1 00:00:00,120 --> 00:00:02,430 The following content is provided under a Creative 2 00:00:02,430 --> 00:00:03,820 Commons license. 3 00:00:03,820 --> 00:00:06,030 Your support will help MIT OpenCourseWare 4 00:00:06,030 --> 00:00:10,120 continue to offer high quality educational resources for free. 5 00:00:10,120 --> 00:00:12,660 To make a donation or to view additional materials 6 00:00:12,660 --> 00:00:16,620 from hundreds of MIT courses, visit MIT OpenCourseWare 7 00:00:16,620 --> 00:00:17,850 at ocw.mit.edu. 8 00:00:21,310 --> 00:00:26,332 PROFESSOR: The outline for today is a little bit more review 9 00:00:26,332 --> 00:00:28,540 of feeling the power of the creation and annihilation 10 00:00:28,540 --> 00:00:31,420 operators. 11 00:00:31,420 --> 00:00:35,320 They enable you to do anything with harmonic oscillators, 12 00:00:35,320 --> 00:00:37,310 really fast. 13 00:00:37,310 --> 00:00:42,760 And so you don't spend time thinking 14 00:00:42,760 --> 00:00:44,860 about how to do the math. 15 00:00:44,860 --> 00:00:48,760 You think about the meaning of the problem and understanding 16 00:00:48,760 --> 00:00:51,940 how to manipulate, or how to understand 17 00:00:51,940 --> 00:00:54,780 harmonic oscillators. 18 00:00:54,780 --> 00:00:56,740 And then the exciting thing. 19 00:00:56,740 --> 00:00:59,790 The real Schrodinger equation is not the one 20 00:00:59,790 --> 00:01:01,160 we've been playing with. 21 00:01:01,160 --> 00:01:04,060 It's the time dependent Schrodinger equation. 22 00:01:04,060 --> 00:01:09,330 And I like to introduce the time independent one 23 00:01:09,330 --> 00:01:15,840 first, because it enables you to sort of develop some insight 24 00:01:15,840 --> 00:01:18,030 and assemble some of the tools before we 25 00:01:18,030 --> 00:01:21,450 hit the really serious stuff. 26 00:01:21,450 --> 00:01:25,970 And so I will talk about this and use the time dependent 27 00:01:25,970 --> 00:01:28,740 Schrodinger equation to show what 28 00:01:28,740 --> 00:01:37,600 it takes to get a motion of this product of the psi star psi. 29 00:01:37,600 --> 00:01:38,350 What does it take? 30 00:01:38,350 --> 00:01:42,750 It takes a superposition state consisting of at least 31 00:01:42,750 --> 00:01:45,660 two different energies. 32 00:01:45,660 --> 00:01:48,830 Then this normalization integral-- 33 00:01:48,830 --> 00:01:52,940 well, you'd expect normalization, or something 34 00:01:52,940 --> 00:01:56,150 like this to be preserved. 35 00:01:56,150 --> 00:02:00,910 And in fact, the normalization is time independent. 36 00:02:00,910 --> 00:02:04,910 Then, if we calculate-- 37 00:02:04,910 --> 00:02:08,570 now, this is a vector rather than just a simple coordinate. 38 00:02:08,570 --> 00:02:13,810 If we calculate the expectation value of the position, 39 00:02:13,810 --> 00:02:19,610 and the expectation value of the momentum, 40 00:02:19,610 --> 00:02:23,030 Ehrenfest's theorem tells you that this 41 00:02:23,030 --> 00:02:25,820 is going to describe the motion of the center of the wave 42 00:02:25,820 --> 00:02:27,170 packet. 43 00:02:27,170 --> 00:02:30,380 And the motion of the center of the wave packet 44 00:02:30,380 --> 00:02:32,720 is following Newton's laws. 45 00:02:32,720 --> 00:02:34,050 No surprise. 46 00:02:34,050 --> 00:02:37,490 And so we're seeing how classical mechanics 47 00:02:37,490 --> 00:02:40,680 is given back to you once we start 48 00:02:40,680 --> 00:02:43,470 making particle-like states. 49 00:02:43,470 --> 00:02:46,380 We can see how these particle-like states evolve. 50 00:02:46,380 --> 00:02:51,510 But there is a lot more than just particle-like behavior. 51 00:02:51,510 --> 00:02:56,070 You would, perhaps, challenge any outfielder for the Red Sox 52 00:02:56,070 --> 00:03:00,810 to go beyond calculating the center of the wave packet. 53 00:03:00,810 --> 00:03:02,149 That's what they know to do. 54 00:03:02,149 --> 00:03:03,690 But they don't know some other things 55 00:03:03,690 --> 00:03:06,280 like survival probability, how fast 56 00:03:06,280 --> 00:03:09,870 does the wave packet move away from its birthplace, 57 00:03:09,870 --> 00:03:15,360 or the wave packet does stuff and wanders around and comes 58 00:03:15,360 --> 00:03:18,450 back and rephases sometimes. 59 00:03:18,450 --> 00:03:22,080 And sometimes it just dephases. 60 00:03:22,080 --> 00:03:25,260 And these are words that you're going to want 61 00:03:25,260 --> 00:03:28,030 to put into your vocabulary. 62 00:03:28,030 --> 00:03:30,900 So there's a lot of really beautiful stuff 63 00:03:30,900 --> 00:03:33,480 when we start looking at the time dependent Schrodinger 64 00:03:33,480 --> 00:03:34,860 equation. 65 00:03:34,860 --> 00:03:40,770 And we are going to mostly consider the time dependent 66 00:03:40,770 --> 00:03:43,950 Schrodinger equation when the Hamiltonian is 67 00:03:43,950 --> 00:03:47,460 independent of time, because we can get our arms around that 68 00:03:47,460 --> 00:03:48,800 really easily. 69 00:03:48,800 --> 00:03:51,390 But when the Hamiltonian is dependent on time, 70 00:03:51,390 --> 00:03:54,450 then it opens up a world of complexity 71 00:03:54,450 --> 00:03:59,400 that is really best left to a more advanced course. 72 00:04:02,860 --> 00:04:09,210 But how do molecules get excited from one state to another? 73 00:04:09,210 --> 00:04:11,300 A time dependent Hamiltonian. 74 00:04:11,300 --> 00:04:15,440 So we are going to have to at least briefly talk 75 00:04:15,440 --> 00:04:18,800 about a time dependent Hamiltonian and what it does. 76 00:04:18,800 --> 00:04:20,959 And you'll see that eventually. 77 00:04:26,480 --> 00:04:29,800 I'm first going to do a little bit of review 78 00:04:29,800 --> 00:04:33,280 of the a's and a daggers. 79 00:04:33,280 --> 00:04:36,310 So the most important thing is, we're 80 00:04:36,310 --> 00:04:41,860 going to have some problem where we have this x operator 81 00:04:41,860 --> 00:04:44,810 to some integer power. 82 00:04:44,810 --> 00:04:48,220 And so we need to be able to relate that 83 00:04:48,220 --> 00:04:49,840 to the a's and a daggers. 84 00:05:00,750 --> 00:05:04,800 I'll drop the hats, because we know they're there. 85 00:05:04,800 --> 00:05:09,390 And one of the nice things is, if we have this operator 86 00:05:09,390 --> 00:05:16,010 to the nth power, we have this co-factor to the nth power. 87 00:05:16,010 --> 00:05:17,762 So we don't ever have to deal with it 88 00:05:17,762 --> 00:05:19,970 until the end of the problem when we say, oh, wow, we 89 00:05:19,970 --> 00:05:21,230 had x to the n. 90 00:05:21,230 --> 00:05:25,621 Well, we have then n h bar. 91 00:05:25,621 --> 00:05:26,120 I'm sorry. 92 00:05:26,120 --> 00:05:30,042 We have h bar over 2 mu n n over 2 power. 93 00:05:32,900 --> 00:05:34,940 So it really saves a lot of writing. 94 00:05:34,940 --> 00:05:38,150 And it means you solve one problem 95 00:05:38,150 --> 00:05:40,160 for a harmonic oscillator. 96 00:05:40,160 --> 00:05:43,110 And you've solved it for all harmonic oscillators. 97 00:05:43,110 --> 00:05:45,990 And this is just details about what is the mass 98 00:05:45,990 --> 00:05:50,830 and what is the force constant, which you need to know. 99 00:05:50,830 --> 00:05:52,430 And there is a similar thing for p. 100 00:05:54,990 --> 00:05:57,360 So that opens the door. 101 00:05:57,360 --> 00:06:00,720 It says, OK, we have some problem involving 102 00:06:00,720 --> 00:06:03,765 the coordinate and the momentum, some function of the coordinate 103 00:06:03,765 --> 00:06:08,130 and momentum, and we want to know things 104 00:06:08,130 --> 00:06:10,290 about the coordinate and momentum. 105 00:06:10,290 --> 00:06:15,070 And so we use this operator algebra. 106 00:06:15,070 --> 00:06:27,760 And so a operating on psi v gives v square root v minus 1. 107 00:06:27,760 --> 00:06:29,490 And a dagger, we know that. 108 00:06:29,490 --> 00:06:31,080 So that's hardwired. 109 00:06:31,080 --> 00:06:35,400 But suppose we wanted a to the 5th, 110 00:06:35,400 --> 00:06:40,810 operating on psi v. Well, what do we do? 111 00:06:40,810 --> 00:06:46,720 Well, we start, and we start operating on... 112 00:06:46,720 --> 00:06:48,900 You know, if this were a complicated operator, 113 00:06:48,900 --> 00:06:52,440 we would take the rightmost piece of that operator 114 00:06:52,440 --> 00:06:54,430 and operate on the wave function. 115 00:06:54,430 --> 00:07:02,260 And that will give us v and then v minus 1 and then v minus 2, 116 00:07:02,260 --> 00:07:04,154 v minus 3. 117 00:07:04,154 --> 00:07:05,070 I've got five of them. 118 00:07:05,070 --> 00:07:06,495 1, 2, 3, 4, 5. 119 00:07:06,495 --> 00:07:08,640 v minus 4. 120 00:07:08,640 --> 00:07:12,080 Square root psi v minus 5. 121 00:07:15,080 --> 00:07:15,860 OK. 122 00:07:15,860 --> 00:07:17,450 It's mechanical. 123 00:07:17,450 --> 00:07:19,370 You don't remember this. 124 00:07:19,370 --> 00:07:23,720 You generate this one step at a time. 125 00:07:23,720 --> 00:07:25,570 And it's automatic. 126 00:07:25,570 --> 00:07:27,110 And so it doesn't stress your brain. 127 00:07:27,110 --> 00:07:28,430 You can be thinking about the next thing 128 00:07:28,430 --> 00:07:29,846 while you're writing that garbage. 129 00:07:37,290 --> 00:07:40,320 We have this number operator, which 130 00:07:40,320 --> 00:07:43,920 is a friend, because it enables you to just 131 00:07:43,920 --> 00:07:45,840 get rid of a bunch of terms. 132 00:07:45,840 --> 00:07:50,340 The number operator is a dagger a, and the number operator 133 00:07:50,340 --> 00:07:58,660 operating on psi v gives v psi v. 134 00:07:58,660 --> 00:08:03,790 If we want any harmonic oscillator function, 135 00:08:03,790 --> 00:08:15,190 we can operate on psi 0 with a dagger to the v power. 136 00:08:15,190 --> 00:08:18,580 And then we have to correct, because you 137 00:08:18,580 --> 00:08:24,420 know that this operating v times on this will give psi v. 138 00:08:24,420 --> 00:08:27,730 But it will also give a bunch of garbage, right? 139 00:08:27,730 --> 00:08:29,800 And you want to cancel that garbage. 140 00:08:29,800 --> 00:08:32,919 And so you write v factorial minus 1/2. 141 00:08:36,980 --> 00:08:39,409 And so that gives you the normalized function. 142 00:08:39,409 --> 00:08:43,100 So these are really, really simple things. 143 00:08:43,100 --> 00:08:45,954 And most of them, once you've thought about it a little bit, 144 00:08:45,954 --> 00:08:47,120 you can figure out yourself. 145 00:08:51,790 --> 00:08:53,580 OK. 146 00:08:53,580 --> 00:09:01,590 Now, many problems involve x, x cubed, x to the 4th. 147 00:09:01,590 --> 00:09:05,340 And we know that x is this. 148 00:09:05,340 --> 00:09:08,046 And x squared is this squared. 149 00:09:08,046 --> 00:09:10,020 And x cubed is this cubed. 150 00:09:10,020 --> 00:09:12,580 And so we have to do a little algebra to simplify. 151 00:09:12,580 --> 00:09:24,060 And what we want to do is simplify to sum of terms 152 00:09:24,060 --> 00:09:31,000 according to delta v selection rule. 153 00:09:35,790 --> 00:09:38,460 So there is some algebra that we do, 154 00:09:38,460 --> 00:09:44,780 when we have, say, a dagger, a dagger, a, a, a dagger. 155 00:09:44,780 --> 00:09:49,010 But we know that three a daggers and two a's means 156 00:09:49,010 --> 00:09:50,330 delta v of plus 1. 157 00:09:54,780 --> 00:09:59,110 And that came from x to the 5th power. 158 00:09:59,110 --> 00:10:02,290 But you get a lot of terms from x to the 5th power. 159 00:10:02,290 --> 00:10:04,130 And you have to simplify them. 160 00:10:04,130 --> 00:10:08,260 And in order to do that, you use this commutation rule-- 161 00:10:08,260 --> 00:10:13,857 a, a dagger is equal to 1. 162 00:10:13,857 --> 00:10:14,940 And that rearranges terms. 163 00:10:14,940 --> 00:10:16,830 So all of the work you do when you're 164 00:10:16,830 --> 00:10:20,820 faced with a problem involving integrals 165 00:10:20,820 --> 00:10:24,990 of integer powers of x and p for a harmonic oscillator 166 00:10:24,990 --> 00:10:29,700 is playing around with moving the a's and a daggers 167 00:10:29,700 --> 00:10:32,220 around, so that you have all the terms that 168 00:10:32,220 --> 00:10:37,680 have the same selection rule compressed into one term. 169 00:10:37,680 --> 00:10:38,650 That's the work. 170 00:10:38,650 --> 00:10:39,990 It's not much. 171 00:10:39,990 --> 00:10:44,430 And once you've done it for x squared, x cubed and x 4th, 172 00:10:44,430 --> 00:10:47,040 you've done it as much as you'll ever need to do. 173 00:10:47,040 --> 00:10:48,220 And that's it. 174 00:10:48,220 --> 00:10:49,370 That's the end. 175 00:10:49,370 --> 00:10:49,870 OK. 176 00:10:54,390 --> 00:11:00,070 Now here's an example of a problem 177 00:11:00,070 --> 00:11:01,850 that's a little bit tricky. 178 00:11:01,850 --> 00:11:06,350 And it's sort of right at the borderline of what 179 00:11:06,350 --> 00:11:08,920 I might use on the exam. 180 00:11:08,920 --> 00:11:15,840 So we have this, we have a dagger to the m power. 181 00:11:15,840 --> 00:11:18,430 A to the n power. 182 00:11:18,430 --> 00:11:20,330 Psi. 183 00:11:20,330 --> 00:11:20,910 OK. 184 00:11:20,910 --> 00:11:22,870 Now, here. 185 00:11:22,870 --> 00:11:26,290 What v is going to give a non-zero integral? 186 00:11:26,290 --> 00:11:28,690 We have a dagger to the m. 187 00:11:28,690 --> 00:11:31,120 And we have a to the n. 188 00:11:31,120 --> 00:11:41,570 And so that's going to be v minus n plus m, right? 189 00:11:41,570 --> 00:11:47,430 Because we lose n quanta, because of this. 190 00:11:47,430 --> 00:11:49,440 And we gain m quanta because of that. 191 00:11:52,180 --> 00:11:54,220 And now, well, that's good. 192 00:11:54,220 --> 00:11:55,810 You've used the selection rule. 193 00:11:55,810 --> 00:11:58,890 Now, how do we write out this interval? 194 00:11:58,890 --> 00:12:01,960 And there is a little bit of art there too. 195 00:12:01,960 --> 00:12:07,240 Because we have a whole bunch of terms. 196 00:12:07,240 --> 00:12:11,360 We have n plus m terms in the square root. 197 00:12:11,360 --> 00:12:15,250 And how do you generate them without getting lost? 198 00:12:18,721 --> 00:12:19,220 Yes? 199 00:12:19,220 --> 00:12:20,886 AUDIENCE: I think you have it backwards. 200 00:12:20,886 --> 00:12:24,512 Shouldn't it be plus n minus n? 201 00:12:24,512 --> 00:12:26,920 It means you're going to lower it n times. 202 00:12:26,920 --> 00:12:27,950 PROFESSOR: Yes. 203 00:12:27,950 --> 00:12:30,410 Yes. 204 00:12:30,410 --> 00:12:32,190 I wonder what I had in my notes. 205 00:12:32,190 --> 00:12:33,290 This is wrong. 206 00:12:39,980 --> 00:12:41,690 OK. 207 00:12:41,690 --> 00:12:49,900 So this has to withstand this and this. 208 00:12:49,900 --> 00:12:51,730 And so, yes. 209 00:12:51,730 --> 00:12:52,230 OK. 210 00:12:52,230 --> 00:12:54,810 However you remember it, you've got to do it right. 211 00:12:54,810 --> 00:13:00,430 And now we have the actual matrix element. 212 00:13:00,430 --> 00:13:07,950 And so the first term is going to be what does a n do to that? 213 00:13:07,950 --> 00:13:10,080 So you start on the right. 214 00:13:10,080 --> 00:13:13,460 And you start building up this way. 215 00:13:13,460 --> 00:13:19,830 And so the first term is going to be, what does a do to this? 216 00:13:19,830 --> 00:13:24,950 Well, it's going to leave it alone. 217 00:13:24,950 --> 00:13:27,440 But it's going to lower v. 218 00:13:27,440 --> 00:13:32,060 So we have v plus n minus m. 219 00:13:32,060 --> 00:13:37,790 And then we have v plus n minus m minus 1, 220 00:13:37,790 --> 00:13:39,995 et cetera, until we have n terms. 221 00:13:45,740 --> 00:13:49,940 And then we start going back up, because we're now 222 00:13:49,940 --> 00:13:53,160 dealing with this. 223 00:13:53,160 --> 00:13:56,410 And so I'm not going to write the rest of this. 224 00:13:56,410 --> 00:14:00,760 Maybe this is going to be a problem I start the exam with. 225 00:14:04,180 --> 00:14:05,500 So you don't want to get lost. 226 00:14:05,500 --> 00:14:08,080 And the main thing is, you have these operators. 227 00:14:08,080 --> 00:14:12,910 And you start operating on the right, and one step at a time. 228 00:14:12,910 --> 00:14:16,060 And this is a little tricky because you're 229 00:14:16,060 --> 00:14:18,130 changing the quantum number, and you're 230 00:14:18,130 --> 00:14:20,100 changing the wave function. 231 00:14:20,100 --> 00:14:22,420 And you have to keep both in mind, 232 00:14:22,420 --> 00:14:25,610 but you're only writing down this. 233 00:14:25,610 --> 00:14:26,110 OK? 234 00:14:35,330 --> 00:14:38,330 I want to save enough time so that we can actually 235 00:14:38,330 --> 00:14:41,510 do the time dependent Schrodinger equation. 236 00:14:41,510 --> 00:14:43,470 The time dependent Schrodinger equation. 237 00:14:43,470 --> 00:14:45,340 H psi. 238 00:14:55,250 --> 00:14:57,530 It still looks pretty simple. 239 00:14:57,530 --> 00:15:02,130 Instead of e psi here, we have this thing. 240 00:15:02,130 --> 00:15:04,500 This is the time dependent Schrodinger equation. 241 00:15:04,500 --> 00:15:05,460 This is it. 242 00:15:05,460 --> 00:15:07,170 This is quantum mechanics. 243 00:15:07,170 --> 00:15:09,900 Everything that comes from quantum mechanics 244 00:15:09,900 --> 00:15:11,850 starts with this. 245 00:15:11,850 --> 00:15:15,270 When we don't care about time, we 246 00:15:15,270 --> 00:15:17,760 can use the time independent Schrodinger equation. 247 00:15:17,760 --> 00:15:19,950 But when we do care about time, we 248 00:15:19,950 --> 00:15:22,480 have to be a little bit careful. 249 00:15:22,480 --> 00:15:25,030 So this is the real Schrodinger equation. 250 00:15:25,030 --> 00:15:27,250 And notice that I'm using a capital 251 00:15:27,250 --> 00:15:33,900 psi, rather than a lower case, or less decorated psi. 252 00:15:33,900 --> 00:15:37,890 And so this is usually used to indicate the time dependent 253 00:15:37,890 --> 00:15:38,910 Schrodinger equation. 254 00:15:38,910 --> 00:15:40,680 It's time dependent wave function. 255 00:15:40,680 --> 00:15:46,200 This is used to indicate the time independent equation. 256 00:15:46,200 --> 00:15:49,520 Now, if the Hamiltonian-- 257 00:15:49,520 --> 00:15:51,180 and this is wonderful-- 258 00:15:51,180 --> 00:15:54,940 if the Hamiltonian is independent of time, 259 00:15:54,940 --> 00:16:03,010 then if we know the solutions psi n en. 260 00:16:03,010 --> 00:16:05,950 If we know all of these solutions, 261 00:16:05,950 --> 00:16:07,940 then there's nothing new. 262 00:16:07,940 --> 00:16:10,900 We just are repackaging the stuff 263 00:16:10,900 --> 00:16:13,900 that we know from the time independent Schrodinger 264 00:16:13,900 --> 00:16:15,430 equation. 265 00:16:15,430 --> 00:16:17,840 So the first thing I want to do is to show you 266 00:16:17,840 --> 00:16:24,180 that if the Hamiltonian is independent, 267 00:16:24,180 --> 00:16:30,090 we can always write a solution to the time 268 00:16:30,090 --> 00:16:36,180 dependent Schrodinger equation-- e to the minus i e n 269 00:16:36,180 --> 00:16:42,690 t over h bar psi n x. 270 00:16:45,330 --> 00:16:52,110 So this, for a time independent Hamiltonian, 271 00:16:52,110 --> 00:16:55,661 is always the solution of the time dependent Schrodinger 272 00:16:55,661 --> 00:16:56,160 equation. 273 00:17:02,010 --> 00:17:04,319 So we're just using this stuff that we know, 274 00:17:04,319 --> 00:17:06,210 or at least we barely know, because we just 275 00:17:06,210 --> 00:17:08,450 started playing the game. 276 00:17:08,450 --> 00:17:12,089 But we can manipulate to see all sorts of useful stuff. 277 00:17:12,089 --> 00:17:12,589 OK. 278 00:17:12,589 --> 00:17:16,319 So let's show if this form satisfies the Schrodinger 279 00:17:16,319 --> 00:17:17,359 equation. 280 00:17:17,359 --> 00:17:25,339 So we have ih bar partial PSI with respect to t. 281 00:17:25,339 --> 00:17:28,339 So we get an ih bar. 282 00:17:28,339 --> 00:17:32,660 And then we take the partial with respect to t. 283 00:17:32,660 --> 00:17:34,370 This is independent of time. 284 00:17:34,370 --> 00:17:36,290 This has time [INAUDIBLE] And so we 285 00:17:36,290 --> 00:17:42,830 get a minus i e n over h bar. 286 00:17:42,830 --> 00:17:50,060 And then we get e to the minus i e n t over h bar psi n of x. 287 00:17:56,090 --> 00:17:56,900 Well. 288 00:17:56,900 --> 00:17:59,040 So, let's put this together. 289 00:17:59,040 --> 00:18:01,520 We have an i times i times minus 1. 290 00:18:01,520 --> 00:18:02,840 So that's plus 1. 291 00:18:02,840 --> 00:18:04,540 We have an h bar in the numerator and h 292 00:18:04,540 --> 00:18:06,180 bar in the denominator. 293 00:18:06,180 --> 00:18:07,160 That's 1. 294 00:18:07,160 --> 00:18:14,690 And so what we end up getting is e n e to the minus i e n 295 00:18:14,690 --> 00:18:17,090 t over h bar psi n. 296 00:18:20,054 --> 00:18:24,980 Well, this is psi. 297 00:18:28,320 --> 00:18:37,020 This function here is the solution to the time 298 00:18:37,020 --> 00:18:38,850 dependent Schrodinger equation. 299 00:18:38,850 --> 00:18:40,080 How do we know that? 300 00:18:40,080 --> 00:18:44,700 Well, we have this factor, h psi. 301 00:18:44,700 --> 00:18:50,200 Well, h doesn't operate on either the i e n t. 302 00:18:50,200 --> 00:18:57,280 So what we have is that we get E n e to the i omega t. 303 00:19:01,118 --> 00:19:01,618 Sorry. 304 00:19:01,618 --> 00:19:03,546 I'm jumping ahead. 305 00:19:03,546 --> 00:19:07,386 i e n t over h bar psi. 306 00:19:16,810 --> 00:19:18,190 All right. 307 00:19:18,190 --> 00:19:23,770 So, if we apply the Hamiltonian to this function, 308 00:19:23,770 --> 00:19:26,500 we get just e n times the function. 309 00:19:31,530 --> 00:19:35,240 And that's what we got when we did i h bar times a partial 310 00:19:35,240 --> 00:19:37,040 with respect to t. 311 00:19:37,040 --> 00:19:41,900 So what that shows is that this form always 312 00:19:41,900 --> 00:19:46,220 satisfies the time dependent Schrodinger equation, provided 313 00:19:46,220 --> 00:19:49,630 that the Hamiltonian is independent of time. 314 00:19:49,630 --> 00:19:53,400 Now, that's a large range of problems, things 315 00:19:53,400 --> 00:19:55,630 that we need to understand. 316 00:19:55,630 --> 00:19:58,920 But it's not the whole potato, because the Hamiltonian 317 00:19:58,920 --> 00:20:01,560 is often dependent on time. 318 00:20:01,560 --> 00:20:06,570 But it enables us to build up insight, and then 319 00:20:06,570 --> 00:20:10,890 treat the time dependence as a perturbation. 320 00:20:10,890 --> 00:20:13,860 And we're going to do perturbation theory in the time 321 00:20:13,860 --> 00:20:15,994 independent world. 322 00:20:15,994 --> 00:20:17,910 And then we're going to do perturbation theory 323 00:20:17,910 --> 00:20:21,470 a little bit in the time dependent world. 324 00:20:21,470 --> 00:20:21,970 OK. 325 00:20:21,970 --> 00:20:26,440 So what we always do here is we solve a familiar problem, 326 00:20:26,440 --> 00:20:29,050 and then we say, OK, well, there's something more 327 00:20:29,050 --> 00:20:31,400 to this familiar problem. 328 00:20:31,400 --> 00:20:34,410 And so we treat that as something extra. 329 00:20:34,410 --> 00:20:36,250 And we work out the formalism for dealing 330 00:20:36,250 --> 00:20:38,210 with that extra thing. 331 00:20:38,210 --> 00:20:39,700 But before we do the extra thing, 332 00:20:39,700 --> 00:20:42,460 we have to really kill the problem that 333 00:20:42,460 --> 00:20:45,950 is within our grasp. 334 00:20:45,950 --> 00:20:46,450 OK. 335 00:20:49,470 --> 00:20:54,630 So now, our job is to just explore 336 00:20:54,630 --> 00:20:55,920 what we've really got here. 337 00:20:58,840 --> 00:21:04,750 So the first problem is motion. 338 00:21:08,140 --> 00:21:16,975 So we have psi star x and t psi x and t. 339 00:21:20,640 --> 00:21:22,350 So we have this thing, which we're not 340 00:21:22,350 --> 00:21:23,640 going to integrate yet. 341 00:21:29,790 --> 00:21:32,220 Well, when is this thing going to move? 342 00:21:35,000 --> 00:21:39,010 Well, the only way this probability density 343 00:21:39,010 --> 00:21:42,190 is going to evolve in time is going 344 00:21:42,190 --> 00:21:46,650 to be if we have a wave function, psi, 345 00:21:46,650 --> 00:21:54,400 which is of x and t is equal to c1 psi 1, e to the minus i e 1, 346 00:21:54,400 --> 00:22:00,720 e over h bar, plus c2, psi 2, e to the minus i e 347 00:22:00,720 --> 00:22:10,290 2, t over h bar, where e1 is not equal to e2. 348 00:22:10,290 --> 00:22:12,780 So this is the first, most elementary step. 349 00:22:12,780 --> 00:22:18,040 And remember, we have this notation e to the i something. 350 00:22:18,040 --> 00:22:20,140 And e to the minus i something. 351 00:22:20,140 --> 00:22:24,200 And when we take a plus 1 and a minus and put them together, 352 00:22:24,200 --> 00:22:26,040 we get 1. 353 00:22:26,040 --> 00:22:28,820 So this notation, this exponential notation, 354 00:22:28,820 --> 00:22:30,450 is really valuable. 355 00:22:30,450 --> 00:22:30,950 OK. 356 00:22:30,950 --> 00:22:34,910 So now let's just look at this quantity, psi star psi. 357 00:22:39,050 --> 00:22:39,550 OK. 358 00:22:39,550 --> 00:22:40,870 Psi star psi. 359 00:22:44,980 --> 00:22:54,040 Well, it's going to be c1 squared, psi 1 squared-- 360 00:22:54,040 --> 00:23:01,430 square modulus-- and we get c2 square modulus, 361 00:23:01,430 --> 00:23:05,360 psi 2 square modulus. 362 00:23:05,360 --> 00:23:06,120 Are we done? 363 00:23:06,120 --> 00:23:07,280 No. 364 00:23:07,280 --> 00:23:14,360 So, what we did is, I put in c1, psi 1 plus c2, psi 2. 365 00:23:14,360 --> 00:23:17,150 And I looked at the easy terms, the terms 366 00:23:17,150 --> 00:23:20,980 where the exponential factor goes away. 367 00:23:20,980 --> 00:23:22,690 And then there's two cross terms. 368 00:23:22,690 --> 00:23:25,730 Those two cross terms are c1 star-- 369 00:23:25,730 --> 00:23:49,080 whoops-- c2 e to the minus i e 2 minus e1 t over h bar 370 00:23:49,080 --> 00:23:54,370 psi 1 star, psi 2. 371 00:23:54,370 --> 00:24:04,780 And we have c1, c2 star e to the plus i e2 minus e1 372 00:24:04,780 --> 00:24:10,930 t over h bar, psi 1 star. 373 00:24:10,930 --> 00:24:14,370 psi 1, psi 2 star. 374 00:24:14,370 --> 00:24:17,371 Now, this is just the automatic writing. 375 00:24:17,371 --> 00:24:17,870 OK. 376 00:24:17,870 --> 00:24:23,760 So we have two terms that are time independent. 377 00:24:23,760 --> 00:24:26,570 So, this is no big surprise. 378 00:24:26,570 --> 00:24:28,520 But then we have this stuff here. 379 00:24:28,520 --> 00:24:38,970 And if we say e2 minus e1 over h bar is omega 2, 1, 380 00:24:38,970 --> 00:24:42,830 everything becomes very transparent, 381 00:24:42,830 --> 00:24:44,630 because now we have something that 382 00:24:44,630 --> 00:24:52,070 looks like it looks like it's trying to be a cosine omega t. 383 00:24:52,070 --> 00:24:55,050 We have to be a little bit careful. 384 00:24:55,050 --> 00:24:57,440 These are the two time dependent terms. 385 00:24:57,440 --> 00:25:01,180 And they are the complex conjugate of each other. 386 00:25:01,180 --> 00:25:12,690 And so we know that if we have two complex numbers, 387 00:25:12,690 --> 00:25:21,840 c plus c star, we're going to get twice the real part of c. 388 00:25:27,140 --> 00:25:31,460 So this enables us to take these two terms and combine them. 389 00:25:31,460 --> 00:25:35,900 And we know it had better be real, 390 00:25:35,900 --> 00:25:38,360 because we're talking about a probability here. 391 00:25:38,360 --> 00:25:42,010 This probability has got to be real. 392 00:25:42,010 --> 00:25:44,410 And it's got to be positive. 393 00:25:44,410 --> 00:25:48,825 It's got to be real and positive everywhere and forever. 394 00:25:51,580 --> 00:25:55,410 Because there's no such thing as a negative probability. 395 00:25:55,410 --> 00:25:57,650 There's no such thing as a negative probability 396 00:25:57,650 --> 00:26:00,170 in a little region of space, and we say, well, 397 00:26:00,170 --> 00:26:04,170 we integrate over all space, and so that goes away. 398 00:26:04,170 --> 00:26:12,330 This psi star psi is going to be real everywhere for all time. 399 00:26:12,330 --> 00:26:14,060 And so that's a good thing, because we 400 00:26:14,060 --> 00:26:21,450 have a sum of a plus its complex conjugate. 401 00:26:21,450 --> 00:26:23,270 And so this is real. 402 00:26:23,270 --> 00:26:32,900 And we can simplify everything, and we can write it simply. 403 00:26:32,900 --> 00:26:35,400 But suppose we choose a particular case-- 404 00:26:35,400 --> 00:26:42,980 c1 star is equal to c1, which is equal to 1 405 00:26:42,980 --> 00:26:45,560 over square root of 2. 406 00:26:45,560 --> 00:26:52,910 And we can say psi 1 and psi 2 are real. 407 00:26:52,910 --> 00:26:57,330 When we do that, then this complicated-looking thing, psi 408 00:26:57,330 --> 00:27:03,760 star psi, becomes 1/2 psi 1 squared, 409 00:27:03,760 --> 00:27:15,430 plus 1/2 psi 2 squared, plus cosine omega 1 2 t psi 1 psi 2. 410 00:27:20,950 --> 00:27:22,760 OK. 411 00:27:22,760 --> 00:27:25,490 Well, these two guys aren't moving. 412 00:27:25,490 --> 00:27:27,540 And they're real. 413 00:27:27,540 --> 00:27:28,590 And positive. 414 00:27:28,590 --> 00:27:29,240 Yeah. 415 00:27:29,240 --> 00:27:32,160 AUDIENCE: Wait, is c2 also 1 over square root of 2? 416 00:27:35,932 --> 00:27:37,640 PROFESSOR: I had 1 over square root of 2, 417 00:27:37,640 --> 00:27:38,490 one over square root of 2. 418 00:27:38,490 --> 00:27:39,060 That's 1/2. 419 00:27:41,880 --> 00:27:46,560 But then when you add the two terms, 420 00:27:46,560 --> 00:27:48,600 you get twice the real part. 421 00:27:48,600 --> 00:27:50,640 So we get a 1/2 times 2. 422 00:27:50,640 --> 00:27:54,000 And so this is not a mistake. 423 00:27:54,000 --> 00:27:56,730 It comes out this way, OK? 424 00:27:56,730 --> 00:27:58,800 AUDIENCE: I think you meant c2. 425 00:27:58,800 --> 00:28:05,340 You're only finding c1 star and c1 to be 2 over square root-- 426 00:28:05,340 --> 00:28:07,580 1 over square root of 2. 427 00:28:07,580 --> 00:28:09,467 You didn't say anything about c2. 428 00:28:09,467 --> 00:28:10,050 PROFESSOR: Oh. 429 00:28:10,050 --> 00:28:10,860 OK. 430 00:28:10,860 --> 00:28:12,010 I want c1 and c2. 431 00:28:16,710 --> 00:28:18,640 That's what I wanted. 432 00:28:18,640 --> 00:28:19,140 OK. 433 00:28:24,450 --> 00:28:25,560 Thank you. 434 00:28:25,560 --> 00:28:27,360 That shows you're listening. 435 00:28:27,360 --> 00:28:30,570 And it shows that I'm sufficiently here 436 00:28:30,570 --> 00:28:32,460 to understand your questions, which 437 00:28:32,460 --> 00:28:34,350 is another wonderful thing. 438 00:28:34,350 --> 00:28:36,960 So this is now, we have something 439 00:28:36,960 --> 00:28:40,460 that's positive everywhere. 440 00:28:40,460 --> 00:28:41,860 It's time independent. 441 00:28:41,860 --> 00:28:45,800 And we have something that's oscillating. 442 00:28:45,800 --> 00:28:49,080 And so this term can be negative. 443 00:28:49,080 --> 00:28:51,150 But you can show-- 444 00:28:51,150 --> 00:28:52,750 I don't choose to do that. 445 00:28:52,750 --> 00:28:55,500 You can show that this term is never larger 446 00:28:55,500 --> 00:28:57,480 than psi 1 squared plus psi 2 squared. 447 00:29:00,770 --> 00:29:05,720 And so even though this term can be negative at some points, 448 00:29:05,720 --> 00:29:10,970 it never is a negative enough to make the evolving probability 449 00:29:10,970 --> 00:29:12,211 go negative. 450 00:29:15,880 --> 00:29:18,780 Now, you may want to play with that just to convince yourself. 451 00:29:18,780 --> 00:29:19,780 And it's an easy proof. 452 00:29:19,780 --> 00:29:22,600 And I'm just not going to do it. 453 00:29:22,600 --> 00:29:25,080 OK. 454 00:29:25,080 --> 00:29:29,400 So we have something that says, just 455 00:29:29,400 --> 00:29:35,270 like for the wave equation, what does it take to get motion? 456 00:29:35,270 --> 00:29:37,040 And to get motion you had to have 457 00:29:37,040 --> 00:29:41,810 a superposition of two waves of different energy 458 00:29:41,810 --> 00:29:43,070 or different wave vector. 459 00:29:45,630 --> 00:29:51,180 And so here we have, if e1 is not equal to e2, 460 00:29:51,180 --> 00:29:53,695 we have a non-zero omega 1, 2. 461 00:29:53,695 --> 00:29:56,340 It doesn't matter whether it's omega 1, 2, or omega 2, 1, 462 00:29:56,340 --> 00:29:59,100 because it's cosine. 463 00:29:59,100 --> 00:30:02,700 And so that's motion. 464 00:30:02,700 --> 00:30:07,890 So we get a standing wave sort of situation. 465 00:30:07,890 --> 00:30:10,950 And then we get this motion. 466 00:30:10,950 --> 00:30:14,430 OK, now, the fun begins. 467 00:30:14,430 --> 00:30:23,614 Suppose we want to calculate the expectation value of x and p. 468 00:30:30,290 --> 00:30:30,790 OK. 469 00:30:30,790 --> 00:30:35,160 And let's just take it as a 1D problem. 470 00:30:35,160 --> 00:30:37,300 And so x of t. 471 00:30:40,090 --> 00:30:41,640 No, there was no question. 472 00:30:41,640 --> 00:30:42,870 All right. 473 00:30:42,870 --> 00:30:43,410 We have-- 474 00:30:59,122 --> 00:30:59,940 OK. 475 00:30:59,940 --> 00:31:02,100 And again, we take this thing apart. 476 00:31:02,100 --> 00:31:05,460 And we say, all right, suppose we have the same superposition 477 00:31:05,460 --> 00:31:09,160 of psi is equal to c1. 478 00:31:09,160 --> 00:31:10,330 psi 1. 479 00:31:21,640 --> 00:31:23,050 OK. 480 00:31:23,050 --> 00:31:30,650 Actually, these should be the time independent. 481 00:31:30,650 --> 00:31:35,120 So what we get is, when we do this integral, we get c1 482 00:31:35,120 --> 00:31:47,940 squared integral psi star x, psi 1 dx. 483 00:31:47,940 --> 00:31:59,890 And we get c2 squared integral psi 2 star x, psi 2 dx. 484 00:31:59,890 --> 00:32:03,260 And then we get cross terms. c1 star, c2. 485 00:32:05,980 --> 00:32:18,970 e to the minus i omega 2, 1 t times the integral psi 1 star 486 00:32:18,970 --> 00:32:23,170 x psi 2 dx. 487 00:32:23,170 --> 00:32:31,330 And we have c1, c2 star, e to the plus i omega 2 1 488 00:32:31,330 --> 00:32:38,090 t integral psi 2 star x psi 1 dx. 489 00:32:40,741 --> 00:32:43,170 A lot of stuff here. 490 00:32:43,170 --> 00:32:47,810 Now, we're talking about the harmonic oscillator. 491 00:32:47,810 --> 00:32:49,385 This integral is 0. 492 00:32:52,360 --> 00:32:55,340 Because x is a plus a dagger. 493 00:32:55,340 --> 00:32:58,750 The selection rule is delta v of plus and minus 1. 494 00:32:58,750 --> 00:33:01,190 This one is 0. 495 00:33:01,190 --> 00:33:05,790 For the particle in a box, one can also 496 00:33:05,790 --> 00:33:08,610 ask, what about this integral? 497 00:33:08,610 --> 00:33:11,880 And for the particle in a box, it's a little bit more 498 00:33:11,880 --> 00:33:12,510 complicated. 499 00:33:12,510 --> 00:33:15,510 Because we've chosen a mathematically simple way 500 00:33:15,510 --> 00:33:19,110 to solve the particle in a box, with the box having a zero 501 00:33:19,110 --> 00:33:21,500 left edge. 502 00:33:21,500 --> 00:33:25,310 If we make the box symmetric, then we can make judgments 503 00:33:25,310 --> 00:33:26,930 and say, oh, yeah. 504 00:33:26,930 --> 00:33:30,930 This integral is also 0 for the particle in a box. 505 00:33:36,010 --> 00:33:38,490 And that's a little bit more complicated, the argument, 506 00:33:38,490 --> 00:33:40,200 than what I just did. 507 00:33:40,200 --> 00:33:45,070 So these two terms are 0. 508 00:33:45,070 --> 00:33:51,100 And now we have motion of the expectation value, which is 509 00:33:51,100 --> 00:33:52,720 described by these two terms. 510 00:33:52,720 --> 00:33:56,180 And again, they're the complex conjugate of each other. 511 00:33:56,180 --> 00:34:13,949 And so what we have is x of t is equal to twice 512 00:34:13,949 --> 00:34:22,900 the real part of c1 star, c2 e to the minus i omega 2, 1 t. 513 00:34:28,500 --> 00:34:32,131 Times x 1, 2. 514 00:34:32,131 --> 00:34:32,630 OK. 515 00:34:32,630 --> 00:34:34,310 This x 1, 2 is an integral. 516 00:34:37,210 --> 00:34:42,969 So x 1, 2 if these are the vibrational quantum numbers, 517 00:34:42,969 --> 00:34:46,310 well, then this is non-zero. 518 00:34:46,310 --> 00:34:52,370 This is just the square root of 2, or square root of 1. 519 00:35:00,051 --> 00:35:00,550 OK. 520 00:35:00,550 --> 00:35:05,005 So we have motion described by this. 521 00:35:07,990 --> 00:35:14,440 And so the only time we get motion 522 00:35:14,440 --> 00:35:20,650 is if v1 is equal to v2 plus or minus 1, 523 00:35:20,650 --> 00:35:22,065 for the harmonic oscillator. 524 00:35:25,320 --> 00:35:29,720 For the particle in a box, there's different rules. 525 00:35:29,720 --> 00:35:32,010 And often, for these simple problems, 526 00:35:32,010 --> 00:35:35,090 you want to go through in your head all of the simple cases. 527 00:35:48,810 --> 00:35:52,630 Now, we already can see that-- 528 00:35:59,950 --> 00:36:02,270 I don't want to talk about the particle in a box. 529 00:36:02,270 --> 00:36:05,320 So now let's just take another step. 530 00:36:05,320 --> 00:36:17,780 And we're going to have Ehrenfest's theorem, which 531 00:36:17,780 --> 00:36:26,800 you can prove, says that m times the derivative of vector p-- 532 00:36:31,790 --> 00:36:35,210 so this is a time dependent expectation value-- 533 00:36:35,210 --> 00:36:37,681 is equal to-- 534 00:36:37,681 --> 00:36:38,180 I'm sorry. 535 00:36:38,180 --> 00:36:39,200 This is not vector p. 536 00:36:39,200 --> 00:36:41,420 This is vector r-- 537 00:36:41,420 --> 00:36:42,080 is equal to-- 538 00:36:48,550 --> 00:36:49,720 So this is the vector p. 539 00:36:49,720 --> 00:36:53,500 So this is the derivative of the coordinate, 540 00:36:53,500 --> 00:36:54,380 with respect to time. 541 00:36:54,380 --> 00:36:55,600 That's velocity. 542 00:36:55,600 --> 00:36:59,080 Velocity times mass is momentum. 543 00:36:59,080 --> 00:37:02,380 And so we have a relationship between the expectation 544 00:37:02,380 --> 00:37:06,070 value of the position and the expectation 545 00:37:06,070 --> 00:37:08,480 value of the momentum. 546 00:37:08,480 --> 00:37:10,520 And that's for Newton's first law. 547 00:37:10,520 --> 00:37:14,170 And then there is another Newton's equation translated 548 00:37:14,170 --> 00:37:16,580 into quantum mechanics. 549 00:37:16,580 --> 00:37:25,270 So we have the expectation value of the momentum, dt, 550 00:37:25,270 --> 00:37:30,520 is equal to minus the expectation 551 00:37:30,520 --> 00:37:33,250 value of the potential. 552 00:37:37,310 --> 00:37:43,540 While this is acceleration times mass, and this is force-- 553 00:37:43,540 --> 00:37:46,020 minus the gradient of a potential is the force-- 554 00:37:46,020 --> 00:37:47,860 these are Newton's two equations. 555 00:37:47,860 --> 00:37:58,280 And what they're saying is, if we know these things, 556 00:37:58,280 --> 00:38:01,520 we know something about the center of the wave packet, 557 00:38:01,520 --> 00:38:03,570 and how the center of the wave packet moves. 558 00:38:03,570 --> 00:38:06,540 Now, the wave packet might be localized at one time. 559 00:38:06,540 --> 00:38:09,210 It might be mushed out at another time. 560 00:38:09,210 --> 00:38:11,710 But you can always calculate the center of the wave packet. 561 00:38:11,710 --> 00:38:13,501 It's just that there are only certain times 562 00:38:13,501 --> 00:38:16,650 that it looks like a particle. 563 00:38:16,650 --> 00:38:19,830 But this thing, these quantities, 564 00:38:19,830 --> 00:38:24,380 which you define by an integral, they evolve classically. 565 00:38:24,380 --> 00:38:26,000 So I told you at the beginning, you 566 00:38:26,000 --> 00:38:28,790 had to give up classical mechanics. 567 00:38:28,790 --> 00:38:31,130 It's all coming back. 568 00:38:31,130 --> 00:38:34,320 But it's coming back in a quantum mechanical framework, 569 00:38:34,320 --> 00:38:38,360 because we're talking now about wave functions, which 570 00:38:38,360 --> 00:38:43,350 have amplitudes and phases, and can do terrible things. 571 00:38:43,350 --> 00:38:49,110 But at certain limits, they're going to act like particles. 572 00:38:49,110 --> 00:38:57,650 But if you were to ask a question, well-- 573 00:38:57,650 --> 00:39:00,230 suppose we do this experiment. 574 00:39:00,230 --> 00:39:06,770 And so here we have an electronic ground state 575 00:39:06,770 --> 00:39:07,970 potential surface. 576 00:39:07,970 --> 00:39:10,610 Now, I'm jumping way ahead. 577 00:39:10,610 --> 00:39:16,730 But this is the wave function for that vibrational level. 578 00:39:16,730 --> 00:39:21,780 And you excite the molecule with a time dependent Hamiltonian, 579 00:39:21,780 --> 00:39:25,200 a time dependent radiation field light. 580 00:39:25,200 --> 00:39:29,880 And you vertically transport this wave function 581 00:39:29,880 --> 00:39:32,520 to the upper state, until you get something 582 00:39:32,520 --> 00:39:35,690 which is not an eigenstate. 583 00:39:35,690 --> 00:39:37,470 It's a pluck. 584 00:39:37,470 --> 00:39:41,560 This pluck is a superposition of eigenstates. 585 00:39:41,560 --> 00:39:43,360 And we can ask, how does this evolve? 586 00:39:43,360 --> 00:39:45,130 And what it's going to do is, it's 587 00:39:45,130 --> 00:39:47,910 going to start out localized. 588 00:39:47,910 --> 00:39:51,280 And at some point, it'll do terrible things. 589 00:39:51,280 --> 00:39:53,140 And then at some other time it'll 590 00:39:53,140 --> 00:39:55,380 be localized again at the other turning point. 591 00:39:55,380 --> 00:39:57,780 And it will come back and forth. 592 00:39:57,780 --> 00:40:00,810 And now, if it's not a harmonic oscillator, 593 00:40:00,810 --> 00:40:03,780 it won't quite relocalize. 594 00:40:03,780 --> 00:40:05,810 It'll mush out a little bit, and it'll come back 595 00:40:05,810 --> 00:40:07,660 and it'll mush out more. 596 00:40:07,660 --> 00:40:11,900 And so again, we can use the evolution of the wave packet 597 00:40:11,900 --> 00:40:15,530 to sample the shape of the potential. 598 00:40:15,530 --> 00:40:17,940 We can measure the anharmonicity. 599 00:40:17,940 --> 00:40:20,780 And so let's now talk about that. 600 00:40:24,970 --> 00:40:27,400 What are other quantities that we 601 00:40:27,400 --> 00:40:34,039 can calculate from the wave function of the time 602 00:40:34,039 --> 00:40:35,330 dependent Schrodinger equation? 603 00:40:35,330 --> 00:40:38,960 So let's talk about the survival probability. 604 00:40:38,960 --> 00:40:41,500 So this is a capital P. Survival probability. 605 00:40:41,500 --> 00:40:45,790 It's going to be the wave function. 606 00:40:45,790 --> 00:40:50,440 The time dependent wave function is created at t equals 0. 607 00:40:50,440 --> 00:40:51,970 It has some shape. 608 00:40:51,970 --> 00:40:55,990 Now, we always like to have a simple shape at t equals 0. 609 00:40:55,990 --> 00:41:00,670 And we'd like to know how fast that thing moves away 610 00:41:00,670 --> 00:41:04,210 from its birthplace. 611 00:41:04,210 --> 00:41:10,900 So we have this survival probability. 612 00:41:10,900 --> 00:41:12,280 It's a probability. 613 00:41:12,280 --> 00:41:25,640 So we're going to have integral psi star xt psi xt dx. 614 00:41:25,640 --> 00:41:28,730 And this integral is going to look like that. 615 00:41:32,490 --> 00:41:40,610 Now, whoops. 616 00:41:40,610 --> 00:41:42,800 I knew I was going to screw up. 617 00:41:42,800 --> 00:41:46,370 If I put a t here, then it would just 618 00:41:46,370 --> 00:41:48,320 be the normalization interval. 619 00:41:48,320 --> 00:41:51,250 And we already know what that is. 620 00:41:51,250 --> 00:41:52,690 But this is the birthplace. 621 00:41:52,690 --> 00:41:55,460 This is what was created at t equals 0. 622 00:41:55,460 --> 00:41:58,300 And this is time evolving thing. 623 00:41:58,300 --> 00:42:01,150 And so we can calculate how that behaves. 624 00:42:01,150 --> 00:42:04,790 And I'm just going to write the solution. 625 00:42:09,770 --> 00:42:19,150 So the result is, if we have the same kind of two state c1 psi 626 00:42:19,150 --> 00:42:27,530 1, e to the minus i e1 t for h bar 627 00:42:27,530 --> 00:42:35,140 plus c2 psi 2 e to the minus i e2 e over h bar, 628 00:42:35,140 --> 00:42:41,330 well then, what we get is c1 to the 4th power 629 00:42:41,330 --> 00:42:55,380 plus c2 to the 4th power plus c1 squared, c2 squared, times 630 00:42:55,380 --> 00:43:06,210 e to the i omega 2, 1 t plus e to the minus i omega 2, 1 t. 631 00:43:10,390 --> 00:43:14,090 Now we're integrating. 632 00:43:14,090 --> 00:43:18,520 When we integrate, the wave functions go away. 633 00:43:18,520 --> 00:43:23,010 The wave functions become either 1 or 0. 634 00:43:23,010 --> 00:43:24,750 And so we're integrating. 635 00:43:24,750 --> 00:43:27,030 We're making the wave functions go away. 636 00:43:27,030 --> 00:43:32,490 And we have some amplitudes of the wave functions. 637 00:43:32,490 --> 00:43:36,210 And we have a time independent part and a time dependent part. 638 00:43:36,210 --> 00:43:41,472 And this is 2 cosine omega 2, 1 t. 639 00:43:44,070 --> 00:43:49,530 So what we see is this survival probability, the wave function, 640 00:43:49,530 --> 00:43:51,870 starts out at some place. 641 00:43:51,870 --> 00:43:53,560 And it goes away. 642 00:43:53,560 --> 00:43:54,700 And it comes back. 643 00:43:54,700 --> 00:43:55,800 And it goes away. 644 00:43:55,800 --> 00:43:59,060 And it comes back. 645 00:43:59,060 --> 00:43:59,930 And it does that. 646 00:43:59,930 --> 00:44:04,670 It completely rephases, because there's only two terms. 647 00:44:04,670 --> 00:44:07,070 But if there were three terms that are not 648 00:44:07,070 --> 00:44:09,400 satisfying a certain requirement, 649 00:44:09,400 --> 00:44:11,870 then when it comes back, it can't completely 650 00:44:11,870 --> 00:44:12,960 reconstruct itself. 651 00:44:17,080 --> 00:44:20,560 And this is the basis for doing experiments. 652 00:44:20,560 --> 00:44:26,770 One can observe the periodic rephasings 653 00:44:26,770 --> 00:44:29,500 of some initial pluck. 654 00:44:29,500 --> 00:44:31,840 And you can look at the decay of them, 655 00:44:31,840 --> 00:44:33,850 and that gives you something about the shape 656 00:44:33,850 --> 00:44:36,650 of the potential, the anharmonicity. 657 00:44:36,650 --> 00:44:40,490 And you can do all sorts of fantastic things. 658 00:44:40,490 --> 00:44:43,760 You can create a wave packet, and you 659 00:44:43,760 --> 00:44:47,250 can wait until it reaches the other turning point. 660 00:44:47,250 --> 00:44:48,920 And at the other turning point, it's 661 00:44:48,920 --> 00:44:50,495 possible that you could excite it 662 00:44:50,495 --> 00:44:53,900 to a different higher excited state. 663 00:44:53,900 --> 00:44:55,770 Ahmed Zewail got the Nobel Prize for that. 664 00:44:59,550 --> 00:45:06,690 So we're right at the frontier of what you can do, 665 00:45:06,690 --> 00:45:08,430 and what you can understand using 666 00:45:08,430 --> 00:45:11,810 this very simple problem of a time independent Hamiltonian 667 00:45:11,810 --> 00:45:17,400 and a 2 or a 3 term superposition. 668 00:45:17,400 --> 00:45:17,900 OK. 669 00:45:27,850 --> 00:45:28,510 Recurrence. 670 00:45:35,910 --> 00:45:38,750 This is a special property. 671 00:45:38,750 --> 00:45:50,960 When all of the wave functions, or all of the difference-- 672 00:45:50,960 --> 00:45:54,410 all of the energy levels, or differences in energy levels 673 00:45:54,410 --> 00:46:06,140 are integer multiples of a common factor, well then 674 00:46:06,140 --> 00:46:09,830 any coherent superposition state you make 675 00:46:09,830 --> 00:46:13,940 will rephase at a special time. 676 00:46:13,940 --> 00:46:19,440 And so what we can do is say, OK, for a particle in a box, 677 00:46:19,440 --> 00:46:26,360 the energy levels are e1 times n squared. 678 00:46:26,360 --> 00:46:29,450 For our harmonic oscillator, the energy level difference 679 00:46:29,450 --> 00:46:39,360 is ev plus n minus ev our n h bar omega. 680 00:46:39,360 --> 00:46:41,970 For a rigid rotor, which we haven't seen yet, 681 00:46:41,970 --> 00:46:49,520 the energy levels are a function of this quantum number j hcb. 682 00:46:49,520 --> 00:46:54,410 This is the rotational constant-- times j plus 1. 683 00:46:56,940 --> 00:47:01,970 So all of the energy levels are related. 684 00:47:01,970 --> 00:47:03,590 I'm jumping ahead. 685 00:47:03,590 --> 00:47:04,550 Sorry. 686 00:47:04,550 --> 00:47:12,380 So the energy levels are j times j plus 1. 687 00:47:12,380 --> 00:47:18,980 And the differences, ej plus 1 minus ej, 688 00:47:18,980 --> 00:47:27,620 are given by 2 hcb times j plus 1. 689 00:47:27,620 --> 00:47:31,880 So for these three problems, we have this perfect situation 690 00:47:31,880 --> 00:47:34,820 where one can have these oscillating 691 00:47:34,820 --> 00:47:37,330 terms all have a common factor. 692 00:47:37,330 --> 00:47:42,130 And at certain times, the oscillating terms are all 1. 693 00:47:42,130 --> 00:47:44,510 Or some are 1 and some are minus 1. 694 00:47:44,510 --> 00:47:47,660 And we get a really wonderful simplification. 695 00:47:47,660 --> 00:47:52,190 So at a time which we call, or I call, 696 00:47:52,190 --> 00:47:59,860 the grand recurrence time, where it's 697 00:47:59,860 --> 00:48:09,010 equal to h over e1 for this case of the particle in a box, 698 00:48:09,010 --> 00:48:24,060 or h over h bar omega, or h over 2 hcb, 699 00:48:24,060 --> 00:48:27,540 we get all of the phase factors becoming 1. 700 00:48:33,040 --> 00:48:38,740 And sometimes, something special happens at the grand recurrence 701 00:48:38,740 --> 00:48:41,170 time divided by 2. 702 00:48:41,170 --> 00:48:44,410 And that's a little bit like this. 703 00:48:44,410 --> 00:48:47,900 We have a wave function here. 704 00:48:47,900 --> 00:48:50,010 And at half the recurrence time, it's over here. 705 00:48:53,720 --> 00:48:56,050 And so you want to work your way through the algebra 706 00:48:56,050 --> 00:49:00,590 to convince yourself that that is in fact true. 707 00:49:00,590 --> 00:49:04,280 And in between, if you have enough terms 708 00:49:04,280 --> 00:49:08,380 in your superposition, which is usually the case, 709 00:49:08,380 --> 00:49:09,610 in between you get this. 710 00:49:09,610 --> 00:49:13,080 You get garbage looking. 711 00:49:13,080 --> 00:49:15,330 It's still moving. 712 00:49:15,330 --> 00:49:18,390 It's still satisfying the Ehrenfest theorem, 713 00:49:18,390 --> 00:49:20,010 but it doesn't look like a particle. 714 00:49:20,010 --> 00:49:23,470 It just looks like garbage. 715 00:49:23,470 --> 00:49:26,140 But you get these wonderful things happening. 716 00:49:26,140 --> 00:49:28,480 And now, if they're not perfectly 717 00:49:28,480 --> 00:49:32,350 satisfying this integer rule, then each time you 718 00:49:32,350 --> 00:49:36,130 get to a turning point, the amplitude 719 00:49:36,130 --> 00:49:40,440 has decreased and decreased and decreased. 720 00:49:40,440 --> 00:49:46,830 And at infinite time, it might recur. 721 00:49:46,830 --> 00:49:48,580 But nobody waits around for infinite time, 722 00:49:48,580 --> 00:49:51,970 because other things happen and destroy the coherence that you 723 00:49:51,970 --> 00:49:55,005 built. So this is a glimpse. 724 00:49:59,310 --> 00:50:01,020 Time independent quantum mechanics 725 00:50:01,020 --> 00:50:03,980 is complicated enough. 726 00:50:03,980 --> 00:50:07,610 Well, we can embed what we understand 727 00:50:07,610 --> 00:50:10,730 in the time dependent mechanics. 728 00:50:10,730 --> 00:50:14,560 And there are a lot of beautiful things that we can anticipate. 729 00:50:14,560 --> 00:50:19,210 Now, we can use these beautiful things 730 00:50:19,210 --> 00:50:22,420 to do experiments which measure stuff 731 00:50:22,420 --> 00:50:27,020 that is related to, how does energy move in the molecule? 732 00:50:27,020 --> 00:50:28,550 What is going on in the molecule? 733 00:50:28,550 --> 00:50:31,964 What are the mechanisms for stuff happening? 734 00:50:31,964 --> 00:50:33,880 And in magnetic resonance, there are all sorts 735 00:50:33,880 --> 00:50:37,150 of pulse sequences that interrogate distances 736 00:50:37,150 --> 00:50:39,830 and correlated motions. 737 00:50:39,830 --> 00:50:43,570 And it is really a laboratory for time dependent quantum 738 00:50:43,570 --> 00:50:48,130 mechanics with a time dependent Hamiltonian. 739 00:50:48,130 --> 00:50:54,700 But a lot of stuff that we do with ordinary laser experiments 740 00:50:54,700 --> 00:51:01,880 are usually understandable in a time independent way. 741 00:51:01,880 --> 00:51:07,590 Now, we want to get rid of things that are complicated. 742 00:51:07,590 --> 00:51:11,220 And so one of the things that we do 743 00:51:11,220 --> 00:51:14,970 is, we map a problem onto something 744 00:51:14,970 --> 00:51:17,460 which is time independent. 745 00:51:17,460 --> 00:51:20,970 And so one of the tricks that you will see 746 00:51:20,970 --> 00:51:25,890 is that if we go into what's called a rotating coordinate 747 00:51:25,890 --> 00:51:28,890 system, this rotating coordinate system 748 00:51:28,890 --> 00:51:36,330 is rotating at an energy level different divided by h bar. 749 00:51:36,330 --> 00:51:39,984 And that converts the problem into a time independent problem 750 00:51:39,984 --> 00:51:41,400 in the rotating coordinate system. 751 00:51:41,400 --> 00:51:43,660 So that you're in a rotating coordinate system 752 00:51:43,660 --> 00:51:47,610 and, basically, you use the ordinary perturbation theory. 753 00:51:47,610 --> 00:51:50,670 And then you go back to the non-rotating coordinate system. 754 00:51:50,670 --> 00:51:53,880 So there's all sorts of tricks where we build on the stuff 755 00:51:53,880 --> 00:51:56,480 that we understood. 756 00:51:56,480 --> 00:52:00,560 And we can have a picture which is intuitive, 757 00:52:00,560 --> 00:52:02,870 because we want to strip away a lot of the mathematics 758 00:52:02,870 --> 00:52:05,540 and see the universal stuff. 759 00:52:05,540 --> 00:52:08,660 And so I'm going to try to present as much of that 760 00:52:08,660 --> 00:52:10,950 as I can during this course. 761 00:52:10,950 --> 00:52:13,882 But a lot of the time independent stuff 762 00:52:13,882 --> 00:52:16,340 is heavy lifting, and I'm going to have to do a lot of that 763 00:52:16,340 --> 00:52:17,250 too. 764 00:52:17,250 --> 00:52:18,080 OK. 765 00:52:18,080 --> 00:52:20,600 Have a nice long weekend. 766 00:52:20,600 --> 00:52:22,250 I'll see you on Monday.