1 00:00:03,390 --> 00:00:05,380 There's another vector operation, 2 00:00:05,380 --> 00:00:11,670 which we call the vector product and sometimes this operation 3 00:00:11,670 --> 00:00:14,310 is called the cross product. 4 00:00:14,310 --> 00:00:20,100 And this is taking two vectors A, the operation cross, 5 00:00:20,100 --> 00:00:23,490 B. And this will give a new vector C. 6 00:00:23,490 --> 00:00:26,190 And now we want to define that new vector C. 7 00:00:26,190 --> 00:00:28,470 So let's draw a three dimensional 8 00:00:28,470 --> 00:00:30,715 picture where we have a plane. 9 00:00:33,890 --> 00:00:45,560 And on this plane, we have two vectors A and B. 10 00:00:45,560 --> 00:00:50,010 And those vectors are forming an angle theta between them. 11 00:00:50,010 --> 00:00:53,480 Now a plane defines two unit normals. 12 00:00:53,480 --> 00:00:56,270 I'll draw one up, which I'm going 13 00:00:56,270 --> 00:01:00,500 to call n hat right hand rule. 14 00:01:00,500 --> 00:01:02,990 And the reason for that right-hand rule 15 00:01:02,990 --> 00:01:09,440 is if we take A cross B, then our right hand thumb 16 00:01:09,440 --> 00:01:13,820 is pointing in the perpendicular direction to the plane. 17 00:01:13,820 --> 00:01:19,789 Now I could have chosen a unit vector down, 18 00:01:19,789 --> 00:01:22,550 n hat left-hand rule. 19 00:01:22,550 --> 00:01:26,570 And this would correspond to taking my left hand 20 00:01:26,570 --> 00:01:30,800 and having A cross B pointing down. 21 00:01:30,800 --> 00:01:35,030 So the way we're going to define our cross-product 22 00:01:35,030 --> 00:01:37,310 is with the right-hand rule. 23 00:01:37,310 --> 00:01:39,830 And so we define it like this. 24 00:01:39,830 --> 00:01:45,979 That the vector C has magnitude, the magnitude 25 00:01:45,979 --> 00:01:52,280 of A times sine of theta, the magnitude of B, 26 00:01:52,280 --> 00:01:58,170 and its direction is given by the right-hand rule. 27 00:01:58,170 --> 00:02:02,720 Now one of the reasons for this definition 28 00:02:02,720 --> 00:02:10,880 is let's draw a vector A and a vector B. 29 00:02:10,880 --> 00:02:15,890 When you have two vectors, they define a magnitude 30 00:02:15,890 --> 00:02:18,110 in the following way. 31 00:02:18,110 --> 00:02:21,020 That we can think about any two vectors 32 00:02:21,020 --> 00:02:24,410 define an area of a parallelogram. 33 00:02:24,410 --> 00:02:28,010 And we can define that area as follows. 34 00:02:28,010 --> 00:02:31,460 Let's drop a perpendicular. 35 00:02:31,460 --> 00:02:34,640 And let's call this B perp. 36 00:02:34,640 --> 00:02:39,260 Then the area, which is a positive quantity, 37 00:02:39,260 --> 00:02:44,720 is given by-- and by the way, our angle theta 38 00:02:44,720 --> 00:02:48,079 here will be always positive-- so we're 39 00:02:48,079 --> 00:02:53,540 going to make it 0 theta pi. 40 00:02:53,540 --> 00:02:58,160 And that way sine of theta is always a positive quantity. 41 00:02:58,160 --> 00:03:04,560 The area is the height, so that B perp times the base, 42 00:03:04,560 --> 00:03:13,090 which is the magnitude of A, and so we can write that as A, 43 00:03:13,090 --> 00:03:18,910 and the magnitude of B perp is B sine theta. 44 00:03:18,910 --> 00:03:23,829 So this quantity, B sine theta, is precisely what's 45 00:03:23,829 --> 00:03:25,430 occurring there. 46 00:03:25,430 --> 00:03:31,210 So the magnitude of C is equal to the area formed 47 00:03:31,210 --> 00:03:34,780 by the vectors A and B. And we have 48 00:03:34,780 --> 00:03:39,490 a choice of which way we want to pick C to point. 49 00:03:39,490 --> 00:03:41,530 And that's where, as a convention, 50 00:03:41,530 --> 00:03:44,540 we're choosing the right-hand rule. 51 00:03:44,540 --> 00:03:47,550 Now again, there is a symmetry here 52 00:03:47,550 --> 00:03:51,790 in that I can also define the area of that triangle 53 00:03:51,790 --> 00:03:52,850 in the following way. 54 00:03:52,850 --> 00:03:54,940 Let's write this, theta. 55 00:03:54,940 --> 00:03:57,340 Instead of taking how much of B is 56 00:03:57,340 --> 00:03:59,770 perpendicular to the direction of A, 57 00:03:59,770 --> 00:04:02,680 let's drop the perpendicular this way, 58 00:04:02,680 --> 00:04:05,890 and write that as a perp. 59 00:04:05,890 --> 00:04:12,910 And then the same area can be expressed 60 00:04:12,910 --> 00:04:16,980 as the magnitude of-- well, we'll express it 61 00:04:16,980 --> 00:04:23,560 as A perp times B. And A perp is the magnitude 62 00:04:23,560 --> 00:04:28,780 of A sine theta times the magnitude of B. 63 00:04:28,780 --> 00:04:32,090 And that's our same definition as before. 64 00:04:32,090 --> 00:04:38,230 And so you see, a sine theta is appearing over here. 65 00:04:38,230 --> 00:04:43,150 So in either choice, our vector operation 66 00:04:43,150 --> 00:04:45,760 says take any two vectors. 67 00:04:45,760 --> 00:04:49,540 Any two vectors forms a parallelogram. 68 00:04:49,540 --> 00:04:52,420 The area of that parallelogram is the magnitude 69 00:04:52,420 --> 00:04:54,250 of the vector product. 70 00:04:54,250 --> 00:04:57,820 And the direction of this new vector C 71 00:04:57,820 --> 00:05:00,070 is given by the right-hand rule with respect 72 00:05:00,070 --> 00:05:04,076 to that parallelogram in that sense.