1 00:00:03,640 --> 00:00:05,780 Let's consider a very simple example 2 00:00:05,780 --> 00:00:10,310 of a runner in which our position function x of t 3 00:00:10,310 --> 00:00:13,150 is given as a quadratic function in time. 4 00:00:13,150 --> 00:00:16,350 It will be a constant b times t squared. 5 00:00:16,350 --> 00:00:18,940 Here, b is a constant. 6 00:00:18,940 --> 00:00:20,820 Now it's always important in SI units 7 00:00:20,820 --> 00:00:23,200 to consider what the units of this constant is. 8 00:00:23,200 --> 00:00:26,400 Because a position function is measured in meters 9 00:00:26,400 --> 00:00:29,980 and time is measured in seconds, b is a constant 10 00:00:29,980 --> 00:00:34,170 and it has units of meters per second squared. 11 00:00:34,170 --> 00:00:36,470 And there's an example of a runner-- 12 00:00:36,470 --> 00:00:40,210 and let's make a plot of that position function. 13 00:00:40,210 --> 00:00:44,370 So we're going to plot x of t as a function of time. 14 00:00:44,370 --> 00:00:47,920 b here-- let's make b a positive constant. 15 00:00:47,920 --> 00:00:52,100 And so our function looks something like that. 16 00:00:52,100 --> 00:00:56,400 Now, the velocity-- component of the velocity-- remember v of t 17 00:00:56,400 --> 00:01:00,660 is given by dx dt of this function. 18 00:01:00,660 --> 00:01:03,540 And the derivative of a polynomial t squared 19 00:01:03,540 --> 00:01:04,500 is very simple. 20 00:01:04,500 --> 00:01:09,080 That's just simply 2b times t. 21 00:01:09,080 --> 00:01:10,630 Again, let's look at our units. 22 00:01:10,630 --> 00:01:14,100 Because b has the units of meters per second squared, 23 00:01:14,100 --> 00:01:15,920 and when multiplying that by second, 24 00:01:15,920 --> 00:01:20,470 we have the units of velocity in SI units as meters per second. 25 00:01:20,470 --> 00:01:23,170 Now let's plot that function. 26 00:01:23,170 --> 00:01:27,970 Notice this is a linear function. 27 00:01:27,970 --> 00:01:33,930 And so if I plotted underneath here, the velocity 28 00:01:33,930 --> 00:01:41,590 as a function of time, it starts off with a zero slope. 29 00:01:41,590 --> 00:01:47,250 Remember we're looking-- our velocity at any given time 30 00:01:47,250 --> 00:01:52,280 corresponds to the slope of a tangent line to the position 31 00:01:52,280 --> 00:01:53,900 function. 32 00:01:53,900 --> 00:01:56,660 And you can see that slope is increasing. 33 00:01:56,660 --> 00:01:59,240 Now you wouldn't know it from this graph, 34 00:01:59,240 --> 00:02:02,330 but if you did plot t squared, it's increasing linearly. 35 00:02:02,330 --> 00:02:04,950 And so our velocity function-- the initial slope 36 00:02:04,950 --> 00:02:09,490 is 0 at t equal 0, and it's increasing linearly in time. 37 00:02:09,490 --> 00:02:13,560 So we'll just draw that as some linear function. 38 00:02:13,560 --> 00:02:16,730 And the slope here of this function 39 00:02:16,730 --> 00:02:19,540 will be now the acceleration. 40 00:02:19,540 --> 00:02:25,340 So a of t is the derivative of the component of the velocity 41 00:02:25,340 --> 00:02:27,240 function as a function of time. 42 00:02:27,240 --> 00:02:29,510 And this derivative is quite easy. 43 00:02:29,510 --> 00:02:32,240 It's just simply 2 b. 44 00:02:32,240 --> 00:02:35,079 Now notice those have the units of meters 45 00:02:35,079 --> 00:02:40,250 per second squared, which are units for acceleration. 46 00:02:40,250 --> 00:02:44,760 When we, again, look at the slope, 47 00:02:44,760 --> 00:02:48,140 notice that at every single point, 48 00:02:48,140 --> 00:02:55,170 the slope of the velocity as a function of time is a constant. 49 00:02:55,170 --> 00:02:59,420 The slope here is just equal to 2b. 50 00:02:59,420 --> 00:03:05,510 And so now if we plotted our acceleration function, 51 00:03:05,510 --> 00:03:09,180 we have this point 2 b, and every single point 52 00:03:09,180 --> 00:03:12,790 has the same value of acceleration. 53 00:03:12,790 --> 00:03:16,420 So here the acceleration is an example 54 00:03:16,420 --> 00:03:20,400 of constant acceleration. 55 00:03:20,400 --> 00:03:22,770 And this is our simplest case. 56 00:03:22,770 --> 00:03:24,750 Notice we started with the position function. 57 00:03:24,750 --> 00:03:27,660 We differentiate to get the component of the velocity 58 00:03:27,660 --> 00:03:30,520 and to get the component of the acceleration. 59 00:03:30,520 --> 00:03:33,870 So this is a very simple model for a runner 60 00:03:33,870 --> 00:03:37,079 whose increasing speed linearly, accelerating 61 00:03:37,079 --> 00:03:39,788 at a constant rate.