minutes right? 294 00:17:40,490 --> 00:17:42,312 OK. 295 00:17:42,312 --> 00:17:46,600 tend I think I'll just do this. 296 00:17:46,600 --> 00:17:47,210 OK. 297 00:17:47,210 --> 00:17:50,610 So these are what I looked up online. 298 00:17:50,610 --> 00:17:54,970 Some of the values for the free air convection 299 00:17:54,970 --> 00:17:56,922 and the forced air convection. 300 00:17:56,922 --> 00:17:58,380 And the [INAUDIBLE] of the aluminum 301 00:17:58,380 --> 00:18:02,040 cube the density of aluminum, and the specific heat 302 00:18:02,040 --> 00:18:04,160 capacitance. 303 00:18:04,160 --> 00:18:04,780 All right. 304 00:18:04,780 --> 00:18:09,420 And these you don't need to look at them because they are never 305 00:18:09,420 --> 00:18:13,360 used in the code because radiation exactly 306 00:18:13,360 --> 00:18:14,440 is not important. 307 00:18:14,440 --> 00:18:18,330 So heating and we are using [INAUDIBLE] so solve 308 00:18:18,330 --> 00:18:19,790 the equation. 309 00:18:19,790 --> 00:18:24,320 I'm basically saying that the heating rate is 310 00:18:24,320 --> 00:18:28,280 proportional to two sides, and the cooling rate et. cetera, 311 00:18:28,280 --> 00:18:30,230 and we are also doing the cooling. 312 00:18:30,230 --> 00:18:33,880 So let's do the simulation. 313 00:18:33,880 --> 00:18:41,110 We are getting a plot like this. 314 00:18:41,110 --> 00:18:56,670 And let's compare our temperatur.txt-- [INAUDIBLE] 315 00:19:08,354 --> 00:19:10,360 Oh, OK. 316 00:19:10,360 --> 00:19:13,890 I need to get rid of this. 317 00:19:13,890 --> 00:19:16,090 Let me push the stop. 318 00:19:20,500 --> 00:19:23,440 Not responding. 319 00:19:23,440 --> 00:19:24,260 Error writing. 320 00:19:24,260 --> 00:19:24,760 [INAUDIBLE] 321 00:19:39,491 --> 00:19:39,990 OK. 322 00:19:45,100 --> 00:19:46,030 Now we are plotting. 323 00:19:49,520 --> 00:19:52,844 So look at the difference between the simulation 324 00:19:52,844 --> 00:19:53,635 and the experiment. 325 00:19:57,370 --> 00:19:58,570 It's huge. 326 00:19:58,570 --> 00:20:00,120 Right? 327 00:20:00,120 --> 00:20:03,660 So what is causing this Difference 328 00:20:03,660 --> 00:20:06,520 It is because now here what I said 329 00:20:06,520 --> 00:20:10,220 is the force convection coefficient is 330 00:20:10,220 --> 00:20:14,100 10 watt per meter square plus K. Right? 331 00:20:14,100 --> 00:20:21,220 Now let's go to the internet and search for force convection 332 00:20:21,220 --> 00:20:24,080 coefficient of air. 333 00:20:27,150 --> 00:20:28,040 Engineering toolbox. 334 00:20:34,000 --> 00:20:35,360 Is it this one? 335 00:20:39,080 --> 00:20:40,940 Yes. 336 00:20:40,940 --> 00:20:47,510 Forced convection of air goes all the way from 10 to 200. 337 00:20:47,510 --> 00:20:48,160 OK. 338 00:20:48,160 --> 00:20:51,790 And here I am actually putting the lower bound. 339 00:20:51,790 --> 00:20:59,260 If I put something like 200 and do the simulation again, 340 00:20:59,260 --> 00:21:08,290 and do the experiment again, this is what I got. 341 00:21:08,290 --> 00:21:08,790 OK. 342 00:21:08,790 --> 00:21:16,340 I've got a much better match and I also have my free convection 343 00:21:16,340 --> 00:21:17,450 to be 5. 344 00:21:17,450 --> 00:21:21,160 If you look over the internet free convection 345 00:21:21,160 --> 00:21:23,880 goes from 5 to 25. 346 00:21:23,880 --> 00:21:24,420 OK. 347 00:21:24,420 --> 00:21:31,170 And also if I go to 25 I think I am also 348 00:21:31,170 --> 00:21:34,540 going to be getting a much better match. 349 00:21:34,540 --> 00:21:35,040 OK. 350 00:21:35,040 --> 00:21:38,520 So the rate of decaying is much better now. 351 00:21:38,520 --> 00:21:41,382 And another thing I assume there are only 352 00:21:41,382 --> 00:21:46,360 two sides of the cube are being heated. [INAUDIBLE] 353 00:21:46,360 --> 00:21:50,234 But actually if you switch over to the next problem 354 00:21:50,234 --> 00:21:54,360 you will see more than two sides are being heated. 355 00:21:54,360 --> 00:21:56,470 So that is actually another motivation 356 00:21:56,470 --> 00:21:59,390 for why we need to look at not only one simulation 357 00:21:59,390 --> 00:22:01,222 but several simulations. 358 00:22:01,222 --> 00:22:04,416 And that is leading into the fourth part 359 00:22:04,416 --> 00:22:08,396 of this subject, probabilistic simulations. 360 00:22:08,396 --> 00:22:11,690 Because when you look at a lot of physical phenomena 361 00:22:11,690 --> 00:22:15,030 there is a lot of uncertainty in it 362 00:22:15,030 --> 00:22:19,470 when you look at the range of coefficients 363 00:22:19,470 --> 00:22:23,880 you can possibly get in modeling physics. 364 00:22:23,880 --> 00:22:27,030 And convection is a primary example 365 00:22:27,030 --> 00:22:29,960 if this because there are so much uncertainty 366 00:22:29,960 --> 00:22:33,480 in what rate you can get. 367 00:22:33,480 --> 00:22:33,980 All right. 368 00:22:33,980 --> 00:22:36,411 So this is our first lecture. 369 00:22:36,411 --> 00:22:38,516 I will see you next Monday. 370 00:22:38,516 --> 00:22:42,100 But remember, one thing is you need to read and do 371 00:22:42,100 --> 00:22:44,830 the homework, do the embedded questions 372 00:22:44,830 --> 00:22:48,410 before you come to class next Monday.