1 00:00:06,750 --> 00:00:07,530 PROFESSOR: Hi everyone. 2 00:00:07,530 --> 00:00:10,280 Welcome to the biochemistry help sessions. 3 00:00:10,280 --> 00:00:14,710 This is the covalent bonds, chirality, electronegativity, 4 00:00:14,710 --> 00:00:16,740 and hydrogen bonds module. 5 00:00:16,740 --> 00:00:19,570 In this help session, I'll be going over the first practice 6 00:00:19,570 --> 00:00:21,270 problem in this module. 7 00:00:21,270 --> 00:00:23,900 If you have not had a chance to look over this problem 8 00:00:23,900 --> 00:00:28,470 yourself, please go back, look over the problem, try it, and 9 00:00:28,470 --> 00:00:30,055 then come back and we'll go through it together. 10 00:00:39,480 --> 00:00:42,360 Now that you've had a chance to look at the problem, let's 11 00:00:42,360 --> 00:00:43,770 get started. 12 00:00:43,770 --> 00:00:48,330 First of all, what is this molecule? 13 00:00:48,330 --> 00:00:51,280 To me, this molecule looks like it's a sugar. 14 00:00:51,280 --> 00:00:55,340 It's a polysaccharide, to be exact, and it's actually a 15 00:00:55,340 --> 00:00:58,330 chain of glucose molecules. 16 00:00:58,330 --> 00:01:02,020 So in this problem, the first part of the problem asks us to 17 00:01:02,020 --> 00:01:05,600 name each circled bond in this molecule. 18 00:01:05,600 --> 00:01:10,040 So the first circled bond is right here, and this is a 19 00:01:10,040 --> 00:01:13,320 carbon to carbon bond. 20 00:01:13,320 --> 00:01:16,310 Now, the first thing that we can notice about this bond is 21 00:01:16,310 --> 00:01:21,050 that it's a carbon to carbon bond, and we know that carbon 22 00:01:21,050 --> 00:01:24,990 only forms covalent bonds in biological systems. 23 00:01:24,990 --> 00:01:28,430 So the first thing we can say is that this bond is a 24 00:01:28,430 --> 00:01:29,680 covalent bond. 25 00:01:35,010 --> 00:01:38,300 Second, we need to decide if this bond is 26 00:01:38,300 --> 00:01:40,700 polar or non polar. 27 00:01:40,700 --> 00:01:43,240 And the way we decide that is we look at the 28 00:01:43,240 --> 00:01:46,560 electronegativity of the atoms involved. 29 00:01:46,560 --> 00:01:49,330 In this bond we have two carbons. 30 00:01:49,330 --> 00:01:51,860 And so since they're the same atoms, we know that they have 31 00:01:51,860 --> 00:01:54,040 the same electronegativity. 32 00:01:54,040 --> 00:01:57,900 And bonds between two atoms of the same electronegativity are 33 00:01:57,900 --> 00:01:59,185 non polar bonds. 34 00:02:04,500 --> 00:02:07,970 So we know that this carbon to carbon bond is 35 00:02:07,970 --> 00:02:10,600 covalent and non polar. 36 00:02:10,600 --> 00:02:13,800 Now we'll look at the second bond circled. 37 00:02:13,800 --> 00:02:18,130 This bond is a carbon to oxygen bond. 38 00:02:18,130 --> 00:02:20,950 It is similar to the first bond in that it involves 39 00:02:20,950 --> 00:02:23,900 carbon, so we can say that it is a covalent bond. 40 00:02:29,290 --> 00:02:32,490 What's different about this bond, however, is that it is a 41 00:02:32,490 --> 00:02:35,340 carbon bound to an oxygen. 42 00:02:35,340 --> 00:02:38,030 And when you look at the electronegativities of carbon 43 00:02:38,030 --> 00:02:42,000 and oxygen, you find that oxygen is much more 44 00:02:42,000 --> 00:02:44,520 electronegative than carbon. 45 00:02:44,520 --> 00:02:50,020 So in a carbon to oxygen bond, you actually have oxygen is 46 00:02:50,020 --> 00:02:53,790 greedy, and it's going to take the electrons closer to itself 47 00:02:53,790 --> 00:02:56,850 and not share them equally with the carbon. 48 00:02:56,850 --> 00:03:00,650 So in this kind of bond, oxygen will be slightly 49 00:03:00,650 --> 00:03:06,000 negative and carbon will be slightly positive, because the 50 00:03:06,000 --> 00:03:10,900 electrons are attracted closer to the oxygen. 51 00:03:10,900 --> 00:03:14,150 In a bond where you have a slightly negative side and a 52 00:03:14,150 --> 00:03:17,525 slightly positive side, we call this a polar bond. 53 00:03:21,310 --> 00:03:26,330 So we can say that a carbon to oxygen bond is a polar bond. 54 00:03:26,330 --> 00:03:30,950 So in this first part, we learned that the difference 55 00:03:30,950 --> 00:03:34,120 between a covalent and a non polar and a 56 00:03:34,120 --> 00:03:37,000 covalent polar bond. 57 00:03:37,000 --> 00:03:40,590 The second part of the problem, part B, asks if this 58 00:03:40,590 --> 00:03:44,280 sugar molecule is soluble in water. 59 00:03:44,280 --> 00:03:48,050 So first you need to know whether this molecule is polar 60 00:03:48,050 --> 00:03:49,670 or non polar. 61 00:03:49,670 --> 00:03:53,450 And since we know that it has carbon to oxygen bonds, we 62 00:03:53,450 --> 00:03:57,980 know that it has polar bonds, so it is a polar molecule. 63 00:03:57,980 --> 00:03:59,690 And what do we know about water? 64 00:03:59,690 --> 00:04:03,170 We know water is an oxygen bound to two hydrogens. 65 00:04:03,170 --> 00:04:06,960 And since it has this very electronegative oxygen, we 66 00:04:06,960 --> 00:04:10,620 know that it is also a polar molecule. 67 00:04:10,620 --> 00:04:14,520 And an easy rule of thumb is that like dissolves like. 68 00:04:14,520 --> 00:04:18,190 So since these are both polar molecules, sugar dissolves 69 00:04:18,190 --> 00:04:20,089 very easily in water. 70 00:04:20,089 --> 00:04:24,150 If you had a fat, on the other hand, which is a non polar 71 00:04:24,150 --> 00:04:26,300 molecule, it would not dissolve in water. 72 00:04:26,300 --> 00:04:29,030 That's why when you put oil and water, you 73 00:04:29,030 --> 00:04:32,430 don't see it dissolve. 74 00:04:32,430 --> 00:04:37,710 So now that we understand why sugar dissolves very easily in 75 00:04:37,710 --> 00:04:40,870 water, we'll move into the third part of the problem, 76 00:04:40,870 --> 00:04:45,450 where they ask what types of bonds can form between these 77 00:04:45,450 --> 00:04:47,460 long polymers. 78 00:04:47,460 --> 00:04:53,470 So looking at these polymers, the first thing that we can 79 00:04:53,470 --> 00:05:00,130 notice is that there are these oxygens and hydrogens on each 80 00:05:00,130 --> 00:05:02,250 of the polymers. 81 00:05:02,250 --> 00:05:06,780 And looking at these, we can see how you can have hydrogen 82 00:05:06,780 --> 00:05:10,260 bonding, which we learned about in class, between the 83 00:05:10,260 --> 00:05:14,940 oxygen of one sugar molecule to the hydrogen of another 84 00:05:14,940 --> 00:05:19,920 sugar molecule, thus forming hydrogen bonding networks 85 00:05:19,920 --> 00:05:24,080 between the sugar molecules. 86 00:05:24,080 --> 00:05:27,960 And in this way, they can interact with each other. 87 00:05:27,960 --> 00:05:32,030 So in this help session we have covered the difference 88 00:05:32,030 --> 00:05:36,400 between a covalent non polar bond and a 89 00:05:36,400 --> 00:05:37,770 covalent polar bond. 90 00:05:37,770 --> 00:05:44,280 We have covered why water can dissolve sugar very easily, 91 00:05:44,280 --> 00:05:47,220 and what kind of bonds can form between 92 00:05:47,220 --> 00:05:49,170 these two sugar molecules. 93 00:05:49,170 --> 00:05:50,420 Thank you.