1 00:00:04,070 --> 00:00:06,940 Recall, when we were examining the motion an object, 2 00:00:06,940 --> 00:00:09,480 in two dimensions, we introduced Cartesian coordinates 3 00:00:09,480 --> 00:00:10,860 and a position vector. 4 00:00:10,860 --> 00:00:14,200 Now let's suppose the object has moved 5 00:00:14,200 --> 00:00:18,140 to a new point, along the orbit. 6 00:00:18,140 --> 00:00:22,980 Well, we'll write another vector r of t. 7 00:00:22,980 --> 00:00:28,680 And let's say this took a time delta t to the new point. 8 00:00:28,680 --> 00:00:32,990 And what we want to define is the displacement 9 00:00:32,990 --> 00:00:34,780 of that object. 10 00:00:34,780 --> 00:00:36,990 So that's a vector delta r. 11 00:00:36,990 --> 00:00:40,410 And recall that a vector of time of t plus delta t 12 00:00:40,410 --> 00:00:47,490 is equal to the old vector r of t plus this displacement vector 13 00:00:47,490 --> 00:00:49,040 delta r. 14 00:00:49,040 --> 00:00:58,660 Now what we want to consider is a limit as delta t goes to 0. 15 00:00:58,660 --> 00:01:03,020 And let's just look graphically at what that means. 16 00:01:03,020 --> 00:01:07,540 As we move this delta, delta t-- as delta t 17 00:01:07,540 --> 00:01:13,140 gets smaller and smaller and our object is getting closer 18 00:01:13,140 --> 00:01:17,470 and closer to its position at time t, 19 00:01:17,470 --> 00:01:20,330 and the position vector r of t plus delta t 20 00:01:20,330 --> 00:01:22,970 is getting closer and closer to r of t delta t, 21 00:01:22,970 --> 00:01:29,400 the key fact is that if we do a tangent to the orbit, 22 00:01:29,400 --> 00:01:35,929 then the limit of delta r is approaching tangent 23 00:01:35,929 --> 00:01:36,470 to the curve. 24 00:01:36,470 --> 00:01:42,940 So in the limit, delta r, the direction 25 00:01:42,940 --> 00:01:49,200 is tangent to the orbit. 26 00:01:49,200 --> 00:01:53,289 So that's our first key property of delta r. 27 00:01:53,289 --> 00:01:55,520 Now the second thing we want to express 28 00:01:55,520 --> 00:01:59,870 is, if we write delta r, as a displacement 29 00:01:59,870 --> 00:02:02,680 in the i-hat direction and a displacement 30 00:02:02,680 --> 00:02:05,240 in the j-hat direction, now again, 31 00:02:05,240 --> 00:02:08,728 maybe we can just clean this up a little bit, 32 00:02:08,728 --> 00:02:10,810 and see what we mean by that. 33 00:02:10,810 --> 00:02:15,640 So here's our delta r. 34 00:02:15,640 --> 00:02:18,500 And we have a little delta x in this direction, 35 00:02:18,500 --> 00:02:20,360 delta y in that direction. 36 00:02:20,360 --> 00:02:23,850 Remember delta x or delta y can be positive or negative. 37 00:02:23,850 --> 00:02:25,230 That's all right. 38 00:02:25,230 --> 00:02:30,600 Now if we want to define our velocity as the limit, 39 00:02:30,600 --> 00:02:35,600 as delta t goes to 0 of delta r over delta t, 40 00:02:35,600 --> 00:02:38,829 then what we see is we have two pieces, the limit as delta t 41 00:02:38,829 --> 00:02:45,810 goes to 0, of delta x over delta t i-hat, plus the limit 42 00:02:45,810 --> 00:02:54,280 as delta t goes to 0 of delta y delta t j-hat. 43 00:02:54,280 --> 00:02:57,329 And the definition of these limits, 44 00:02:57,329 --> 00:03:01,210 we'll write that as the derivative dr, dt. 45 00:03:01,210 --> 00:03:03,860 So the velocity is dr, dt. 46 00:03:03,860 --> 00:03:08,170 And that's equal to dx, dt, how that coordinate function is 47 00:03:08,170 --> 00:03:15,460 changing in time, i-hat plus dy, dt j-hat. 48 00:03:15,460 --> 00:03:18,380 Now as far as notation goes, we write 49 00:03:18,380 --> 00:03:23,940 this philosophy as an x component of the velocity 50 00:03:23,940 --> 00:03:27,440 plus a y component of the velocity, where 51 00:03:27,440 --> 00:03:32,260 the x component, the x, is dx, dt. 52 00:03:32,260 --> 00:03:35,960 And the y component is dy, dt. 53 00:03:35,960 --> 00:03:39,550 Now recall that the direction was tangent to the curve, 54 00:03:39,550 --> 00:03:41,640 but the magnitude of the velocity, 55 00:03:41,640 --> 00:03:45,070 what we call the speed, is just the sum 56 00:03:45,070 --> 00:03:48,960 of the squares of the components, the square root. 57 00:03:48,960 --> 00:03:51,630 And so now we've describe what we 58 00:03:51,630 --> 00:03:55,111 refer to as the instantaneous velocity. 59 00:04:02,480 --> 00:04:06,170 So far we've looked that a trajectory in two dimensions. 60 00:04:06,170 --> 00:04:09,030 Let's again consider some type of motion 61 00:04:09,030 --> 00:04:13,330 where we choose a positive y-axis, a positive x-axis, 62 00:04:13,330 --> 00:04:17,860 an origin, e at vectors, i-hat and j-hat. 63 00:04:17,860 --> 00:04:19,839 And I'll have some type of trajectory, 64 00:04:19,839 --> 00:04:23,010 where our object is moving like that. 65 00:04:23,010 --> 00:04:26,820 We know that at this particular time, 66 00:04:26,820 --> 00:04:34,390 the velocity is tangent to this trajectory, at that point. 67 00:04:34,390 --> 00:04:37,700 And now, what we'd like to do, is 68 00:04:37,700 --> 00:04:40,510 try to describe-- we've described 69 00:04:40,510 --> 00:04:46,020 it's two components ex and vy as a vector. 70 00:04:46,020 --> 00:04:48,730 So if you did vector decomposition, 71 00:04:48,730 --> 00:04:53,870 you would write a vector like this and a vector like that. 72 00:04:53,870 --> 00:04:56,530 This is the x component. 73 00:04:56,530 --> 00:04:58,570 That's the y component. 74 00:04:58,570 --> 00:05:02,270 And now if I define this angle theta, 75 00:05:02,270 --> 00:05:05,960 we know that a vector has a direction and a magnitude. 76 00:05:05,960 --> 00:05:09,600 We've seen what we call the magnitude the speed. 77 00:05:09,600 --> 00:05:13,240 So that's just the sum of these components squared, 78 00:05:13,240 --> 00:05:14,160 square root. 79 00:05:14,160 --> 00:05:15,580 Speed is always positive. 80 00:05:15,580 --> 00:05:18,590 So we always take the positive square root. 81 00:05:18,590 --> 00:05:23,210 And now what about the direction of this vector in the xy plane? 82 00:05:23,210 --> 00:05:26,530 Well, we can see from our geometry 83 00:05:26,530 --> 00:05:31,110 that the tangent theta is given by the y 84 00:05:31,110 --> 00:05:34,460 component over the x component. 85 00:05:34,460 --> 00:05:39,310 Or one could say that the angle theta, at this given time, 86 00:05:39,310 --> 00:05:44,270 is the inverse function of vy over vx. 87 00:05:44,270 --> 00:05:48,740 And so now we've described not only the direction of velocity, 88 00:05:48,740 --> 00:05:53,590 but the angle that it's making with the horizontal axis. 89 00:05:53,590 --> 00:05:56,540 And so we have now completely described the velocity, 90 00:05:56,540 --> 00:05:59,640 instantaneous velocity, vector at time t 91 00:05:59,640 --> 00:06:03,450 in terms of its two component functions, its speed 92 00:06:03,450 --> 00:06:07,130 and the angle that makes at the positive x-axis.