1 00:00:00,630 --> 00:00:02,990 The Damped Vibrations applet illustrates 2 00:00:02,990 --> 00:00:04,790 several different concepts related 3 00:00:04,790 --> 00:00:06,720 to differential equations. 4 00:00:06,720 --> 00:00:09,515 Initial conditions for second-order equations, 5 00:00:09,515 --> 00:00:13,020 the phase plane for autonomous equations, 6 00:00:13,020 --> 00:00:15,070 and damping conditions for second-order 7 00:00:15,070 --> 00:00:18,240 homogeneous linear equations. 8 00:00:18,240 --> 00:00:22,102 The differential we're studying appears at upper right. 9 00:00:22,102 --> 00:00:24,510 And the parameter names reflect the fact 10 00:00:24,510 --> 00:00:28,310 that this equation describes a mass-spring-dashpot system, 11 00:00:28,310 --> 00:00:33,960 with mass m, dashpot constant b, and spring constant k. 12 00:00:33,960 --> 00:00:36,700 The right-hand side of the equation is zero. 13 00:00:36,700 --> 00:00:38,440 There's no forcing term. 14 00:00:38,440 --> 00:00:41,410 The equation is homogeneous. 15 00:00:41,410 --> 00:00:43,960 The sliders at bottom control the values 16 00:00:43,960 --> 00:00:45,940 of the system parameters. 17 00:00:45,940 --> 00:00:49,550 With the selected values for m, b, and k, 18 00:00:49,550 --> 00:00:52,540 the solutions are damped vibrations. 19 00:00:52,540 --> 00:00:58,090 I can let the solution evolve by grabbing the time slider 20 00:00:58,090 --> 00:01:03,390 or by using the animation key, which also 21 00:01:03,390 --> 00:01:06,170 serves to stop the animation. 22 00:01:06,170 --> 00:01:09,240 If the value of the solution gets too small, 23 00:01:09,240 --> 00:01:12,610 I can blow the picture up using the zoom slider 24 00:01:12,610 --> 00:01:14,250 at the upper left. 25 00:01:14,250 --> 00:01:17,990 Moving it to the right squeezes the solutions. 26 00:01:17,990 --> 00:01:20,020 Moving it to the left makes them larger. 27 00:01:23,984 --> 00:01:28,330 The window on the left lets you set the initial condition 28 00:01:28,330 --> 00:01:29,870 of the system. 29 00:01:29,870 --> 00:01:32,030 There are two components to the initial condition 30 00:01:32,030 --> 00:01:33,880 of a second-order equation. 31 00:01:33,880 --> 00:01:40,150 Position and velocity, that is x and x dot. 32 00:01:40,150 --> 00:01:41,620 Together they form the coordinates 33 00:01:41,620 --> 00:01:44,120 of a point on this plane. 34 00:01:44,120 --> 00:01:47,740 I can grab the point and change both x and x 35 00:01:47,740 --> 00:01:48,620 prime simultaneously. 36 00:01:54,430 --> 00:01:57,480 The x-coordinate is written vertically, 37 00:01:57,480 --> 00:02:00,370 because that's how it's written on the right-hand graphing 38 00:02:00,370 --> 00:02:00,870 window. 39 00:02:00,870 --> 00:02:04,470 And you can see that they keep pace with each other. 40 00:02:04,470 --> 00:02:08,889 The horizontal component is x dot, the initial velocity. 41 00:02:08,889 --> 00:02:11,620 That's positive when we're to the right, 42 00:02:11,620 --> 00:02:14,340 and becomes negative when we're to the left. 43 00:02:18,110 --> 00:02:22,130 The left window represents phase space. 44 00:02:22,130 --> 00:02:25,730 For any time t, the values of x and x dot 45 00:02:25,730 --> 00:02:29,740 are the coordinates of a point in phase space. 46 00:02:29,740 --> 00:02:33,050 And as the solution evolves through time, 47 00:02:33,050 --> 00:02:36,530 that point follows a path, sweeps out 48 00:02:36,530 --> 00:02:40,250 a path in phase space. 49 00:02:40,250 --> 00:02:44,500 And with these selected choices of m, b, and k, 50 00:02:44,500 --> 00:02:46,540 the path is a spiral. 51 00:02:46,540 --> 00:02:49,620 This reflects the fact that both x and x 52 00:02:49,620 --> 00:02:53,101 dot undergo a damped vibration. 53 00:02:53,101 --> 00:02:56,710 The system parameters can be set using these sliders 54 00:02:56,710 --> 00:02:58,350 at lower left. 55 00:02:58,350 --> 00:03:03,680 Let's suggest the mass to be 1/2 and leave k to be one, 56 00:03:03,680 --> 00:03:05,550 and watch what happens to the solutions 57 00:03:05,550 --> 00:03:09,490 as we vary the damping constant b. 58 00:03:09,490 --> 00:03:13,560 When b is small, the solution doesn't damp out as quickly, 59 00:03:13,560 --> 00:03:16,420 and when b is large, it damps out more quickly. 60 00:03:19,400 --> 00:03:22,390 These things become much clearer when you think about them 61 00:03:22,390 --> 00:03:25,220 in terms of the roots of the characteristic polynomial 62 00:03:25,220 --> 00:03:26,660 of this equation. 63 00:03:26,660 --> 00:03:30,130 And we can display those roots by clicking the roots button 64 00:03:30,130 --> 00:03:31,340 here. 65 00:03:31,340 --> 00:03:34,300 What's shown here is the complex plane 66 00:03:34,300 --> 00:03:36,735 with the roots of the characteristic polynomial drawn 67 00:03:36,735 --> 00:03:37,860 on it. 68 00:03:37,860 --> 00:03:42,440 Also we have a readout of the two roots in green over here. 69 00:03:42,440 --> 00:03:46,950 So let's watch what happens when we adjust b. 70 00:03:46,950 --> 00:03:50,930 I'm going to start with b equal to zero. 71 00:03:50,930 --> 00:03:53,880 In this case, there's no damping. 72 00:03:53,880 --> 00:03:58,010 The solutions are sinusoidal, the roots 73 00:03:58,010 --> 00:04:01,590 of the characteristic polynomial are purely imaginary, 74 00:04:01,590 --> 00:04:06,520 and the trajectory in phase space is an ellipse. 75 00:04:06,520 --> 00:04:12,510 Both the solution and its derivative vary sinusoidally. 76 00:04:12,510 --> 00:04:20,120 As I increase b away from zero, I get spirals. 77 00:04:20,120 --> 00:04:25,260 And at the same time, the roots move off the imaginary axis. 78 00:04:25,260 --> 00:04:31,260 They acquire a negative real part, which is minus b over 2m, 79 00:04:31,260 --> 00:04:33,930 incidentally. 80 00:04:33,930 --> 00:04:39,040 And as I increase b further, the spiral opens up, 81 00:04:39,040 --> 00:04:42,290 the damping occurs more quickly, the roots 82 00:04:42,290 --> 00:04:46,860 move away from the imaginary axis. 83 00:04:46,860 --> 00:04:52,560 They increase the size of their real part. 84 00:04:52,560 --> 00:04:54,040 The damping occurs more quickly. 85 00:04:54,040 --> 00:04:56,180 And you'll notice that they get closer and closer 86 00:04:56,180 --> 00:04:58,460 to the real axis as well. 87 00:04:58,460 --> 00:05:01,000 Their imaginary part is decreasing. 88 00:05:01,000 --> 00:05:05,050 That means that the circular frequency, the angular 89 00:05:05,050 --> 00:05:07,470 frequency of the solution, is decreasing. 90 00:05:07,470 --> 00:05:12,060 The period, or pseudo-period of the solution is decreasing. 91 00:05:12,060 --> 00:05:14,600 You can see that in the graph, but it's much clearer 92 00:05:14,600 --> 00:05:17,030 to see what's happening to these roots 93 00:05:17,030 --> 00:05:18,840 of the characteristic polynomial. 94 00:05:18,840 --> 00:05:20,930 There are converging on the real axis, 95 00:05:20,930 --> 00:05:27,449 and eventually they merge into a double root on the real axis. 96 00:05:27,449 --> 00:05:28,490 This is critical damping. 97 00:05:31,440 --> 00:05:40,380 From the readout, we see that the value of b 98 00:05:40,380 --> 00:05:43,120 seems to be about 1.41. 99 00:05:43,120 --> 00:05:45,320 Why don't you take a moment and calculate 100 00:05:45,320 --> 00:05:49,830 what b is for these values of m and k 101 00:05:49,830 --> 00:05:51,435 when critical damping occurs? 102 00:05:55,540 --> 00:05:59,940 If we continue to increase b beyond critical damping, 103 00:05:59,940 --> 00:06:04,400 now the roots move out on the real axis. 104 00:06:04,400 --> 00:06:07,440 There are two exponential solutions, 105 00:06:07,440 --> 00:06:12,450 and the general solution is a linear combination of them. 106 00:06:12,450 --> 00:06:16,350 And there's no oscillation in any solution.