1 00:00:07,000 --> 00:00:13,000 I just recalling some of the notation we are going to need 2 00:00:12,000 --> 00:00:18,000 for today, and a couple of the facts that we're going to use, 3 00:00:18,000 --> 00:00:24,000 plus trying to clear up a couple of confusions that the 4 00:00:23,000 --> 00:00:29,000 recitations report. This can be thought of two 5 00:00:28,000 --> 00:00:34,000 ways. It's a formal polynomial in D, 6 00:00:31,000 --> 00:00:37,000 in the letter D. It just has the shape of the 7 00:00:36,000 --> 00:00:42,000 polynomial, D squared plus AD plus B. 8 00:00:40,000 --> 00:00:46,000 A and B are constant coefficients. 9 00:00:42,000 --> 00:00:48,000 But, it's also, at the same time, 10 00:00:45,000 --> 00:00:51,000 if you think what it does, it's a linear operator on 11 00:00:49,000 --> 00:00:55,000 functions. It's a linear operator on 12 00:00:52,000 --> 00:00:58,000 functions like y of t. You think of it both ways: 13 00:00:56,000 --> 00:01:02,000 formal polynomial because we want to do things like factoring 14 00:01:01,000 --> 00:01:07,000 it, substituting two for D and things like that. 15 00:01:06,000 --> 00:01:12,000 Those are things you do with polynomials. 16 00:01:08,000 --> 00:01:14,000 You do them algebraically. You can take the formal 17 00:01:11,000 --> 00:01:17,000 derivative of the polynomial because it's just sums of 18 00:01:14,000 --> 00:01:20,000 powers. On the other hand, 19 00:01:16,000 --> 00:01:22,000 as a linear operator, it does something to functions. 20 00:01:19,000 --> 00:01:25,000 It differentiates them, multiplies them by constants or 21 00:01:23,000 --> 00:01:29,000 something like that. So it's, so to speak, 22 00:01:25,000 --> 00:01:31,000 has a dual aspect this way. And, that's one of the things 23 00:01:29,000 --> 00:01:35,000 we are exploiting what we use operator methods to solve 24 00:01:32,000 --> 00:01:38,000 differential equations. Now, let me remind you of the 25 00:01:37,000 --> 00:01:43,000 key thing we were interested in. f of t: 26 00:01:40,000 --> 00:01:46,000 not any old function, we'll get to that next time, 27 00:01:44,000 --> 00:01:50,000 but f of t, exponentials. 28 00:01:46,000 --> 00:01:52,000 So, it should be an exponential or something like an 29 00:01:50,000 --> 00:01:56,000 exponential, or pretty close to it, for example, 30 00:01:54,000 --> 00:02:00,000 something with sine t and cosine t, 31 00:01:57,000 --> 00:02:03,000 or e to the, that could be thought of as 32 00:02:01,000 --> 00:02:07,000 part of the real or imaginary part of a complex exponential. 33 00:02:07,000 --> 00:02:13,000 And, maybe by the end of today, we will have generalized that 34 00:02:10,000 --> 00:02:16,000 even little more. But basically, 35 00:02:12,000 --> 00:02:18,000 I'm interested in exponentials. Let's make it alpha complex. 36 00:02:16,000 --> 00:02:22,000 That will at least take care of the cases, e to the ax times 37 00:02:20,000 --> 00:02:26,000 cosine bx, sin bx, 38 00:02:23,000 --> 00:02:29,000 which are the main cases. Those are the main cases. 39 00:02:26,000 --> 00:02:32,000 Then, remember the little table we made. 40 00:02:30,000 --> 00:02:36,000 I simply gave you the formula for the particular solution. 41 00:02:34,000 --> 00:02:40,000 So, what we're looking for is we already know how to solve the 42 00:02:39,000 --> 00:02:45,000 homogeneous equation. What we want is that particular 43 00:02:44,000 --> 00:02:50,000 solution. And then, the recipe for it I 44 00:02:47,000 --> 00:02:53,000 gave you, these things were proved by the substitution rules 45 00:02:52,000 --> 00:02:58,000 and exponential shift rules. The recipe was that if f of t 46 00:02:57,000 --> 00:03:03,000 was, let's make a little table. 47 00:03:00,000 --> 00:03:06,000 f of t is, well, it's always e to the a t. 48 00:03:03,000 --> 00:03:09,000 So, in other words, 49 00:03:07,000 --> 00:03:13,000 it's e to the a t. The cases are, 50 00:03:10,000 --> 00:03:16,000 so yp, what is the yp? Well, it is the normal case is 51 00:03:13,000 --> 00:03:19,000 yp equals e to that alpha t divided by the 52 00:03:17,000 --> 00:03:23,000 polynomial where you substitute, you take that polynomial, 53 00:03:21,000 --> 00:03:27,000 and wherever you see a D, you substitute the complex 54 00:03:24,000 --> 00:03:30,000 number, alpha. There, I'm thinking of it as a 55 00:03:27,000 --> 00:03:33,000 formal polynomial. I'm not thinking of it as an 56 00:03:31,000 --> 00:03:37,000 operator. Now, this breaks down. 57 00:03:34,000 --> 00:03:40,000 So, that's the formula for the particular solution. 58 00:03:37,000 --> 00:03:43,000 The only trouble is, it breaks down if p of alpha is 59 00:03:40,000 --> 00:03:46,000 zero. So, we have to assume that it's 60 00:03:43,000 --> 00:03:49,000 not. Now, if p of alpha is zero, 61 00:03:45,000 --> 00:03:51,000 that means alpha is a root of the polynomial, 62 00:03:48,000 --> 00:03:54,000 a zero of the polynomial is a better word. 63 00:03:51,000 --> 00:03:57,000 So, in that case, it will be e to the alpha t 64 00:03:54,000 --> 00:04:00,000 divided by p prime of alpha. 65 00:03:57,000 --> 00:04:03,000 Differentiate formally the polynomials, -- 66 00:04:02,000 --> 00:04:08,000 -- and you will get 2D plus A. 67 00:04:04,000 --> 00:04:10,000 And now, substitute in the alpha. 68 00:04:06,000 --> 00:04:12,000 And, this will be okay provided p prime of alpha 69 00:04:10,000 --> 00:04:16,000 is not zero. That means that alpha is the 70 00:04:12,000 --> 00:04:18,000 simple root, simple zero of p. And then, there's one more 71 00:04:15,000 --> 00:04:21,000 case, which, since I won't need today, I won't write on the 72 00:04:19,000 --> 00:04:25,000 board. But, you'll need it for 73 00:04:21,000 --> 00:04:27,000 homework. So, make sure you know it. 74 00:04:23,000 --> 00:04:29,000 Another words, if this is zero, 75 00:04:25,000 --> 00:04:31,000 then you've got a double root. And, there is still a different 76 00:04:28,000 --> 00:04:34,000 formula. And, this is wrong because I 77 00:04:30,000 --> 00:04:36,000 forgot the t. Yes? 78 00:04:33,000 --> 00:04:39,000 I could tell on your faces. That was before, 79 00:04:41,000 --> 00:04:47,000 and now we are up to today. What we are interested in 80 00:04:51,000 --> 00:04:57,000 talking about today is what this has to do with the phenomenon of 81 00:05:03,000 --> 00:05:09,000 resonance. Everybody knows at least one 82 00:05:09,000 --> 00:05:15,000 case of resonance, I hope. 83 00:05:11,000 --> 00:05:17,000 A little kid is on his swing, right? 84 00:05:14,000 --> 00:05:20,000 Back and forth, and they are very, 85 00:05:16,000 --> 00:05:22,000 very little, so they want a push. 86 00:05:19,000 --> 00:05:25,000 Okay, well, everybody knows that to make the swing go, 87 00:05:23,000 --> 00:05:29,000 a swing has a certain natural frequency. 88 00:05:27,000 --> 00:05:33,000 It swings back and forth like that. 89 00:05:31,000 --> 00:05:37,000 It's a simple pendulum. It's actually damped, 90 00:05:34,000 --> 00:05:40,000 but let's pretend that it isn't. 91 00:05:36,000 --> 00:05:42,000 Everybody knows you want to push a kid on a swing so that 92 00:05:41,000 --> 00:05:47,000 they go high. You have to push with 93 00:05:43,000 --> 00:05:49,000 essentially the same frequency that the natural frequency of 94 00:05:48,000 --> 00:05:54,000 the spring, of the swing is. It's automatic, 95 00:05:51,000 --> 00:05:57,000 because when you come back here, it gets to there, 96 00:05:55,000 --> 00:06:01,000 and that's where you push. So, automatically, 97 00:05:59,000 --> 00:06:05,000 you time your pushes. But if you want the kid to 98 00:06:04,000 --> 00:06:10,000 stop, you just do the opposite. Push at the wrong time. 99 00:06:08,000 --> 00:06:14,000 So anyway, that's resonance. Of course, there are more 100 00:06:12,000 --> 00:06:18,000 serious applications of it. It's what made the Tacoma 101 00:06:16,000 --> 00:06:22,000 Bridge fall down, and I think movies of that are 102 00:06:20,000 --> 00:06:26,000 now being shown not merely on television, but in elementary 103 00:06:24,000 --> 00:06:30,000 school. Resonance is what made, 104 00:06:27,000 --> 00:06:33,000 okay, more resonance stories later. 105 00:06:31,000 --> 00:06:37,000 So, my aim is, what is this physical 106 00:06:33,000 --> 00:06:39,000 phenomenon, that to get a big amplitude you should have it 107 00:06:38,000 --> 00:06:44,000 match the frequency? What does that have to do with 108 00:06:41,000 --> 00:06:47,000 a differential equation? Well, the differential equation 109 00:06:46,000 --> 00:06:52,000 for that simple pendulum, let's assume it's undamped, 110 00:06:50,000 --> 00:06:56,000 will be of the type y double prime plus, 111 00:06:53,000 --> 00:06:59,000 I'm using t now since t is time. 112 00:06:56,000 --> 00:07:02,000 That will be our new independent variable, 113 00:06:59,000 --> 00:07:05,000 plus omega nought squared is the natural 114 00:07:03,000 --> 00:07:09,000 frequency of the pendulum or of the spring, or whatever it is 115 00:07:08,000 --> 00:07:14,000 that's doing the vibrating. Yeah, any questions? 116 00:07:15,000 --> 00:07:21,000 What we're doing is driving that with the cosine, 117 00:07:23,000 --> 00:07:29,000 with something of a different frequency. 118 00:07:31,000 --> 00:07:37,000 So, this is the input, or the driving term as it's 119 00:07:36,000 --> 00:07:42,000 often called, or it's sometimes called the 120 00:07:40,000 --> 00:07:46,000 forcing term. And, the point is I'm going to 121 00:07:45,000 --> 00:07:51,000 assume that the frequency is different. 122 00:07:49,000 --> 00:07:55,000 The driving frequency is different from the natural 123 00:07:54,000 --> 00:08:00,000 frequency. So, this is the input 124 00:07:57,000 --> 00:08:03,000 frequency. Okay, and now let's simply 125 00:08:01,000 --> 00:08:07,000 solve the equation and see what we get. 126 00:08:03,000 --> 00:08:09,000 So, it's if I write it using the operator, 127 00:08:06,000 --> 00:08:12,000 it's D squared plus omega nought squared applied to y 128 00:08:09,000 --> 00:08:15,000 is equal to cosine. 129 00:08:12,000 --> 00:08:18,000 It's a good idea to do this because the formulas are going 130 00:08:15,000 --> 00:08:21,000 to ask you to substitute into a polynomial. 131 00:08:17,000 --> 00:08:23,000 So, it's good to have the polynomial right in front of you 132 00:08:21,000 --> 00:08:27,000 to avoid the possibility of error. 133 00:08:23,000 --> 00:08:29,000 Well, really what I want is the particular solution. 134 00:08:26,000 --> 00:08:32,000 It's the particular solution that's going to give me a pure 135 00:08:30,000 --> 00:08:36,000 oscillation. And, the thing to do is, 136 00:08:33,000 --> 00:08:39,000 of course, since this cosine, you want to make it complex. 137 00:08:37,000 --> 00:08:43,000 So, we are going to complexify the equation in order to be able 138 00:08:42,000 --> 00:08:48,000 to solve it more easily, and in order to be able to use 139 00:08:45,000 --> 00:08:51,000 those formulas. So, the complex equation is 140 00:08:48,000 --> 00:08:54,000 going to be D squared plus omega nought squared. 141 00:08:52,000 --> 00:08:58,000 Well, it's going to be a 142 00:08:55,000 --> 00:09:01,000 complex, particular solution. So, I'll call it y tilde. 143 00:09:00,000 --> 00:09:06,000 And, on the right-hand side, that's going to be e to the i 144 00:09:04,000 --> 00:09:10,000 omega1 t. Cosine is the real part of 145 00:09:07,000 --> 00:09:13,000 this. So, when we get our answer, 146 00:09:10,000 --> 00:09:16,000 we want to be sure to take the real part of the answer. 147 00:09:13,000 --> 00:09:19,000 I don't want the complex answer, I want its real part. 148 00:09:17,000 --> 00:09:23,000 I want the real answer, in other words, 149 00:09:20,000 --> 00:09:26,000 the really real answer, the real real answer. 150 00:09:23,000 --> 00:09:29,000 So, now without further ado, because of those beautiful, 151 00:09:27,000 --> 00:09:33,000 the problem has been solved once and for all by using the 152 00:09:31,000 --> 00:09:37,000 substitution rule. I did that for you on Monday. 153 00:09:36,000 --> 00:09:42,000 The answer is simply e to the i omega1 t 154 00:09:41,000 --> 00:09:47,000 divided by what? This polynomial with omega one 155 00:09:45,000 --> 00:09:51,000 substituted in for D. So, sorry, i omega one, 156 00:09:49,000 --> 00:09:55,000 the complex coefficient of t. 157 00:09:53,000 --> 00:09:59,000 So, it is substitute i omega for D, I omega one for D, 158 00:09:57,000 --> 00:10:03,000 and you get (i omega one) squared plus omega nought 159 00:10:01,000 --> 00:10:07,000 squared. 160 00:10:06,000 --> 00:10:12,000 Well, let's make that look a little bit better. 161 00:10:09,000 --> 00:10:15,000 This should be e to the (i omega one t) 162 00:10:14,000 --> 00:10:20,000 divided by, now, what's this? 163 00:10:17,000 --> 00:10:23,000 This is simply omega nought squared minus omega 164 00:10:22,000 --> 00:10:28,000 one squared. But, I want the real part of 165 00:10:27,000 --> 00:10:33,000 it. So, as one final, 166 00:10:28,000 --> 00:10:34,000 last step, the real part of that is what we call just the 167 00:10:33,000 --> 00:10:39,000 real particular solution, so, yp without the tilde 168 00:10:37,000 --> 00:10:43,000 anymore. And, the real part of this, 169 00:10:42,000 --> 00:10:48,000 well, this cosine plus i sine. And, the denominator, 170 00:10:45,000 --> 00:10:51,000 luckily, turns out to be real. So, it's simply going to be 171 00:10:50,000 --> 00:10:56,000 cosine omega one t. 172 00:10:52,000 --> 00:10:58,000 That's the top, divided by this thing, 173 00:10:55,000 --> 00:11:01,000 omega nought squared minus omega one squared. 174 00:11:00,000 --> 00:11:06,000 In other words, 175 00:11:03,000 --> 00:11:09,000 that's the response. This is the input, 176 00:11:07,000 --> 00:11:13,000 and that's what came out. Well, in other words, 177 00:11:11,000 --> 00:11:17,000 what one sees is, regardless of what natural 178 00:11:15,000 --> 00:11:21,000 frequency this system wanted to use for itself, 179 00:11:20,000 --> 00:11:26,000 at least for this solution, what it responds to is the 180 00:11:25,000 --> 00:11:31,000 driving frequency, the input frequency. 181 00:11:30,000 --> 00:11:36,000 The only thing is that the amplitude has changed, 182 00:11:34,000 --> 00:11:40,000 and in a rather dramatic way, if omega1, depending on the 183 00:11:39,000 --> 00:11:45,000 relative sizes of omega1 and omega2. 184 00:11:43,000 --> 00:11:49,000 Now, the interesting case is when omega one is very close to 185 00:11:48,000 --> 00:11:54,000 omega, the natural frequency. When you push it with 186 00:11:53,000 --> 00:11:59,000 approximately it's natural frequency, then the solution is 187 00:11:59,000 --> 00:12:05,000 big amplitude. The amplitude is large. 188 00:12:04,000 --> 00:12:10,000 So, the solution looks like the frequency. 189 00:12:07,000 --> 00:12:13,000 The input might have looked like this. 190 00:12:10,000 --> 00:12:16,000 Well, it's cosine, so it ought to start up here. 191 00:12:13,000 --> 00:12:19,000 The input might have looked like this, but the response will 192 00:12:18,000 --> 00:12:24,000 be a curve with the same frequency and still a pure 193 00:12:22,000 --> 00:12:28,000 oscillation. But, it will have much, 194 00:12:24,000 --> 00:12:30,000 much bigger amplitude. And, it's because the 195 00:12:28,000 --> 00:12:34,000 denominator, omega nought squared minus omega 196 00:12:32,000 --> 00:12:38,000 one squared, is always zero. 197 00:12:35,000 --> 00:12:41,000 So, the response will, instead, look like this. 198 00:12:41,000 --> 00:12:47,000 Now, to all intents and purposes, that's resonance. 199 00:12:44,000 --> 00:12:50,000 You are pushing something with approximately the same 200 00:12:48,000 --> 00:12:54,000 frequency, something that wants to oscillate. 201 00:12:52,000 --> 00:12:58,000 And, you are pushing it with approximately the same frequency 202 00:12:57,000 --> 00:13:03,000 that it would like to oscillate by itself. 203 00:13:00,000 --> 00:13:06,000 And, what that does is it builds up the amplitude 204 00:13:05,000 --> 00:13:11,000 Well, what happens if omega one is actually equal 205 00:13:10,000 --> 00:13:16,000 to omega zero? So, that's the case I'd like to 206 00:13:14,000 --> 00:13:20,000 analyze for you now. Suppose the two are equal, 207 00:13:18,000 --> 00:13:24,000 in other words. Well, the problem is, 208 00:13:21,000 --> 00:13:27,000 of course, I can't use that same solution. 209 00:13:24,000 --> 00:13:30,000 It isn't applicable. But that's why I gave you, 210 00:13:28,000 --> 00:13:34,000 derived for you using the exponential shift law last time, 211 00:13:33,000 --> 00:13:39,000 the second version, when it is a root. 212 00:13:38,000 --> 00:13:44,000 So, if omega one equals omega nought, 213 00:13:42,000 --> 00:13:48,000 so now our equation looks like D squared plus omega nought 214 00:13:47,000 --> 00:13:53,000 squared, the natural frequency, y. 215 00:13:51,000 --> 00:13:57,000 But this time, the driving frequency, 216 00:13:54,000 --> 00:14:00,000 the input frequency, is omega nought itself. 217 00:13:57,000 --> 00:14:03,000 Then, the same analysis, a lot of it is, 218 00:14:00,000 --> 00:14:06,000 well, I'd better be careful. I'd better be careful. 219 00:14:04,000 --> 00:14:10,000 Let's go through the analysis again very rapidly. 220 00:14:10,000 --> 00:14:16,000 What we want to do is first complexify it, 221 00:14:13,000 --> 00:14:19,000 and then solve. So, the complex equation will 222 00:14:17,000 --> 00:14:23,000 be D squared plus omega nought squared times y tilde equals e 223 00:14:22,000 --> 00:14:28,000 to the i omega nought t, this time. 224 00:14:29,000 --> 00:14:35,000 But now, i omega is zero of this polynomial. 225 00:14:32,000 --> 00:14:38,000 That's why I picked it, right? 226 00:14:35,000 --> 00:14:41,000 If I plug in i omega zero, I get i omega zero 227 00:14:40,000 --> 00:14:46,000 quantity squared plus omega nought squared. 228 00:14:46,000 --> 00:14:52,000 That's zero. 229 00:14:48,000 --> 00:14:54,000 So, I'm in the second case. So, i omega nought is a simple 230 00:14:53,000 --> 00:14:59,000 root, simple zero, of D squared plus 231 00:14:58,000 --> 00:15:04,000 omega nought, that polynomial squared. 232 00:15:04,000 --> 00:15:10,000 Therefore, the complex particular solution is now t e 233 00:15:08,000 --> 00:15:14,000 to the i omega nought t divided by p prime, 234 00:15:13,000 --> 00:15:19,000 where you plug in that root, the i omega nought. 235 00:15:17,000 --> 00:15:23,000 Now, what's p prime? 236 00:15:19,000 --> 00:15:25,000 p prime is 2D, right? 237 00:15:22,000 --> 00:15:28,000 If I differentiate this formally, as if D were a 238 00:15:26,000 --> 00:15:32,000 variable, the way you differentiate polynomials, 239 00:15:29,000 --> 00:15:35,000 the derivative, this is a constant, 240 00:15:32,000 --> 00:15:38,000 and the derivative is 2D. So, the denominator should have 241 00:15:38,000 --> 00:15:44,000 two times for D. You are going to plug in i 242 00:15:42,000 --> 00:15:48,000 omega zero. So, it's 2 i omega zero. 243 00:15:47,000 --> 00:15:53,000 And now, I want the real part 244 00:15:51,000 --> 00:15:57,000 of that, which is what? Well, think about it. 245 00:15:55,000 --> 00:16:01,000 The top is cosine plus i sine. The real part is now going to 246 00:16:00,000 --> 00:16:06,000 come from the sine, right, because it's cosine plus 247 00:16:05,000 --> 00:16:11,000 i sine. But this i is going to divide 248 00:16:09,000 --> 00:16:15,000 out the i that goes with this sine. 249 00:16:11,000 --> 00:16:17,000 And, therefore, the real part is going to be t 250 00:16:15,000 --> 00:16:21,000 times the sine, this time, of omega nought t. 251 00:16:18,000 --> 00:16:24,000 And, that's going to be divided 252 00:16:22,000 --> 00:16:28,000 by, well, the i canceled out the i that was in front of the sine 253 00:16:27,000 --> 00:16:33,000 function. And therefore, 254 00:16:28,000 --> 00:16:34,000 what's left is two omega nought down below. 255 00:16:34,000 --> 00:16:40,000 So, that's our particular solution now. 256 00:16:36,000 --> 00:16:42,000 Well, it looks different from that guy. 257 00:16:39,000 --> 00:16:45,000 It doesn't look like that anymore. 258 00:16:42,000 --> 00:16:48,000 What does it look like? Well, it shows the way to plot 259 00:16:46,000 --> 00:16:52,000 such things is basically it's an oscillation of frequency omega 260 00:16:50,000 --> 00:16:56,000 nought. But, its amplitude is changing. 261 00:16:54,000 --> 00:17:00,000 So, the way to do it is, as always, if you have a basic 262 00:16:58,000 --> 00:17:04,000 oscillation which is neither too fast nor too slow, 263 00:17:02,000 --> 00:17:08,000 think of that as the thing, and the other stuff multiplying 264 00:17:06,000 --> 00:17:12,000 it, think of it as changing the amplitude of that oscillation 265 00:17:10,000 --> 00:17:16,000 with time. So, the amplitude is that 266 00:17:14,000 --> 00:17:20,000 function, t divided by two omega zero. 267 00:17:18,000 --> 00:17:24,000 So, just as we did when we talked about damping, 268 00:17:21,000 --> 00:17:27,000 you plot that and it's negative on the picture. 269 00:17:25,000 --> 00:17:31,000 So, this is the function whose graph is t divided by two omega 270 00:17:29,000 --> 00:17:35,000 nought. That's the changing amplitude, 271 00:17:34,000 --> 00:17:40,000 as it were. And then, the function itself 272 00:17:37,000 --> 00:17:43,000 does what oscillation it can, but it has to stay within those 273 00:17:41,000 --> 00:17:47,000 lines. So, the thing that's 274 00:17:43,000 --> 00:17:49,000 oscillating is sine omega nought t, 275 00:17:47,000 --> 00:17:53,000 which would like to be a pure oscillation, but can't because 276 00:17:52,000 --> 00:17:58,000 its amplitude is being changed by that thing. 277 00:17:55,000 --> 00:18:01,000 So, it's doing this, and now the rest I have to 278 00:17:58,000 --> 00:18:04,000 leave to your imagination. In other words, 279 00:18:03,000 --> 00:18:09,000 what happens when omega nought is equal to, when the driving 280 00:18:07,000 --> 00:18:13,000 frequency is actually equal to omega nought, 281 00:18:11,000 --> 00:18:17,000 mathematically this turns into a different looking solution, 282 00:18:15,000 --> 00:18:21,000 one with steadily increasing amplitude. 283 00:18:18,000 --> 00:18:24,000 The amplitude increases linearly like the function t 284 00:18:22,000 --> 00:18:28,000 divided by two omega nought. 285 00:18:25,000 --> 00:18:31,000 Well, many people are upset by this, slightly, 286 00:18:29,000 --> 00:18:35,000 in the sense that there is a funny feeling. 287 00:18:32,000 --> 00:18:38,000 How is it that that solution can turn into this one? 288 00:18:38,000 --> 00:18:44,000 If I simply let omega one go to omega zero, what happens? 289 00:18:43,000 --> 00:18:49,000 Well, the pink curve just gets taller and taller, 290 00:18:47,000 --> 00:18:53,000 and after a while all you see of it is just a bunch of 291 00:18:52,000 --> 00:18:58,000 vertical lines which seem to be spaced at whatever the right 292 00:18:57,000 --> 00:19:03,000 period is for that function. It's sort of like being in a 293 00:19:03,000 --> 00:19:09,000 first story window and watching a giraffe go by. 294 00:19:08,000 --> 00:19:14,000 All you see is that. Okay. 295 00:19:20,000 --> 00:19:26,000 So, my concern is how does that function turn into this one? 296 00:19:24,000 --> 00:19:30,000 I have something in mind to remind you of, 297 00:19:27,000 --> 00:19:33,000 and that's why we'll go through this little exercise. 298 00:19:31,000 --> 00:19:37,000 It's a simple exercise. But the function of it is, 299 00:19:35,000 --> 00:19:41,000 of course that as omega one goes to omega zero cannot 300 00:19:39,000 --> 00:19:45,000 possibly turn into this. It's doing the wrong thing near 301 00:19:43,000 --> 00:19:49,000 zero. It's already zooming up. 302 00:19:45,000 --> 00:19:51,000 But, the point is, this is not the only particular 303 00:19:49,000 --> 00:19:55,000 solution on the block. Any solution whatsoever of the 304 00:19:52,000 --> 00:19:58,000 differential equation, the inhomogeneous equation, 305 00:19:56,000 --> 00:20:02,000 is a particular solution. It's like Fred Rogers: 306 00:20:01,000 --> 00:20:07,000 everybody is special. Okay, so all solutions are 307 00:20:05,000 --> 00:20:11,000 special. We don't have to use that one. 308 00:20:08,000 --> 00:20:14,000 So, I will use, where are all the other 309 00:20:11,000 --> 00:20:17,000 solutions? So, I'm going back to the 310 00:20:14,000 --> 00:20:20,000 equation D squared plus omega zero squared, 311 00:20:18,000 --> 00:20:24,000 applied to y, 312 00:20:20,000 --> 00:20:26,000 is equal to cosine omega one t. 313 00:20:24,000 --> 00:20:30,000 Now, the particular solution we found was that one, 314 00:20:27,000 --> 00:20:33,000 cosine omega one t divided by that omega nought squared minus 315 00:20:32,000 --> 00:20:38,000 omega one squared. 316 00:20:39,000 --> 00:20:45,000 What do the other particular solutions look like? 317 00:20:44,000 --> 00:20:50,000 Well, in general, any particular solution will 318 00:20:49,000 --> 00:20:55,000 look like that one we found, what is it, omega nought 319 00:20:54,000 --> 00:21:00,000 squared minus omega one squared, 320 00:21:01,000 --> 00:21:07,000 plus I'm allowed to add to it any piece of the complementary 321 00:21:07,000 --> 00:21:13,000 solution. Equally particular, 322 00:21:11,000 --> 00:21:17,000 and equally good, as a particular solution is 323 00:21:14,000 --> 00:21:20,000 this plus anything which solved the homogeneous equation. 324 00:21:18,000 --> 00:21:24,000 Now, all I'm going to do is pick out one good function which 325 00:21:23,000 --> 00:21:29,000 solves the homogeneous equation, and here it is. 326 00:21:26,000 --> 00:21:32,000 It's the function minus cosine. In fact, what does solve the 327 00:21:32,000 --> 00:21:38,000 homogeneous equation? Well, it's solved by sine omega 328 00:21:36,000 --> 00:21:42,000 nought t, cosine omega nought t, 329 00:21:40,000 --> 00:21:46,000 and any linear combination of 330 00:21:44,000 --> 00:21:50,000 those. So, out of all those functions, 331 00:21:47,000 --> 00:21:53,000 the one I'm going to pick is cosine omega nought t. 332 00:21:51,000 --> 00:21:57,000 And, I'm going to divide it by this same guy. 333 00:21:55,000 --> 00:22:01,000 So, this is part of the complementary solution. 334 00:22:00,000 --> 00:22:06,000 That's what we call the complementary solution, 335 00:22:02,000 --> 00:22:08,000 the solution to the associated homogeneous equation, 336 00:22:06,000 --> 00:22:12,000 to the reduced equation. Call it what you like. 337 00:22:08,000 --> 00:22:14,000 So, this is one of the guys in there, and it's still a 338 00:22:12,000 --> 00:22:18,000 particular solution to take the one I first found, 339 00:22:15,000 --> 00:22:21,000 and add to it anything which solves the homogeneous equation. 340 00:22:19,000 --> 00:22:25,000 I showed you that when we first set out to solve the 341 00:22:22,000 --> 00:22:28,000 inhomogeneous equation in general. 342 00:22:24,000 --> 00:22:30,000 Now, why do I pick that? Well, I'm going to now 343 00:22:27,000 --> 00:22:33,000 calculate, what's the limit? So, these guys are also good 344 00:22:31,000 --> 00:22:37,000 solutions to that. This is a good solution to that 345 00:22:35,000 --> 00:22:41,000 equation, this equation. All I'm going to do now is 346 00:22:38,000 --> 00:22:44,000 calculate the limit as omega one approaches omega zero of this 347 00:22:42,000 --> 00:22:48,000 function. Well, what is that? 348 00:22:46,000 --> 00:22:52,000 It's cosine omega one t minus cosine omega zero t divided by 349 00:22:50,000 --> 00:22:56,000 omega nought squared minus omega one squared. 350 00:22:57,000 --> 00:23:03,000 Now, you see why I did that. If I let just this guy, 351 00:23:02,000 --> 00:23:08,000 omega one approaches omega zero, 352 00:23:07,000 --> 00:23:13,000 I get infinity. I don't get anything. 353 00:23:10,000 --> 00:23:16,000 But, this is different here because I fixed it up, 354 00:23:14,000 --> 00:23:20,000 now. The denominator becomes zero, 355 00:23:17,000 --> 00:23:23,000 but so does the numerator. In other words, 356 00:23:21,000 --> 00:23:27,000 I've put myself in position to use L'Hopital rule. 357 00:23:26,000 --> 00:23:32,000 So, let's L'Hopital it. It's the limit. 358 00:23:29,000 --> 00:23:35,000 As omega one approaches omega zero, and what do you do? 359 00:23:34,000 --> 00:23:40,000 You differentiate the top and the bottom with respect to what? 360 00:23:42,000 --> 00:23:48,000 Right, with respect to omega one. 361 00:23:44,000 --> 00:23:50,000 Omega one is the variable. That's what's changing. 362 00:23:47,000 --> 00:23:53,000 The t that I'm thinking of is, I'm thinking, 363 00:23:50,000 --> 00:23:56,000 for the temporary fixed. This has a fixed value. 364 00:23:53,000 --> 00:23:59,000 Omega nought is fixed. All that's changing in this 365 00:23:57,000 --> 00:24:03,000 limit operation is omega one. And therefore, 366 00:24:01,000 --> 00:24:07,000 it's with respect to omega one that I differentiate it. 367 00:24:05,000 --> 00:24:11,000 You got that? Well, you are in no position to 368 00:24:08,000 --> 00:24:14,000 say yes or no, so I shouldn't even ask the 369 00:24:11,000 --> 00:24:17,000 question, but okay, rhetorical question. 370 00:24:14,000 --> 00:24:20,000 All right, let's differentiate this expression, 371 00:24:17,000 --> 00:24:23,000 the top and bottom with respect to omega one. 372 00:24:20,000 --> 00:24:26,000 So, the derivative of the top with respect to omega one is 373 00:24:24,000 --> 00:24:30,000 negative sine omega one t. 374 00:24:28,000 --> 00:24:34,000 But, I have to use the chain rule. 375 00:24:32,000 --> 00:24:38,000 That's differentiating with respect to this argument, 376 00:24:35,000 --> 00:24:41,000 this variable. But now, I must take times the 377 00:24:38,000 --> 00:24:44,000 derivative of this thing with respect to omega one. 378 00:24:43,000 --> 00:24:49,000 And that is t is the constant, so times t. 379 00:24:46,000 --> 00:24:52,000 And, how about the bottom? The derivative of the bottom 380 00:24:49,000 --> 00:24:55,000 with respect to omega one is, well, that's a constant. 381 00:24:53,000 --> 00:24:59,000 So, it becomes zero. And, this becomes negative two 382 00:24:57,000 --> 00:25:03,000 omega one. So, it's the limit of this 383 00:25:01,000 --> 00:25:07,000 expression as omega one approaches omega zero. 384 00:25:05,000 --> 00:25:11,000 And now it's not indeterminate 385 00:25:09,000 --> 00:25:15,000 anymore. The answer is, 386 00:25:10,000 --> 00:25:16,000 the negative signs cancel. It's simply t sine omega nought 387 00:25:15,000 --> 00:25:21,000 t divided by two omega nought. 388 00:25:19,000 --> 00:25:25,000 So, that's how we get that 389 00:25:21,000 --> 00:25:27,000 solution. It is a limit as omega one, 390 00:25:24,000 --> 00:25:30,000 but not of the particular solution we found 391 00:25:28,000 --> 00:25:34,000 first, but of this other one. Now, it's still too much 392 00:25:34,000 --> 00:25:40,000 algebra. I mean, what's going on here? 393 00:25:37,000 --> 00:25:43,000 Well, that's something else you should know. 394 00:25:41,000 --> 00:25:47,000 Okay, so my question is, therefore, what does this mean? 395 00:25:46,000 --> 00:25:52,000 What's the geometric meaning of all this? 396 00:25:50,000 --> 00:25:56,000 In other words, what does that function look 397 00:25:54,000 --> 00:26:00,000 like? Well, that's another 398 00:25:56,000 --> 00:26:02,000 trigonometric identity, which in your book is just 399 00:26:01,000 --> 00:26:07,000 buried as half of one line sort of casual as if everybody knows 400 00:26:07,000 --> 00:26:13,000 it, and I know that virtually no one knows it. 401 00:26:13,000 --> 00:26:19,000 But, here's your chance. So, the cosine of B minus the 402 00:26:17,000 --> 00:26:23,000 cosine of A can be expressed as a product of 403 00:26:22,000 --> 00:26:28,000 signs. It's the sine of (A minus B) 404 00:26:25,000 --> 00:26:31,000 over two times the sine of (A plus B) over two, 405 00:26:29,000 --> 00:26:35,000 I believe. 406 00:26:33,000 --> 00:26:39,000 My only uncertainty: is there a two in front of 407 00:26:37,000 --> 00:26:43,000 that? I think there has to be. 408 00:26:40,000 --> 00:26:46,000 Let me check. Sorry. 409 00:26:42,000 --> 00:26:48,000 Is there a two? I wouldn't trust my memory 410 00:26:46,000 --> 00:26:52,000 anyway. I'd look it up. 411 00:26:49,000 --> 00:26:55,000 I did look it up, two, yes. 412 00:26:51,000 --> 00:26:57,000 If you had to prove that, you could use the sine formula 413 00:26:57,000 --> 00:27:03,000 to expand this out. That would be a bad way to do 414 00:27:03,000 --> 00:27:09,000 it. The best way is to use complex 415 00:27:05,000 --> 00:27:11,000 numbers. Express the sign in terms of 416 00:27:08,000 --> 00:27:14,000 complex numbers, exponentials, 417 00:27:10,000 --> 00:27:16,000 you know, the backwards Euler formula. 418 00:27:13,000 --> 00:27:19,000 Then do it here, and then just multiply those 419 00:27:17,000 --> 00:27:23,000 two expressions involving exponentials together, 420 00:27:20,000 --> 00:27:26,000 and cancel, cancel, cancel, cancel, 421 00:27:23,000 --> 00:27:29,000 cancel, and this is what you will end up with. 422 00:27:26,000 --> 00:27:32,000 You see why I did this. It's because this has that 423 00:27:31,000 --> 00:27:37,000 form. So, let's apply that formula to 424 00:27:33,000 --> 00:27:39,000 it. So, what's the left-hand side? 425 00:27:36,000 --> 00:27:42,000 B is omega one t, and A is omega nought t. 426 00:27:39,000 --> 00:27:45,000 So, this is omega one t, 427 00:27:42,000 --> 00:27:48,000 and this is omega nought t 428 00:27:44,000 --> 00:27:50,000 All right, so what we get is 429 00:27:47,000 --> 00:27:53,000 that the cosine of omega one t minus the cosine of omega nought 430 00:27:51,000 --> 00:27:57,000 t, which is exactly the 431 00:27:54,000 --> 00:28:00,000 numerator of this function that I'm trying to get a handle on. 432 00:28:00,000 --> 00:28:06,000 Then we will divide it by its amplitude. 433 00:28:02,000 --> 00:28:08,000 So, that's this constant factor that's real. 434 00:28:05,000 --> 00:28:11,000 It's a small number because I'm thinking of omega one 435 00:28:10,000 --> 00:28:16,000 as being rather close to omega zero, 436 00:28:13,000 --> 00:28:19,000 and getting closer and closer. What does this tell us about 437 00:28:17,000 --> 00:28:23,000 the right-hand side? Well, the right-hand side is 438 00:28:21,000 --> 00:28:27,000 twice the sine of A minus B. 439 00:28:24,000 --> 00:28:30,000 Now, that's good because these guys sort of resemble each 440 00:28:28,000 --> 00:28:34,000 other. So, that's (omega nought minus 441 00:28:32,000 --> 00:28:38,000 omega one) times t. 442 00:28:35,000 --> 00:28:41,000 That's A minus B, and I'm supposed to divide that 443 00:28:39,000 --> 00:28:45,000 by two. And then, the other one will be 444 00:28:42,000 --> 00:28:48,000 the same thing with plus: sine omega nought plus omega 445 00:28:46,000 --> 00:28:52,000 one over two times t. 446 00:28:50,000 --> 00:28:56,000 Now, how big is this, approximately? 447 00:28:52,000 --> 00:28:58,000 Remember, think of omega one as close to omega zero. 448 00:28:56,000 --> 00:29:02,000 Then, this is approximately 449 00:28:59,000 --> 00:29:05,000 omega zero. So this part is approximately 450 00:29:03,000 --> 00:29:09,000 sine of omega zero t. 451 00:29:06,000 --> 00:29:12,000 This part, on the other hand, that's a very small thing. 452 00:29:09,000 --> 00:29:15,000 Okay, now what I want to know is what does this function look 453 00:29:13,000 --> 00:29:19,000 like? The interest in knowing what 454 00:29:15,000 --> 00:29:21,000 the function looks like it is because we want to be able to 455 00:29:19,000 --> 00:29:25,000 see that it's limited is that thing. 456 00:29:21,000 --> 00:29:27,000 You can't tell what's what its limit is, geometrically, 457 00:29:25,000 --> 00:29:31,000 unless you know it looks like. So, what does it look like? 458 00:29:30,000 --> 00:29:36,000 Well, again, the way to analyze it is the 459 00:29:35,000 --> 00:29:41,000 thing, that thing. What you think of is, 460 00:29:41,000 --> 00:29:47,000 yeah, of course you cannot divide one side of equality 461 00:29:49,000 --> 00:29:55,000 without dividing the equation by the other side. 462 00:29:56,000 --> 00:30:02,000 So, that's got to be there, too. 463 00:30:02,000 --> 00:30:08,000 Now, what does that look like? Well, the way to think of it 464 00:30:06,000 --> 00:30:12,000 is, here is something with a normal sort of frequency, 465 00:30:10,000 --> 00:30:16,000 omega nought. It's doing its thing. 466 00:30:14,000 --> 00:30:20,000 It's a sine curve. It's doing that. 467 00:30:16,000 --> 00:30:22,000 What's this? Think of all this part as 468 00:30:19,000 --> 00:30:25,000 varying amplitude. It's just another example of 469 00:30:23,000 --> 00:30:29,000 what I gave you before. Here is a basic, 470 00:30:26,000 --> 00:30:32,000 pure oscillation, and now, think of everything 471 00:30:29,000 --> 00:30:35,000 else that's multiplying it as varying its amplitude. 472 00:30:35,000 --> 00:30:41,000 All right, so what does that thing look like? 473 00:30:38,000 --> 00:30:44,000 Well, first what we want to do is plot the amplitude lines. 474 00:30:44,000 --> 00:30:50,000 Now, what will they be? This is sine of an extremely 475 00:30:48,000 --> 00:30:54,000 small number times t. The frequency is small. 476 00:30:52,000 --> 00:30:58,000 How does the sine curve look if its frequency is very low, 477 00:30:57,000 --> 00:31:03,000 very close to zero? Well, that must mean its period 478 00:31:02,000 --> 00:31:08,000 is very large. Here's something with a big 479 00:31:05,000 --> 00:31:11,000 frequency. Here's something with a very, 480 00:31:08,000 --> 00:31:14,000 very low frequency. Now, with a low frequency, 481 00:31:11,000 --> 00:31:17,000 it would hardly get off the ground and get up to one here, 482 00:31:15,000 --> 00:31:21,000 and it would do that. But, it's made to look a little 483 00:31:19,000 --> 00:31:25,000 more presentable because of this coefficient in front, 484 00:31:23,000 --> 00:31:29,000 which is rather large. And so, what this thing looks 485 00:31:27,000 --> 00:31:33,000 like, I won't pause to analyze it more exactly. 486 00:31:32,000 --> 00:31:38,000 It's something which goes up at a reasonable rate for quite a 487 00:31:36,000 --> 00:31:42,000 while, and let's say that's quite awhile. 488 00:31:39,000 --> 00:31:45,000 And then it comes down, and then it goes, 489 00:31:42,000 --> 00:31:48,000 and so on. Of course, in figuring out its 490 00:31:45,000 --> 00:31:51,000 amplitude, we have to be willing to draw its negative, 491 00:31:49,000 --> 00:31:55,000 too. And since I didn't figure 492 00:31:51,000 --> 00:31:57,000 things out right, I can at least make it cross, 493 00:31:54,000 --> 00:32:00,000 right? Okay. 494 00:31:55,000 --> 00:32:01,000 So, this is a picture of this slowly varying amplitude. 495 00:32:01,000 --> 00:32:07,000 And in between, this is the function which is 496 00:32:05,000 --> 00:32:11,000 doing the oscillation, as well as it can. 497 00:32:08,000 --> 00:32:14,000 But, it has to stay within that amplitude. 498 00:32:12,000 --> 00:32:18,000 So, it's doing this. Now, what happens? 499 00:32:15,000 --> 00:32:21,000 As omega one approaches omega zero, 500 00:32:21,000 --> 00:32:27,000 this frequency gets closer and closer to zero, 501 00:32:25,000 --> 00:32:31,000 which means the period of that dotted line gets further and 502 00:32:30,000 --> 00:32:36,000 further out, goes to infinity, and you never do ultimately get 503 00:32:35,000 --> 00:32:41,000 a chance to come down again. All you can see is the initial 504 00:32:42,000 --> 00:32:48,000 part, where it's rising and rising. 505 00:32:45,000 --> 00:32:51,000 And, that's how this curve turns into that one. 506 00:32:49,000 --> 00:32:55,000 Now, of course, this curve is enormously 507 00:32:52,000 --> 00:32:58,000 interesting. You must have had this 508 00:32:55,000 --> 00:33:01,000 somewhere. That's the phenomenon of what 509 00:32:59,000 --> 00:33:05,000 are called beats. Too frequencies-- 510 00:33:03,000 --> 00:33:09,000 Your book has half a page explaining this. 511 00:33:05,000 --> 00:33:11,000 That's the half a page where he gives you this identity, 512 00:33:09,000 --> 00:33:15,000 except it gives it in a wrong form, so that it's hard to 513 00:33:13,000 --> 00:33:19,000 figure out. But anyway, the beats are two 514 00:33:16,000 --> 00:33:22,000 frequencies when you combine them, the two frequencies being 515 00:33:20,000 --> 00:33:26,000 two combined pure oscillations where the frequencies are very 516 00:33:24,000 --> 00:33:30,000 close to each other. What you get is a curve which 517 00:33:27,000 --> 00:33:33,000 looks like that. And, of course, 518 00:33:31,000 --> 00:33:37,000 what you hear is the envelope of the curve. 519 00:33:34,000 --> 00:33:40,000 You hear the dotted lines. Well, you hear this. 520 00:33:37,000 --> 00:33:43,000 You hear that, too. 521 00:33:39,000 --> 00:33:45,000 But, what you hear is-- And, that's how good violinists and 522 00:33:43,000 --> 00:33:49,000 cellists, and so on, tune their instruments. 523 00:33:46,000 --> 00:33:52,000 They get one string right, and then the other strings are 524 00:33:51,000 --> 00:33:57,000 tuned by listening. They don't actually listen for 525 00:33:54,000 --> 00:34:00,000 the sound of the note. They listened just for the 526 00:33:58,000 --> 00:34:04,000 beats, wah, wah, wah, wah, and they turn the peg 527 00:34:02,000 --> 00:34:08,000 and it goes wah, wah, wah, wah, 528 00:34:04,000 --> 00:34:10,000 and then finally as soon as the wahs disappear, 529 00:34:07,000 --> 00:34:13,000 they know that the two strings are in tune. 530 00:34:13,000 --> 00:34:19,000 A piano tuner does the same thing. 531 00:34:16,000 --> 00:34:22,000 Of course, I, being a very bad cellist, 532 00:34:19,000 --> 00:34:25,000 use a tuner. That's another solution, 533 00:34:22,000 --> 00:34:28,000 a more modern solution. Okay. 534 00:34:49,000 --> 00:34:55,000 Oh well. Let's give it a try. 535 00:34:51,000 --> 00:34:57,000 The bad news is that problem six in your problem set, 536 00:34:55,000 --> 00:35:01,000 I didn't ask you about the undamped case. 537 00:34:58,000 --> 00:35:04,000 I thought, since you are mature citizens, you could be asked 538 00:35:03,000 --> 00:35:09,000 about the damped case. 539 00:35:21,000 --> 00:35:27,000 I warn you, first of all you have to get the notation. 540 00:35:26,000 --> 00:35:32,000 This is probably the most important thing I'll do with 541 00:35:31,000 --> 00:35:37,000 this. Your book uses this, resonance. 542 00:36:02,000 --> 00:36:08,000 I'm optimistic. [LAUGHTER] Let's say zero or f 543 00:36:06,000 --> 00:36:12,000 of t. It doesn't matter. 544 00:36:09,000 --> 00:36:15,000 In other words, the constants, 545 00:36:12,000 --> 00:36:18,000 the book uses two sets of constants to describe these 546 00:36:17,000 --> 00:36:23,000 equations. If it's a spring, 547 00:36:20,000 --> 00:36:26,000 and not even talking about RLC circuits, the spring mass, 548 00:36:26,000 --> 00:36:32,000 damping, k, spring constant. Then you divide out by m and 549 00:36:33,000 --> 00:36:39,000 you get this. You're familiar with that. 550 00:36:36,000 --> 00:36:42,000 And, it's only after you divided out by the m that you're 551 00:36:41,000 --> 00:36:47,000 allowed to call this the square of the natural frequency. 552 00:36:46,000 --> 00:36:52,000 So, omega naught is the natural frequency, the natural undamped 553 00:36:51,000 --> 00:36:57,000 frequency. If this term were not there, 554 00:36:54,000 --> 00:37:00,000 that omega nought would give the frequency with 555 00:36:59,000 --> 00:37:05,000 which the system, the little spring would like to 556 00:37:03,000 --> 00:37:09,000 vibrate by itself. Now, further complication is 557 00:37:08,000 --> 00:37:14,000 that the visual uses neither of these. 558 00:37:11,000 --> 00:37:17,000 The visual uses x double dot plus b times x prime, 559 00:37:16,000 --> 00:37:22,000 I think we will have to fix this in the future, 560 00:37:20,000 --> 00:37:26,000 but for now, just live with it, 561 00:37:22,000 --> 00:37:28,000 plus kx, and that's some function, 562 00:37:27,000 --> 00:37:33,000 again, a function. So, in other words, 563 00:37:30,000 --> 00:37:36,000 the problem is that b is okay, can't be confused with c. 564 00:37:37,000 --> 00:37:43,000 On the other hand, this is not the same k as that. 565 00:37:42,000 --> 00:37:48,000 What I'm trying to say is, don't automatically go to a 566 00:37:48,000 --> 00:37:54,000 formula one place, and assume it's the same 567 00:37:53,000 --> 00:37:59,000 formula in another place. You have to use these 568 00:37:58,000 --> 00:38:04,000 equivalences. You have to look and see how 569 00:38:03,000 --> 00:38:09,000 the basic equation was written, and then figure out what the 570 00:38:08,000 --> 00:38:14,000 constant should be. Now, there was something 571 00:38:12,000 --> 00:38:18,000 called, when we analyzed this before, and this has happened in 572 00:38:17,000 --> 00:38:23,000 recitation, there was the natural, damped frequency. 573 00:38:22,000 --> 00:38:28,000 I'll call it the natural, damped frequency. 574 00:38:25,000 --> 00:38:31,000 The book calls it the pseudo-frequency. 575 00:38:30,000 --> 00:38:36,000 It's called pseudo-frequency because the function, 576 00:38:33,000 --> 00:38:39,000 if you have zero on the right hand side, but have damping, 577 00:38:38,000 --> 00:38:44,000 the function isn't periodic. It decays. 578 00:38:41,000 --> 00:38:47,000 It does this. Nonetheless, 579 00:38:43,000 --> 00:38:49,000 it still crosses the t-axis at regular intervals, 580 00:38:47,000 --> 00:38:53,000 and therefore, almost everybody just casually 581 00:38:50,000 --> 00:38:56,000 refers to it as the frequency, and understands it's the 582 00:38:54,000 --> 00:39:00,000 natural damped frequency. Now, the relation between them 583 00:38:59,000 --> 00:39:05,000 is given by the little picture I drew you once. 584 00:39:02,000 --> 00:39:08,000 But, I didn't emphasize it enough. 585 00:39:07,000 --> 00:39:13,000 Here is omega nought. 586 00:39:09,000 --> 00:39:15,000 Here is the right angle. The side is omega one, 587 00:39:12,000 --> 00:39:18,000 and this side is the damping. 588 00:39:15,000 --> 00:39:21,000 So, in other words, this is fixed because it's 589 00:39:19,000 --> 00:39:25,000 fixed by the spring. That's the natural frequency of 590 00:39:23,000 --> 00:39:29,000 the spring, by itself. If you are damping near the 591 00:39:27,000 --> 00:39:33,000 motion, then the more you damped it, the bigger this side gets, 592 00:39:31,000 --> 00:39:37,000 and therefore the smaller omega one is, the bigger the damping, 593 00:39:36,000 --> 00:39:42,000 then the smaller the frequency with which the damped thing 594 00:39:40,000 --> 00:39:46,000 vibrates. That sort of intuitive, 595 00:39:44,000 --> 00:39:50,000 and vice versa. If you decrease the damping to 596 00:39:47,000 --> 00:39:53,000 almost zero, well, then you'll make omega one 597 00:39:49,000 --> 00:39:55,000 almost the same size as omega zero. 598 00:39:51,000 --> 00:39:57,000 This must be a right angle, and therefore, 599 00:39:54,000 --> 00:40:00,000 if there's very little damping, the natural damped frequency 600 00:39:57,000 --> 00:40:03,000 will be almost the same as the original frequency, 601 00:40:00,000 --> 00:40:06,000 the natural frequency. So, the relation between them 602 00:40:05,000 --> 00:40:11,000 is that omega one squared is equal to omega nought squared 603 00:40:11,000 --> 00:40:17,000 minus p squared, 604 00:40:15,000 --> 00:40:21,000 and this comes from the characteristic roots from the 605 00:40:20,000 --> 00:40:26,000 characteristic roots of the damped equation. 606 00:40:26,000 --> 00:40:32,000 So, we did that before. I'm just reminding you of it. 607 00:40:31,000 --> 00:40:37,000 Now, the third frequency which now enters, and that I'm asking 608 00:40:37,000 --> 00:40:43,000 you about on the problem set is if you've got a damped spring, 609 00:40:43,000 --> 00:40:49,000 okay, what happens when you impose a motion on it with yet a 610 00:40:49,000 --> 00:40:55,000 third frequency? In other words, 611 00:40:53,000 --> 00:40:59,000 drive the damped spring. I don't care. 612 00:40:56,000 --> 00:41:02,000 I switched to y, since I'm in y mode. 613 00:41:02,000 --> 00:41:08,000 So, our equation looks like this, just as it did before, 614 00:41:06,000 --> 00:41:12,000 except now going to drive that with an undetermined frequency, 615 00:41:10,000 --> 00:41:16,000 cosine omega t. 616 00:41:13,000 --> 00:41:19,000 And, my question, now, is, see, 617 00:41:15,000 --> 00:41:21,000 it's not going to be able to resonate in the correct-- you 618 00:41:19,000 --> 00:41:25,000 really only get true resonance when you don't have damping. 619 00:41:24,000 --> 00:41:30,000 That's the only time where the amplitude can build up 620 00:41:27,000 --> 00:41:33,000 indefinitely. But nonetheless, 621 00:41:31,000 --> 00:41:37,000 for all practical purposes, and there's always some damping 622 00:41:37,000 --> 00:41:43,000 unless you are a perfect vacuum or something, 623 00:41:42,000 --> 00:41:48,000 there's almost always some damping. 624 00:41:46,000 --> 00:41:52,000 So, p isn't zero, can't be exactly zero. 625 00:41:50,000 --> 00:41:56,000 So, the problem is, which omega gives, 626 00:41:54,000 --> 00:42:00,000 which frequency in the input, which input frequency gives the 627 00:42:00,000 --> 00:42:06,000 maximal amplitude for the response? 628 00:42:20,000 --> 00:42:26,000 We solved that problem when it was undamped, 629 00:42:22,000 --> 00:42:28,000 and the answer was easy. Omega should equal omega zero. 630 00:42:26,000 --> 00:42:32,000 But, when it's damped, the answer is different. 631 00:42:30,000 --> 00:42:36,000 And, I'm not asking you to do it in general. 632 00:42:33,000 --> 00:42:39,000 I'm giving you some numbers. But nonetheless, 633 00:42:37,000 --> 00:42:43,000 it still must be the case. So, I'm giving you, 634 00:42:40,000 --> 00:42:46,000 I give you specific values of p and omega zero. 635 00:42:45,000 --> 00:42:51,000 That's on the problem set. Of course, one of them is tied 636 00:42:50,000 --> 00:42:56,000 to your recitation. But, the answer is, 637 00:42:53,000 --> 00:42:59,000 I'm going to give you the general formula for the answer 638 00:42:58,000 --> 00:43:04,000 to make sure that you don't get wildly astray. 639 00:43:03,000 --> 00:43:09,000 Let's call that omega r, 640 00:43:05,000 --> 00:43:11,000 the resonant omega. This isn't true resonance. 641 00:43:09,000 --> 00:43:15,000 Your book calls it practical resonance. 642 00:43:11,000 --> 00:43:17,000 Again, most people just call it resonance. 643 00:43:15,000 --> 00:43:21,000 So, you know what I mean, type of thing. 644 00:43:18,000 --> 00:43:24,000 It is omega r is very much like that. 645 00:43:20,000 --> 00:43:26,000 Maybe I should have written this one down in the same form. 646 00:43:25,000 --> 00:43:31,000 Omega one is the square root of omega nought squared minus p 647 00:43:29,000 --> 00:43:35,000 squared. 648 00:43:34,000 --> 00:43:40,000 What would you expect? Well, what I would expect is 649 00:43:37,000 --> 00:43:43,000 that omega r should be omega one. 650 00:43:40,000 --> 00:43:46,000 The damped system has a natural frequency. 651 00:43:43,000 --> 00:43:49,000 The resonant frequency should be the same as that natural 652 00:43:47,000 --> 00:43:53,000 frequency with which the damped system wants to do its thing. 653 00:43:52,000 --> 00:43:58,000 And the answer is, that's not right. 654 00:43:54,000 --> 00:44:00,000 It is the square root. It's a little lower. 655 00:43:57,000 --> 00:44:03,000 It's a little lower. It is omega nought squared 656 00:44:01,000 --> 00:44:07,000 minus two p squared.