1 00:00:03,460 --> 00:00:06,430 Let's consider what we call the window washer problem. 2 00:00:06,430 --> 00:00:09,640 What we have is suspended from some ceiling. 3 00:00:09,640 --> 00:00:11,140 We have a pulley. 4 00:00:11,140 --> 00:00:15,790 And the pulley is suspended by a rope, which we're 5 00:00:15,790 --> 00:00:20,060 going to call this string 3. 6 00:00:20,060 --> 00:00:25,140 And we have a rope that is wrapping around this pulley. 7 00:00:25,140 --> 00:00:29,400 And then it wraps around another pulley. 8 00:00:29,400 --> 00:00:32,100 So this rope is going around another pulley. 9 00:00:32,100 --> 00:00:36,750 And it's fixed to the ceiling. 10 00:00:36,750 --> 00:00:41,910 And this is what we're going to call string 1. 11 00:00:41,910 --> 00:00:45,550 And then this string, there's another string 12 00:00:45,550 --> 00:00:49,450 that comes down to a platform. 13 00:00:52,440 --> 00:00:57,290 And this one we're going to call string 2. 14 00:00:57,290 --> 00:01:01,550 And sitting on the platform is a person. 15 00:01:01,550 --> 00:01:05,019 So we have a person sitting on the platform. 16 00:01:05,019 --> 00:01:09,470 And that person is pulling the rope down. 17 00:01:09,470 --> 00:01:12,340 Now this is a very complicated problem. 18 00:01:12,340 --> 00:01:14,640 And it's a classic example of how 19 00:01:14,640 --> 00:01:19,330 do we choose systems so that we can apply Newton's second law. 20 00:01:19,330 --> 00:01:21,539 Now, one of the important things we're going to do 21 00:01:21,539 --> 00:01:25,590 is learn to see when we choose a system what forces 22 00:01:25,590 --> 00:01:28,090 are internal and external. 23 00:01:28,090 --> 00:01:32,970 And that will enable us to pick a very nice system, which 24 00:01:32,970 --> 00:01:35,180 will make the analysis easy. 25 00:01:35,180 --> 00:01:37,820 The way we'll do this is will approach it in stages. 26 00:01:37,820 --> 00:01:42,370 We'll first focus on the person, the platform, and this pulley. 27 00:01:42,370 --> 00:01:51,370 By the way, this is pulley A. And this one is pulley B. 28 00:01:51,370 --> 00:01:56,950 And let's use a symbol P for the platform. 29 00:01:56,950 --> 00:02:02,760 And we'll call this a washer person. 30 00:02:02,760 --> 00:02:05,750 And we're going to use the symbol W for the person. 31 00:02:05,750 --> 00:02:07,620 So what makes this problem complicated 32 00:02:07,620 --> 00:02:09,949 is all these different elements. 33 00:02:09,949 --> 00:02:13,140 Now the first stage is that what we're going to do 34 00:02:13,140 --> 00:02:14,930 is we're going to separately look 35 00:02:14,930 --> 00:02:18,720 at the person, the platform, and then 36 00:02:18,720 --> 00:02:22,190 combine them into a system of person and platform. 37 00:02:22,190 --> 00:02:24,800 But notice, the rope is connected to the platform. 38 00:02:24,800 --> 00:02:27,640 So the next stages will also consider 39 00:02:27,640 --> 00:02:32,220 a system consisting of pulley A, person, and the platform, 40 00:02:32,220 --> 00:02:33,760 and the washer. 41 00:02:33,760 --> 00:02:36,000 Now let's draw the free body diagram. 42 00:02:36,000 --> 00:02:41,400 Let's begin by drawing the free body diagram on the washer. 43 00:02:41,400 --> 00:02:45,540 So what do we have on the washer? 44 00:02:45,540 --> 00:02:48,500 The first thing to think about is the string. 45 00:02:48,500 --> 00:02:51,530 The washer is pulling the string down. 46 00:02:51,530 --> 00:02:54,710 So the string is pulling the washer up. 47 00:02:54,710 --> 00:02:59,710 So that's a force of string 1 on the washer. 48 00:02:59,710 --> 00:03:05,650 Now, there's also the gravitational force m washer g. 49 00:03:05,650 --> 00:03:07,460 And what we also have to consider the fact 50 00:03:07,460 --> 00:03:10,750 is that the person is sitting on the platform. 51 00:03:10,750 --> 00:03:13,900 So the platform is pushing the person up. 52 00:03:13,900 --> 00:03:17,600 And we'll call that a normal force on the washer 53 00:03:17,600 --> 00:03:19,600 due to the platform. 54 00:03:19,600 --> 00:03:23,870 And those are the free body diagram for the body diagram 55 00:03:23,870 --> 00:03:24,930 on the washer. 56 00:03:24,930 --> 00:03:27,610 Now let's focus on the platform. 57 00:03:27,610 --> 00:03:29,270 So here, we'll draw the platform. 58 00:03:32,070 --> 00:03:34,390 And now let's look at the forces on the platform. 59 00:03:34,390 --> 00:03:38,030 Let's begin by looking for the internal forces, the Newton's 60 00:03:38,030 --> 00:03:40,340 third law pairs. 61 00:03:40,340 --> 00:03:42,450 The platform is pushing the person up. 62 00:03:42,450 --> 00:03:45,200 The person is pushing the platform down. 63 00:03:45,200 --> 00:03:49,130 So we'll write that force as N on the platform 64 00:03:49,130 --> 00:03:50,329 due to the washer. 65 00:03:50,329 --> 00:03:55,980 And immediately, let's just circle this third law pair. 66 00:03:55,980 --> 00:04:00,920 Now, string 2 is pulling the platform up. 67 00:04:00,920 --> 00:04:04,000 So let's draw that force. 68 00:04:04,000 --> 00:04:06,630 We'll call that a tension force in the string. 69 00:04:06,630 --> 00:04:09,850 It's on the platform due to string 2. 70 00:04:09,850 --> 00:04:12,930 And finally, we have the gravitational force 71 00:04:12,930 --> 00:04:14,620 on the platform. 72 00:04:14,620 --> 00:04:17,940 And that's our free body diagram on the platform. 73 00:04:17,940 --> 00:04:20,880 Now, you may have said, well, why should I separate these 74 00:04:20,880 --> 00:04:21,380 out? 75 00:04:21,380 --> 00:04:24,790 Why didn't I just use the person and the platform? 76 00:04:24,790 --> 00:04:26,680 So let's draw that picture. 77 00:04:26,680 --> 00:04:30,630 So now imagine underneath this is a system consisting 78 00:04:30,630 --> 00:04:34,440 of the person and the platform. 79 00:04:34,440 --> 00:04:39,120 And I'll just draw that system like that. 80 00:04:39,120 --> 00:04:41,150 So what we're doing is we're taking 81 00:04:41,150 --> 00:04:43,850 these two separate free body diagrams 82 00:04:43,850 --> 00:04:45,980 and we're going to combine them here. 83 00:04:45,980 --> 00:04:48,760 And by Newton's third law, all internal forces 84 00:04:48,760 --> 00:04:50,550 should cancel in pairs. 85 00:04:50,550 --> 00:04:52,920 So now let's separately think about the forces 86 00:04:52,920 --> 00:04:54,470 and see that that's the case. 87 00:04:54,470 --> 00:04:56,420 Well, we have the gravitational force 88 00:04:56,420 --> 00:04:59,570 on the system, which is the mass of the platform 89 00:04:59,570 --> 00:05:03,480 plus the mass of the washer times g. 90 00:05:03,480 --> 00:05:08,180 We still have the string pulling the person up 91 00:05:08,180 --> 00:05:10,950 because the person is pulling the string down. 92 00:05:10,950 --> 00:05:18,030 So we still have the force F1 on the washer. 93 00:05:18,030 --> 00:05:20,100 That's string 1 on the washer. 94 00:05:20,100 --> 00:05:24,830 And we still have the pulley, the tension in string 2, 95 00:05:24,830 --> 00:05:26,040 pulling it up. 96 00:05:26,040 --> 00:05:32,150 So we still have the force T2 on the platform. 97 00:05:32,150 --> 00:05:35,480 Now, when you look at this, what we're doing is 98 00:05:35,480 --> 00:05:40,530 we're adding these two free body diagrams together. 99 00:05:40,530 --> 00:05:44,190 The internal forces now are the normal force. 100 00:05:44,190 --> 00:05:47,810 They're equal in magnitude, opposite in direction. 101 00:05:47,810 --> 00:05:49,909 So when you add them together, they cancel. 102 00:05:49,909 --> 00:05:55,100 And we're just left with that, with that, with that, 103 00:05:55,100 --> 00:05:56,590 and with that. 104 00:05:56,590 --> 00:06:00,080 And so this is now the combined system. 105 00:06:00,080 --> 00:06:04,180 Now you might ask, why did we not include the pulley? 106 00:06:04,180 --> 00:06:06,330 Well, let's take a look at that. 107 00:06:06,330 --> 00:06:10,680 So I'm going to draw the free body diagram just on pulley 108 00:06:10,680 --> 00:06:13,740 A. So let's draw pulley A. 109 00:06:13,740 --> 00:06:17,450 Now what we have here is the string on both sides 110 00:06:17,450 --> 00:06:20,200 is pulling pulley A up. 111 00:06:20,200 --> 00:06:24,180 And that's the tension in string 1. 112 00:06:24,180 --> 00:06:29,660 So what we have is-- I'm going to call that tension in string 113 00:06:29,660 --> 00:06:32,890 1, tension in string 1. 114 00:06:32,890 --> 00:06:38,840 And just to alert you that keep in mind that this force here 115 00:06:38,840 --> 00:06:40,970 is the force of the string on the person 116 00:06:40,970 --> 00:06:45,810 and this too is also tension in the string, 117 00:06:45,810 --> 00:06:52,140 because this is our assumption of a massless string. 118 00:06:52,140 --> 00:06:58,220 So notice that everywhere in the string, the tension is uniform. 119 00:06:58,220 --> 00:07:00,620 So I'm just going to simplify that by calling it T1. 120 00:07:00,620 --> 00:07:02,450 What are the other forces on the pulley? 121 00:07:02,450 --> 00:07:06,210 Well, we're assuming that these pulleys are massless. 122 00:07:06,210 --> 00:07:08,880 And so there's no gravitational force on the pulley. 123 00:07:08,880 --> 00:07:15,520 And the only thing we have is the string pulling-- 124 00:07:15,520 --> 00:07:17,560 is the tension in the string. 125 00:07:17,560 --> 00:07:21,280 So now this is a little bit different. 126 00:07:21,280 --> 00:07:25,050 This is a force on the pulley too. 127 00:07:25,050 --> 00:07:29,210 So at the moment, let's do something a little bit 128 00:07:29,210 --> 00:07:30,490 different. 129 00:07:30,490 --> 00:07:36,620 Let's consider our system to be the string. 130 00:07:36,620 --> 00:07:41,550 So it's pulley A. We call that string 2. 131 00:07:41,550 --> 00:07:43,827 That's our system. 132 00:07:43,827 --> 00:07:45,159 So I modified that a little bit. 133 00:07:45,159 --> 00:07:47,060 I just didn't consider the pulley separately. 134 00:07:47,060 --> 00:07:50,210 I considered the pulley and the string as the system. 135 00:07:50,210 --> 00:07:55,790 Then here the string is pulling the platform up. 136 00:07:55,790 --> 00:08:02,030 The platform therefore is pulling the string down. 137 00:08:02,030 --> 00:08:07,670 And once again, we have a third law pair. 138 00:08:07,670 --> 00:08:13,820 And so if I added these two together, 139 00:08:13,820 --> 00:08:18,630 then what I now have-- and this is why this problem is kind 140 00:08:18,630 --> 00:08:29,190 of complex-- we have pulley A, string 2, platform P 141 00:08:29,190 --> 00:08:35,880 and washer person. 142 00:08:35,880 --> 00:08:41,808 And if we now add these two systems together, 143 00:08:41,808 --> 00:08:44,720 we have this complicated system. 144 00:08:44,720 --> 00:08:46,950 But what are the forces in this system? 145 00:08:46,950 --> 00:08:51,550 Well, the rope is pulling it up. 146 00:08:51,550 --> 00:08:58,780 The person was-- remember we had this force, W1, 147 00:08:58,780 --> 00:09:01,360 was the force of string 1 on the washer. 148 00:09:01,360 --> 00:09:04,600 That also was the tension everywhere in the string. 149 00:09:04,600 --> 00:09:08,580 So we have another T1 up. 150 00:09:08,580 --> 00:09:11,850 These two forces now cancel in pairs, 151 00:09:11,850 --> 00:09:14,160 the internal forces there. 152 00:09:14,160 --> 00:09:18,090 And so down, we just have mass platform plus mass 153 00:09:18,090 --> 00:09:21,980 of a washer times g. 154 00:09:21,980 --> 00:09:24,110 And so you see in this problem, if we 155 00:09:24,110 --> 00:09:27,310 tried to treat everything separate-- 156 00:09:27,310 --> 00:09:28,810 and I could have even had the string 157 00:09:28,810 --> 00:09:32,060 separate-- I have a lot of free body diagram. 158 00:09:32,060 --> 00:09:35,590 But when I think about what's internal and what's external, 159 00:09:35,590 --> 00:09:39,550 I can take these two pieces, combine them here, 160 00:09:39,550 --> 00:09:41,820 internal forces cancel in pairs. 161 00:09:41,820 --> 00:09:46,470 I can draw these two separate systems, again, combine them. 162 00:09:46,470 --> 00:09:48,420 Internal forces cancel in pair. 163 00:09:48,420 --> 00:09:52,870 And now I have this pulley A. 164 00:09:52,870 --> 00:09:56,510 Now I can write down Newton's second law. 165 00:09:56,510 --> 00:09:59,290 So what I'll do next is I'll introduce-- 166 00:09:59,290 --> 00:10:03,510 I still have to consider pulley B. I'll use this as my system. 167 00:10:03,510 --> 00:10:05,380 And I'll write down Newton's second law. 168 00:10:05,380 --> 00:10:07,692 And we'll be able to solve this problem.