1 00:00:00,090 --> 00:00:02,490 The following content is provided under a Creative 2 00:00:02,490 --> 00:00:04,030 Commons license. 3 00:00:04,030 --> 00:00:06,330 Your support will help MIT OpenCourseWare 4 00:00:06,330 --> 00:00:10,720 continue to offer high quality educational resources for free. 5 00:00:10,720 --> 00:00:13,320 To make a donation or view additional materials 6 00:00:13,320 --> 00:00:17,280 from hundreds of MIT courses, visit MIT OpenCourseWare 7 00:00:17,280 --> 00:00:18,270 at ocw.mit.edu. 8 00:00:21,230 --> 00:00:24,930 JOHN ESSIGMANN: We're now on storyboard 12, session 13. 9 00:00:24,930 --> 00:00:26,810 Let's take a look first at panel A. 10 00:00:26,810 --> 00:00:28,370 I mentioned earlier that respiration 11 00:00:28,370 --> 00:00:31,460 is the oxidative metabolism of all metabolic fuels, 12 00:00:31,460 --> 00:00:33,890 carbohydrates as well as lipids. 13 00:00:33,890 --> 00:00:36,410 If we were starting with a carbohydrate then 14 00:00:36,410 --> 00:00:40,250 respiration starts with the pyruvate dehydrogenase reaction 15 00:00:40,250 --> 00:00:42,770 and then proceeds into the TCA cycle, 16 00:00:42,770 --> 00:00:47,330 and then into electron transport and oxidative phosphorylation. 17 00:00:47,330 --> 00:00:50,570 If the acetylcholine comes from fatty acid oxidation, which 18 00:00:50,570 --> 00:00:52,460 we'll cover later, then we do not 19 00:00:52,460 --> 00:00:55,520 have to do the pyruvate dehydrogenase step. 20 00:00:55,520 --> 00:00:58,820 Three molecules of NADH and one molecule of FADH2 21 00:00:58,820 --> 00:01:01,370 are produced as the carriers of electrons 22 00:01:01,370 --> 00:01:03,740 from the intermediates in the TCA cycle 23 00:01:03,740 --> 00:01:08,120 from each input molecule of acetyl coenzyme A. 24 00:01:08,120 --> 00:01:09,740 As I mentioned a number of times, 25 00:01:09,740 --> 00:01:13,970 we look at NADH and FADH2 as relatively mobile electron 26 00:01:13,970 --> 00:01:15,124 carriers. 27 00:01:15,124 --> 00:01:16,790 They're going to be picking up electrons 28 00:01:16,790 --> 00:01:19,460 from intermediates and biochemical pathways 29 00:01:19,460 --> 00:01:21,500 and then they bring those electrons 30 00:01:21,500 --> 00:01:23,810 into the mitochondrial inner membrane, where 31 00:01:23,810 --> 00:01:26,900 the reducing equivalents are passed along to the electron 32 00:01:26,900 --> 00:01:28,310 transport chain. 33 00:01:28,310 --> 00:01:30,260 Ultimately the electrons will end up 34 00:01:30,260 --> 00:01:34,120 being deposited into oxygen to make water. 35 00:01:34,120 --> 00:01:36,520 Let's turn to panel B where I'm going to start 36 00:01:36,520 --> 00:01:38,440 laying out the big picture. 37 00:01:38,440 --> 00:01:40,930 In this small cartoon we see fuel being 38 00:01:40,930 --> 00:01:43,420 oxidized to carbon dioxide. 39 00:01:43,420 --> 00:01:46,090 The electrons are passed to either in NAD-plus, 40 00:01:46,090 --> 00:01:49,830 or FAD to form the reduced cofactor. 41 00:01:49,830 --> 00:01:51,910 The reduced co-factors find their way 42 00:01:51,910 --> 00:01:54,220 to the mitochondrial inner membrane 43 00:01:54,220 --> 00:01:56,110 and the electrons, or reducing equivalents, 44 00:01:56,110 --> 00:01:59,050 are passed to oxygen to make water. 45 00:01:59,050 --> 00:02:01,390 This process is highly exergonic. 46 00:02:01,390 --> 00:02:03,370 And we'll do a model calculation in a minute 47 00:02:03,370 --> 00:02:06,310 to show just how energy yielding it is, 48 00:02:06,310 --> 00:02:09,830 resulting in the liberation of a lot of free energy. 49 00:02:09,830 --> 00:02:13,480 That energy is captured by the movement of protons 50 00:02:13,480 --> 00:02:15,760 from one side of the mitochondrial inner membrane 51 00:02:15,760 --> 00:02:18,310 to the other side of the membrane. 52 00:02:18,310 --> 00:02:21,970 In this process you're taking a low concentration of protons 53 00:02:21,970 --> 00:02:25,540 and creating a relatively high concentration of protons. 54 00:02:25,540 --> 00:02:28,990 That's an uphill process that's going to require an energy 55 00:02:28,990 --> 00:02:31,870 input, and the energy from nutrient oxidation 56 00:02:31,870 --> 00:02:35,650 is what powers this generation of an ion gradient. 57 00:02:35,650 --> 00:02:38,890 Concentrating the protons in a small defined space 58 00:02:38,890 --> 00:02:41,230 is kind of like charging a battery. 59 00:02:41,230 --> 00:02:44,830 It took energy to create that high concentration of protons. 60 00:02:44,830 --> 00:02:48,820 We'll see that nature invented a way to channel the protons back 61 00:02:48,820 --> 00:02:53,110 through a device and a way to capture the energy released 62 00:02:53,110 --> 00:02:55,390 when the gradient is dissipated. 63 00:02:55,390 --> 00:02:57,820 That energy can be captured in various ways, 64 00:02:57,820 --> 00:03:01,860 enabling us to be able to do useful things with it. 65 00:03:01,860 --> 00:03:03,740 For example, the energy could be used 66 00:03:03,740 --> 00:03:06,830 to accomplish the otherwise energy requiring process 67 00:03:06,830 --> 00:03:10,160 of putting a phosphate onto ADP to make ATP, 68 00:03:10,160 --> 00:03:13,970 and that way the energy is captured in a chemical bond. 69 00:03:13,970 --> 00:03:16,280 Alternatively, let's think of a situation in which 70 00:03:16,280 --> 00:03:18,380 you may need to generate heat. 71 00:03:18,380 --> 00:03:20,060 You could allow the protons simply 72 00:03:20,060 --> 00:03:23,090 to flow back across the membrane through a channel. 73 00:03:23,090 --> 00:03:24,830 The energy of the proton gradient 74 00:03:24,830 --> 00:03:27,170 would then be released as heat. 75 00:03:27,170 --> 00:03:30,260 Thirdly, we can perhaps allow the protons to flow back 76 00:03:30,260 --> 00:03:33,530 through a device that creates rotary movement 77 00:03:33,530 --> 00:03:35,780 and that's how, for example, a flagellar 78 00:03:35,780 --> 00:03:38,690 motor can spin to move a bacterium from one 79 00:03:38,690 --> 00:03:40,400 place to another. 80 00:03:40,400 --> 00:03:43,490 Let's now turn to panel C. We've seen 81 00:03:43,490 --> 00:03:45,590 earlier that oxidation can result 82 00:03:45,590 --> 00:03:48,710 in the production of NADH or FADH2. 83 00:03:48,710 --> 00:03:51,590 To begin let's consider NADH. 84 00:03:51,590 --> 00:03:54,650 In this panel you can see the NADH oxidized 85 00:03:54,650 --> 00:03:56,210 where the electrons flow-- and it 86 00:03:56,210 --> 00:03:57,890 doesn't matter what the path of the flow 87 00:03:57,890 --> 00:04:01,250 is-- all the way to oxygen. Thermodynamics 88 00:04:01,250 --> 00:04:04,210 gives us the tools to calculate how much energy you 89 00:04:04,210 --> 00:04:06,910 would get in this process. 90 00:04:06,910 --> 00:04:09,520 JoAnne taught you a lot about thermodynamics 91 00:04:09,520 --> 00:04:11,710 in biological systems, And this is just 92 00:04:11,710 --> 00:04:13,540 a repeat of what she said. 93 00:04:13,540 --> 00:04:15,520 But what I'm going to do is put what 94 00:04:15,520 --> 00:04:19,149 she said into a concrete, practical example. 95 00:04:19,149 --> 00:04:21,430 I've drawn out at the bottom of panel C 96 00:04:21,430 --> 00:04:24,640 the overall reaction, showing electrons going from NADH 97 00:04:24,640 --> 00:04:27,940 to oxygen in the forward direction. 98 00:04:27,940 --> 00:04:31,360 Now, of course, we could also think about the back reaction, 99 00:04:31,360 --> 00:04:34,630 where electrons would flow from water into NAD-plus 100 00:04:34,630 --> 00:04:36,400 to form NADH. 101 00:04:36,400 --> 00:04:39,110 At this point this is just an equation on a piece of paper 102 00:04:39,110 --> 00:04:40,840 and we don't know in which direction 103 00:04:40,840 --> 00:04:43,240 the reaction is overall favorable. 104 00:04:43,240 --> 00:04:45,850 That is, is it favorable in the forward direction 105 00:04:45,850 --> 00:04:49,120 as drawn, left to right, or in the reverse direction, 106 00:04:49,120 --> 00:04:50,560 right to left? 107 00:04:50,560 --> 00:04:52,990 The reaction from left to right is the direction 108 00:04:52,990 --> 00:04:57,130 we usually think about in the context of nutrient oxidation. 109 00:04:57,130 --> 00:05:00,070 Interestingly, the reaction from right to left 110 00:05:00,070 --> 00:05:01,670 is photosynthesis. 111 00:05:01,670 --> 00:05:04,060 So both directions are biologically used, 112 00:05:04,060 --> 00:05:06,010 but we'll see that one of the directions 113 00:05:06,010 --> 00:05:09,010 will require substantial energy input in order 114 00:05:09,010 --> 00:05:11,880 to make it biologically useful. 115 00:05:11,880 --> 00:05:14,370 Probably you can appreciate that photosynthesis 116 00:05:14,370 --> 00:05:17,130 is the energy requiring process, because we all 117 00:05:17,130 --> 00:05:18,840 know that sunlight is needed to make 118 00:05:18,840 --> 00:05:22,440 the process thermodynamically and kinetically favorable. 119 00:05:22,440 --> 00:05:24,960 We don't cover photosynthesis in 5.07, so let 120 00:05:24,960 --> 00:05:27,080 me say a few words about it. 121 00:05:27,080 --> 00:05:30,660 In photosynthesis nature takes electrons from water 122 00:05:30,660 --> 00:05:34,110 and uses them to reduce NADP-plus to NADPH. 123 00:05:34,110 --> 00:05:37,560 Note that I said NADP-plus, and not NAD-plus, 124 00:05:37,560 --> 00:05:40,770 but for the purposes here they are equivalent. 125 00:05:40,770 --> 00:05:43,380 In the case of photosynthesis we know intuitively 126 00:05:43,380 --> 00:05:45,810 that the overall process is powered by light, 127 00:05:45,810 --> 00:05:48,630 so in going from right to left the process intuitively, 128 00:05:48,630 --> 00:05:51,390 once again, should require energy. 129 00:05:51,390 --> 00:05:53,760 By contrast, nutrient oxidation, where 130 00:05:53,760 --> 00:05:56,430 we go from left to right in this equation, 131 00:05:56,430 --> 00:05:59,280 should be a process that generates energy. 132 00:05:59,280 --> 00:06:03,220 But intuition aside, let's do the calculation. 133 00:06:03,220 --> 00:06:06,060 So the question is, in which direction 134 00:06:06,060 --> 00:06:09,270 is the equation at the bottom of panel C thermodynamically 135 00:06:09,270 --> 00:06:14,600 favorable-- left to right or right to left? 136 00:06:14,600 --> 00:06:17,380 Let's take a look now at panel D. 137 00:06:17,380 --> 00:06:19,450 You'll see here that I have split the master 138 00:06:19,450 --> 00:06:22,060 equation into half reactions. 139 00:06:22,060 --> 00:06:24,340 I always write out the half reaction 140 00:06:24,340 --> 00:06:26,330 in the direction of reduction. 141 00:06:26,330 --> 00:06:28,870 For example, look at the second half reaction. 142 00:06:28,870 --> 00:06:31,540 It shows that half a mole of oxygen 143 00:06:31,540 --> 00:06:34,880 plus two protons, plus two electrons, go to water. 144 00:06:34,880 --> 00:06:36,790 Again, I've written out these reactions 145 00:06:36,790 --> 00:06:38,250 in the direction of reduction. 146 00:06:38,250 --> 00:06:40,330 It's just the way I do it. 147 00:06:40,330 --> 00:06:42,370 Next I go to the redox chart, that 148 00:06:42,370 --> 00:06:45,940 is the table of redox potentials of electrochemical reactions, 149 00:06:45,940 --> 00:06:49,330 and I figure out what the standard energies are for each 150 00:06:49,330 --> 00:06:51,070 of these half reactions. 151 00:06:51,070 --> 00:06:56,470 As you can see, it's 0.32 volts, and, plus 0.82 volts 152 00:06:56,470 --> 00:06:59,660 respectively, for the two half reactions. 153 00:06:59,660 --> 00:07:02,260 Next I use a variant of the Nernst equation 154 00:07:02,260 --> 00:07:04,630 to calculate the free energy and ultimately 155 00:07:04,630 --> 00:07:06,740 the directionality of the reaction. 156 00:07:06,740 --> 00:07:10,840 The equation I use is delta G naught prime equals 157 00:07:10,840 --> 00:07:13,810 N times Faraday's constant, times the difference 158 00:07:13,810 --> 00:07:16,980 in the reduction potentials of the two half reactions. 159 00:07:16,980 --> 00:07:20,380 To find delta E naught prime, we look 160 00:07:20,380 --> 00:07:22,360 at the reaction that I've written out, 161 00:07:22,360 --> 00:07:24,340 the overall reaction, and we looked 162 00:07:24,340 --> 00:07:27,550 at see which is the electron acceptor, 163 00:07:27,550 --> 00:07:30,040 in which is the electron donor the way 164 00:07:30,040 --> 00:07:32,110 the reaction was written. 165 00:07:32,110 --> 00:07:34,480 Then we subtract the reduction potential 166 00:07:34,480 --> 00:07:40,130 of the electron receptor from that of the electron donor. 167 00:07:40,130 --> 00:07:43,070 The way the equation is written, left to right, oxygen 168 00:07:43,070 --> 00:07:44,930 is the electron acceptor. 169 00:07:44,930 --> 00:07:49,460 It's reduction potential is plus 0.82 volts, so delta E naught 170 00:07:49,460 --> 00:07:55,580 prime is plus 0.8 to minus a minus 0.32, 171 00:07:55,580 --> 00:08:00,870 or a total of plus 1.14 volts. 172 00:08:00,870 --> 00:08:02,630 In the Nernst equation, the number 173 00:08:02,630 --> 00:08:04,970 of electrons transferred in this case is two, 174 00:08:04,970 --> 00:08:08,600 and Faraday's constant is 96.4 kilojoules 175 00:08:08,600 --> 00:08:11,340 per mole times volts. 176 00:08:11,340 --> 00:08:13,650 If you do the math, or as we say at MIT, 177 00:08:13,650 --> 00:08:15,960 plug and chug, what you find out is 178 00:08:15,960 --> 00:08:18,950 that the free energy change of the reaction that's written, 179 00:08:18,950 --> 00:08:25,500 the NADH oxidation reaction, is minus 220 kilojoules per mole. 180 00:08:25,500 --> 00:08:29,100 This number is negative and that means the reaction is favorable 181 00:08:29,100 --> 00:08:31,520 as drawn. 182 00:08:31,520 --> 00:08:35,090 That is, the reaction goes from left to right. 183 00:08:35,090 --> 00:08:37,940 The 220 kilojoules is the amount of energy 184 00:08:37,940 --> 00:08:40,580 that's available for the three purposes of the pathway. 185 00:08:40,580 --> 00:08:47,140 That is, ATP synthesis, heat generation, or movement. 186 00:08:47,140 --> 00:08:51,910 If we were going to make ATP, we would divide 220 by 32, 187 00:08:51,910 --> 00:08:54,670 because we get about 32 kilojoules of energy 188 00:08:54,670 --> 00:08:57,855 by hydrolysis of ATP, and we can calculate 189 00:08:57,855 --> 00:08:59,230 that we're going to get something 190 00:08:59,230 --> 00:09:03,400 in the order of about 3 ATPs for every NADH that 191 00:09:03,400 --> 00:09:07,560 gives up two electrons to the electron transport chain. 192 00:09:07,560 --> 00:09:10,740 We could easily do the same oxidation reaction and study 193 00:09:10,740 --> 00:09:13,890 FADH2, but in this case, we would calculate 194 00:09:13,890 --> 00:09:17,280 that we would get actually less energy, because the oxidation 195 00:09:17,280 --> 00:09:21,330 potential of flavins, as compared to NAD, is different. 196 00:09:21,330 --> 00:09:24,780 In that case, that is, FADH2 oxidation, 197 00:09:24,780 --> 00:09:28,950 you would get only about two ATPs per FADH2 oxidized. 198 00:09:28,950 --> 00:09:32,960 So the FADH2 produced in the succinate dehydrogenase 199 00:09:32,960 --> 00:09:35,550 step of the TCA cycle is less energy 200 00:09:35,550 --> 00:09:38,760 yielding than, for example, the oxidation of malate 201 00:09:38,760 --> 00:09:43,850 to oxaloacetate that occurs later in the pathway. 202 00:09:43,850 --> 00:09:46,150 Let's turn now to storyboard 13. 203 00:09:46,150 --> 00:09:49,100 We now have an idea of the rough amount of energy 204 00:09:49,100 --> 00:09:52,870 that's going to be generated by nutrient oxidation. 205 00:09:52,870 --> 00:09:54,910 Next we're going to look a little bit more 206 00:09:54,910 --> 00:09:57,700 in detail at the mechanism by which the electrons are 207 00:09:57,700 --> 00:10:00,550 transported from the reduced substances 208 00:10:00,550 --> 00:10:04,840 that constitute our electron donors, NADH and FADH2, 209 00:10:04,840 --> 00:10:08,830 to molecular oxygen, or whatever the terminal electron 210 00:10:08,830 --> 00:10:12,920 acceptor is in the biological system under study. 211 00:10:12,920 --> 00:10:15,380 As was seen, the electron transfer 212 00:10:15,380 --> 00:10:18,620 process that we've been studying liberates energy, 213 00:10:18,620 --> 00:10:21,290 and that energy is going to be used to power pumps that 214 00:10:21,290 --> 00:10:25,520 will transport protons from the matrix of the mitochondrian 215 00:10:25,520 --> 00:10:29,300 out into the intermembrane space between the mitochondrial inner 216 00:10:29,300 --> 00:10:31,400 and outer membranes. 217 00:10:31,400 --> 00:10:32,870 In the case of electron transport 218 00:10:32,870 --> 00:10:35,660 with the goal of ATP synthesis, the protons 219 00:10:35,660 --> 00:10:38,360 that are generated in the intermembrane space 220 00:10:38,360 --> 00:10:40,640 will be allowed to flow back through a device 221 00:10:40,640 --> 00:10:42,620 that mechanically couples motion-- 222 00:10:42,620 --> 00:10:44,600 that is the spinning of a shaft-- 223 00:10:44,600 --> 00:10:47,660 to drive conformational changes in enzymes 224 00:10:47,660 --> 00:10:51,500 that will allow the otherwise endergonic synthesis of ATP 225 00:10:51,500 --> 00:10:54,800 from ADP in inorganic phosphate. 226 00:10:54,800 --> 00:10:58,900 That machine is called the ATP synthase. 227 00:10:58,900 --> 00:11:00,970 Let's look at panel A. This panel 228 00:11:00,970 --> 00:11:04,150 shows the details of the electron transport system. 229 00:11:04,150 --> 00:11:05,809 It looks a little bit complicated, 230 00:11:05,809 --> 00:11:08,350 but let's not lose sight of the fact that what it's all about 231 00:11:08,350 --> 00:11:12,280 is powering pumps, pumps that pump protons. 232 00:11:12,280 --> 00:11:14,020 In the lower left of the panel we 233 00:11:14,020 --> 00:11:18,340 see the TCA cycle generating NADH and FADH2. 234 00:11:18,340 --> 00:11:22,270 The NADH approaches complex one of the mitochondrial inner 235 00:11:22,270 --> 00:11:24,270 membrane. 236 00:11:24,270 --> 00:11:29,310 Complex one is in an NADH dehydrogenase enzyme. 237 00:11:29,310 --> 00:11:31,980 The enzyme has a flavin that accepts the electrons 238 00:11:31,980 --> 00:11:36,090 from NADH, passes them along to iron sulfur centers, 239 00:11:36,090 --> 00:11:38,064 and then to a variety of cytochromes. 240 00:11:38,064 --> 00:11:40,230 It moves the electrons up to the point where they're 241 00:11:40,230 --> 00:11:42,000 going to be transferred to coenzyme 242 00:11:42,000 --> 00:11:45,270 Q. In its oxidized form, coenzyme Q 243 00:11:45,270 --> 00:11:47,370 binds to complex one. 244 00:11:47,370 --> 00:11:49,650 The oxidized form of coenzyme Q will 245 00:11:49,650 --> 00:11:52,140 be reduced first to a semiquinone 246 00:11:52,140 --> 00:11:55,380 and then to a hydroquinone, which are located, as shown, 247 00:11:55,380 --> 00:11:58,710 inside the mitochondrial inner membrane. 248 00:11:58,710 --> 00:12:01,110 We usually draw them as being free floating 249 00:12:01,110 --> 00:12:04,440 within the membrane, but that's probably inaccurate. 250 00:12:04,440 --> 00:12:06,270 These co-factors are probably bound 251 00:12:06,270 --> 00:12:10,140 to physical entities inside the mitochondrial inner membrane. 252 00:12:10,140 --> 00:12:14,430 The picture also shows FADH2 from the TCA cycle interacting 253 00:12:14,430 --> 00:12:17,430 with complex two, which is a flavin containing enzyme, 254 00:12:17,430 --> 00:12:20,010 and it will also transfer its electrons 255 00:12:20,010 --> 00:12:22,230 to the oxidized form of coenzyme Q, 256 00:12:22,230 --> 00:12:25,190 ultimately to create the reduced coenzyme 257 00:12:25,190 --> 00:12:28,590 QH2 which is the hydroquinone. 258 00:12:28,590 --> 00:12:31,520 Just as a point of reference to the TCA cycle, 259 00:12:31,520 --> 00:12:35,900 complex two is also known as succinate dehydrogenase. 260 00:12:35,900 --> 00:12:38,780 We haven't done fatty acid oxidation yet, 261 00:12:38,780 --> 00:12:41,300 but there's a step in fatty acid oxidation 262 00:12:41,300 --> 00:12:45,050 in which an alkane is converted to an alkene. 263 00:12:45,050 --> 00:12:47,360 The electrons from that oxidation reaction 264 00:12:47,360 --> 00:12:50,810 go through a flavin protein called ETF-pre, 265 00:12:50,810 --> 00:12:54,770 for electron transferring flavor protein, and once again 266 00:12:54,770 --> 00:12:57,320 those electrons flow into coenzyme Q 267 00:12:57,320 --> 00:13:01,230 to form the reduced form of coenzyme Q. 268 00:13:01,230 --> 00:13:04,470 Remember when we talked about the glycerol three phosphate 269 00:13:04,470 --> 00:13:05,120 shuttle? 270 00:13:05,120 --> 00:13:07,350 I mentioned that there's a mitochondrial membrane 271 00:13:07,350 --> 00:13:11,280 associated glycerol three phosphate dehydrogenase. 272 00:13:11,280 --> 00:13:14,490 You can see that enzyme at the top part of the inner membrane 273 00:13:14,490 --> 00:13:16,010 as I've drawn it. 274 00:13:16,010 --> 00:13:18,150 And once again, flavin in that enzyme 275 00:13:18,150 --> 00:13:20,730 will carry the electrons into coenzyme Q, 276 00:13:20,730 --> 00:13:25,300 generating reduced form of the co-factor QH2. 277 00:13:25,300 --> 00:13:27,520 The left part of this picture pretty neatly 278 00:13:27,520 --> 00:13:31,870 shows how nutrient oxidation can channel the electrons 279 00:13:31,870 --> 00:13:34,240 into a common mobile electron carrier, 280 00:13:34,240 --> 00:13:37,000 coenzyme Q. Lots of different fuels 281 00:13:37,000 --> 00:13:41,130 give up their electrons to a common electron carrier. 282 00:13:41,130 --> 00:13:43,840 The hydroquinone QH2 will then go and interact 283 00:13:43,840 --> 00:13:47,250 with complex three of the electron transport chain. 284 00:13:47,250 --> 00:13:49,990 In complex three, electrons will be transported 285 00:13:49,990 --> 00:13:52,960 through a number of different electron relay stations 286 00:13:52,960 --> 00:13:55,900 and ultimately be picked up by cytochrome C, which 287 00:13:55,900 --> 00:13:59,750 is initially in its plus three oxidation state. 288 00:13:59,750 --> 00:14:02,740 Cytochrome C is reduced by the single electron 289 00:14:02,740 --> 00:14:04,870 coming through complex three. 290 00:14:04,870 --> 00:14:09,520 In this process its iron is reduced to its plus two state. 291 00:14:09,520 --> 00:14:11,980 This electron on cytochrome C then 292 00:14:11,980 --> 00:14:14,710 migrates across the outer surface 293 00:14:14,710 --> 00:14:16,930 of the inner membrane of the mitochondrian 294 00:14:16,930 --> 00:14:19,630 to interact with complex four. 295 00:14:19,630 --> 00:14:21,430 When it interacts with complex four, 296 00:14:21,430 --> 00:14:24,910 the reduced form cytochrome C gives up its electron 297 00:14:24,910 --> 00:14:27,370 to a copper residue on the copper 298 00:14:27,370 --> 00:14:31,910 A subunit of complex four. 299 00:14:31,910 --> 00:14:35,810 In the figure, this complex is called CuA. 300 00:14:35,810 --> 00:14:40,560 the more common name for complex four is cytochrome C oxidase. 301 00:14:40,560 --> 00:14:45,180 So cytochrome c oxidase oxidizes is the iron back 302 00:14:45,180 --> 00:14:49,590 to its iron three oxidation state, then cytochrome C 303 00:14:49,590 --> 00:14:52,050 migrates back to complex three where 304 00:14:52,050 --> 00:14:54,910 it's able to pick up another electron. 305 00:14:54,910 --> 00:14:58,390 We can think of cytochrome C as a mobile electron carrier that 306 00:14:58,390 --> 00:15:01,420 shuttles an electron along the inner surface 307 00:15:01,420 --> 00:15:04,790 of the mitochondrial inner membrane. 308 00:15:04,790 --> 00:15:08,150 Looking back at complex four, or cytochrome C oxidase, 309 00:15:08,150 --> 00:15:11,480 the electrons are passed from cytochrome A 310 00:15:11,480 --> 00:15:13,550 to a series of other electron carriers, 311 00:15:13,550 --> 00:15:16,700 and ultimately they flow into molecular oxygen. 312 00:15:16,700 --> 00:15:20,250 Molecular oxygen is anchored on one side to heme A3 313 00:15:20,250 --> 00:15:23,110 and on the other side to copper B. 314 00:15:23,110 --> 00:15:26,470 Oxygen undergoes a four electron reduction and picks 315 00:15:26,470 --> 00:15:30,910 up four protons along the way to form two molecules of water. 316 00:15:30,910 --> 00:15:34,150 If the electrons started with NADH and ends up in oxygen 317 00:15:34,150 --> 00:15:37,690 to form water, you get 220 kilojoules of energy. 318 00:15:37,690 --> 00:15:39,440 And as I said, you get somewhat less 319 00:15:39,440 --> 00:15:42,910 of your electrons started out as a reduced flavin. 320 00:15:42,910 --> 00:15:45,070 Now let's look at panel B. I want 321 00:15:45,070 --> 00:15:47,920 to say a few words at the outset about proton pumps, 322 00:15:47,920 --> 00:15:51,220 keeping in mind that the reason electrons were moved 323 00:15:51,220 --> 00:15:55,330 through the electron transport chain was to power these pumps. 324 00:15:55,330 --> 00:15:59,080 In the lower left part of the figure, we can see complex one. 325 00:15:59,080 --> 00:16:03,070 The transit of electrons through complex one from NADH 326 00:16:03,070 --> 00:16:05,830 results in the transport of four protons 327 00:16:05,830 --> 00:16:09,610 from the mitochondrial matrix into the intermembrane space. 328 00:16:09,610 --> 00:16:13,330 That is, two electrons from NADH are transported, 329 00:16:13,330 --> 00:16:15,700 and coincident with that, four protons 330 00:16:15,700 --> 00:16:19,060 are pumped into the intermembrane space. 331 00:16:19,060 --> 00:16:20,740 Later we'll see that complex three 332 00:16:20,740 --> 00:16:23,530 is the location of something called the Q cycle. 333 00:16:23,530 --> 00:16:25,660 I'm going to cover the proton pumping 334 00:16:25,660 --> 00:16:28,450 properties of the Q cycle in some detail 335 00:16:28,450 --> 00:16:30,400 in the next storyboard. 336 00:16:30,400 --> 00:16:32,620 The passage of those two electrons 337 00:16:32,620 --> 00:16:35,710 through complex three results in the transport 338 00:16:35,710 --> 00:16:40,960 of an additional four protons into the intermembrane space. 339 00:16:40,960 --> 00:16:44,320 Lastly, the transit of electrons through complex four, 340 00:16:44,320 --> 00:16:46,660 the cytochrome C oxidase, results 341 00:16:46,660 --> 00:16:48,820 in the transport of another two protons 342 00:16:48,820 --> 00:16:51,750 into the intermembrane space. 343 00:16:51,750 --> 00:16:55,050 Now let's look at panel C. Adding things up, 344 00:16:55,050 --> 00:16:56,820 if we start with two electrons coming 345 00:16:56,820 --> 00:17:00,270 from NADH we transport about 10 protons 346 00:17:00,270 --> 00:17:01,530 into the intermembrane space. 347 00:17:01,530 --> 00:17:05,880 That's enough to make about three molecules of ATP. 348 00:17:05,880 --> 00:17:09,359 If our electrons start with FADH2 reduced flavin, 349 00:17:09,359 --> 00:17:12,230 we only transport about six protons. 350 00:17:12,230 --> 00:17:14,550 That's enough to make two ATPs. 351 00:17:14,550 --> 00:17:17,490 If you remember, making ATP is only one of the things 352 00:17:17,490 --> 00:17:20,430 that we can do with the power of the proton gradient. 353 00:17:20,430 --> 00:17:22,140 I mentioned earlier that we can also use 354 00:17:22,140 --> 00:17:24,800 it to generate heat and motion. 355 00:17:24,800 --> 00:17:27,140 Let me talk for a minute about why one 356 00:17:27,140 --> 00:17:29,060 would want to generate heat. 357 00:17:29,060 --> 00:17:31,160 Newborn babies are like small balls. 358 00:17:31,160 --> 00:17:34,410 They have a high surface to volume ratio. 359 00:17:34,410 --> 00:17:36,320 Their high surface to volume ratio 360 00:17:36,320 --> 00:17:39,090 makes heat loss a very significant reality, 361 00:17:39,090 --> 00:17:41,690 and, in fact, a problem for the newborn. 362 00:17:41,690 --> 00:17:44,390 They have, therefore, specialized mitochondria 363 00:17:44,390 --> 00:17:47,600 in their neck in an area called brown fat. 364 00:17:47,600 --> 00:17:50,630 The fat is brown because it is loaded with highly colored 365 00:17:50,630 --> 00:17:51,950 mitochondria. 366 00:17:51,950 --> 00:17:53,870 These mitochondria have a protein 367 00:17:53,870 --> 00:17:57,650 that enables the protons pumped into the intermembrane space 368 00:17:57,650 --> 00:18:00,950 to flow back freely into the mitochondrial matrix 369 00:18:00,950 --> 00:18:02,840 with the generation of heat. 370 00:18:02,840 --> 00:18:06,530 That is, they don't make ATP in the brown fat, they make heat. 371 00:18:06,530 --> 00:18:09,680 This helps promote thermal regulation in the baby. 372 00:18:09,680 --> 00:18:11,780 This is also the mechanism by which 373 00:18:11,780 --> 00:18:14,240 hibernating animals, such as a bear, 374 00:18:14,240 --> 00:18:16,790 can maintain body temperature during the winter 375 00:18:16,790 --> 00:18:19,440 when the bear is hibernating. 376 00:18:19,440 --> 00:18:22,200 This process overall is called uncoupling 377 00:18:22,200 --> 00:18:24,690 of electron transport, from the process 378 00:18:24,690 --> 00:18:27,300 that we're going to be looking at next, oxidative 379 00:18:27,300 --> 00:18:28,470 phosphorylation. 380 00:18:28,470 --> 00:18:31,830 Oxidative phosphorylation is the process by which 381 00:18:31,830 --> 00:18:35,180 we're going to be making ATP. 382 00:18:35,180 --> 00:18:37,730 Uncoupling is also a process used 383 00:18:37,730 --> 00:18:40,070 by some flowers that have to come up 384 00:18:40,070 --> 00:18:42,500 through frozen ground in the springtime. 385 00:18:42,500 --> 00:18:45,170 For example, the skunk cabbage and the crocus 386 00:18:45,170 --> 00:18:47,960 are very good at uncoupling electron transport 387 00:18:47,960 --> 00:18:50,180 from oxidative phosphorylation. 388 00:18:50,180 --> 00:18:53,090 They let the protons in the proton gradient flow 389 00:18:53,090 --> 00:18:55,370 back across the mitochondrial inner membrane, 390 00:18:55,370 --> 00:18:58,520 and by doing so these plants are able to generate 391 00:18:58,520 --> 00:19:00,620 heat that will allow them to grow 392 00:19:00,620 --> 00:19:02,630 at subfreezing temperatures. 393 00:19:02,630 --> 00:19:07,020 In other words, the plant itself becomes a little heater. 394 00:19:07,020 --> 00:19:08,850 At this point, let me give you a little bit 395 00:19:08,850 --> 00:19:12,120 of a preview of how we use this proton gradient in order 396 00:19:12,120 --> 00:19:13,890 to synthesize ATP. 397 00:19:13,890 --> 00:19:15,750 As we have seen, it took energy in order 398 00:19:15,750 --> 00:19:19,170 to create a gradient in which there are protons 399 00:19:19,170 --> 00:19:22,980 in the intermembrane space, and protons are chemical entities, 400 00:19:22,980 --> 00:19:25,770 so we've created a chemical gradient. 401 00:19:25,770 --> 00:19:29,190 But also, we're putting a very high positive charge 402 00:19:29,190 --> 00:19:32,640 density in the small, enclosed intermembrane space. 403 00:19:32,640 --> 00:19:36,450 So we have also created an electrochemical gradient. 404 00:19:36,450 --> 00:19:39,960 It is the release of those gradients that empowers 405 00:19:39,960 --> 00:19:42,420 many of our vital processes. 406 00:19:42,420 --> 00:19:46,350 For a final comment please see panel D. Peter Mitchell figured 407 00:19:46,350 --> 00:19:49,230 out how the energy in that electrochemical gradient 408 00:19:49,230 --> 00:19:51,510 could be released and converted into the energy 409 00:19:51,510 --> 00:19:53,640 it takes to make chemical bonds. 410 00:19:53,640 --> 00:19:56,070 Mitchell's conclusions serve as the basis 411 00:19:56,070 --> 00:19:58,230 of what is called the chemiosmotic coupling 412 00:19:58,230 --> 00:20:02,870 hypothesis, and we'll be looking at that in some detail later.