1 00:00:03,500 --> 00:00:05,780 When we're looking at polar coordinates, 2 00:00:05,780 --> 00:00:09,140 one of the important issues is to understand the unit vectors. 3 00:00:09,140 --> 00:00:12,290 Let's describe our coordinate system, again. 4 00:00:12,290 --> 00:00:15,860 We have a point where there is an object. 5 00:00:15,860 --> 00:00:20,080 And at this point, we have a pair of unit vectors, r hat 6 00:00:20,080 --> 00:00:22,240 and theta hat. 7 00:00:22,240 --> 00:00:24,800 Now those unit vectors will change, depending 8 00:00:24,800 --> 00:00:26,180 on where you are in space. 9 00:00:26,180 --> 00:00:27,990 We now want to address the question, 10 00:00:27,990 --> 00:00:30,530 how do I compare polar coordinates 11 00:00:30,530 --> 00:00:32,310 and Cartesian coordinates. 12 00:00:32,310 --> 00:00:34,760 In Cartesian coordinates, at this point 13 00:00:34,760 --> 00:00:40,360 here, we would have-- let's say we choose a Cartesian plus x 14 00:00:40,360 --> 00:00:45,950 and plus y, then we would have a unit vector i hat and j hat. 15 00:00:45,950 --> 00:00:48,390 And how are these vectors related? 16 00:00:48,390 --> 00:00:53,190 Remember our angle theta, so we have the angle theta here 17 00:00:53,190 --> 00:00:54,930 and the angle theta there. 18 00:00:54,930 --> 00:00:57,990 And now I would like to apply a simple vector decomposition 19 00:00:57,990 --> 00:01:01,510 to r hat and theta hat and express each of these unit 20 00:01:01,510 --> 00:01:05,432 vectors in terms of the unit vectors i hat and j hat. 21 00:01:05,432 --> 00:01:07,370 Let's begin with r hat. 22 00:01:07,370 --> 00:01:09,690 As you can see in the diagram, r hat 23 00:01:09,690 --> 00:01:13,730 has a horizontal component and a vertical component. 24 00:01:13,730 --> 00:01:17,330 So what we have is r hat. 25 00:01:17,330 --> 00:01:19,370 It's a unit vector, so its length is 1. 26 00:01:19,370 --> 00:01:22,340 Its horizontal component is adjacent to the angle, 27 00:01:22,340 --> 00:01:28,020 so that's cosine of theta i hat plus sine of theta j hat. 28 00:01:28,020 --> 00:01:30,740 The vertical component is opposite the angle. 29 00:01:30,740 --> 00:01:34,520 In a similar fashion, theta hat-- well, theta hat 30 00:01:34,520 --> 00:01:39,780 has a component in the negative i hat direction, 31 00:01:39,780 --> 00:01:42,240 which is opposite the angle. 32 00:01:42,240 --> 00:01:45,060 And it has a component in the positive j hat direction, 33 00:01:45,060 --> 00:01:46,690 which is adjacent to the angle. 34 00:01:46,690 --> 00:01:56,400 So we have minus sine theta i hat plus cosine theta j hat. 35 00:01:56,400 --> 00:01:59,539 And that's how we can decompose our unit vectors r 36 00:01:59,539 --> 00:02:03,810 hat and theta hat in terms of Cartesian coordinates. 37 00:02:03,810 --> 00:02:06,590 Now why is this significant? 38 00:02:06,590 --> 00:02:10,720 Because if we're describing the motion of an object, 39 00:02:10,720 --> 00:02:13,560 for instance, an object that's going around a circle, 40 00:02:13,560 --> 00:02:19,130 then our polar coordinate theta is a function of time. 41 00:02:19,130 --> 00:02:23,450 And so these unit vectors are actually changing in direction. 42 00:02:23,450 --> 00:02:24,480 You saw that before. 43 00:02:24,480 --> 00:02:29,340 Over here, r hat and theta hat point in different directions. 44 00:02:29,340 --> 00:02:34,950 So what we actually have as functions of time is r hat of t 45 00:02:34,950 --> 00:02:38,760 equals cosine theta of t i hat. 46 00:02:38,760 --> 00:02:40,970 Now the unit vectors don't change 47 00:02:40,970 --> 00:02:42,020 in Cartesian coordinates. 48 00:02:42,020 --> 00:02:45,820 At every single point, you have the same Cartesian unit 49 00:02:45,820 --> 00:02:47,829 vectors. 50 00:02:47,829 --> 00:02:51,992 And so this vector is time dependent. 51 00:02:54,670 --> 00:02:58,440 Now the significance of that is our first important vector 52 00:02:58,440 --> 00:03:02,690 in kinematics is the position vector. 53 00:03:02,690 --> 00:03:04,260 The position vector is a vector that 54 00:03:04,260 --> 00:03:06,940 goes from the origin to where the object is. 55 00:03:06,940 --> 00:03:09,590 We'll call that r of t. 56 00:03:09,590 --> 00:03:17,840 So this position vector r of t can be expressed as a length r. 57 00:03:17,840 --> 00:03:21,120 And its direction is in the r hat direction, 58 00:03:21,120 --> 00:03:23,500 which is a function of time. 59 00:03:23,500 --> 00:03:27,980 So we have r cosine theta of t i hat 60 00:03:27,980 --> 00:03:32,610 plus r sine theta of t j hat. 61 00:03:32,610 --> 00:03:37,250 Now we can now define the velocity of this object 62 00:03:37,250 --> 00:03:41,329 where the velocity is the derivative of the position 63 00:03:41,329 --> 00:03:42,740 vector. 64 00:03:42,740 --> 00:03:46,660 When you differentiate, remember, r is a constant, 65 00:03:46,660 --> 00:03:48,640 so we get r. 66 00:03:48,640 --> 00:03:50,920 Now what is the derivative with respect 67 00:03:50,920 --> 00:03:53,720 to time of cosine theta t. 68 00:03:53,720 --> 00:03:57,040 Because the argument of theta is a function of t, 69 00:03:57,040 --> 00:03:58,940 we need to use the chain rule. 70 00:03:58,940 --> 00:04:06,220 So the derivative is minus sine theta of t, d theta dt i hat. 71 00:04:06,220 --> 00:04:11,260 And the derivative of the sine is cosine theta 72 00:04:11,260 --> 00:04:16,670 of t d theta dt j hat. 73 00:04:16,670 --> 00:04:22,040 Now notice that I can pull out the common term d theta dt. 74 00:04:22,040 --> 00:04:25,440 So I have r d theta dt. 75 00:04:25,440 --> 00:04:30,640 And I have minus sine theta of t i hat plus cosine 76 00:04:30,640 --> 00:04:33,909 theta of t j hat. 77 00:04:33,909 --> 00:04:38,240 And if you'll notice, this is exactly the unit vector theta 78 00:04:38,240 --> 00:04:39,130 hat. 79 00:04:39,130 --> 00:04:42,110 So we can write our velocity vector 80 00:04:42,110 --> 00:04:50,030 for this object that's moving in a circle as r d theta dt theta 81 00:04:50,030 --> 00:04:52,320 hat. 82 00:04:52,320 --> 00:04:54,130 When we write a vector like this, 83 00:04:54,130 --> 00:04:57,100 it's pointing tangentially, the theta hat direction, 84 00:04:57,100 --> 00:04:58,430 and this part is the component. 85 00:05:01,140 --> 00:05:05,250 So often we can use a notation v theta theta 86 00:05:05,250 --> 00:05:11,340 hat, where v theta is the component r d theta dt. 87 00:05:11,340 --> 00:05:15,250 Now this component can be positive or negative or 0. 88 00:05:15,250 --> 00:05:21,510 For example, if d theta dt is positive, what does that mean? 89 00:05:21,510 --> 00:05:23,140 That means that our angle theta is 90 00:05:23,140 --> 00:05:26,810 increasing so the object is moving the way I indicate 91 00:05:26,810 --> 00:05:29,090 with my finger. 92 00:05:29,090 --> 00:05:35,240 If d theta dt is 0, then the angle is not changing, 93 00:05:35,240 --> 00:05:37,460 so the object is at rest. 94 00:05:37,460 --> 00:05:42,200 And finally, if d theta dt is negative, 95 00:05:42,200 --> 00:05:44,520 then the angle theta is decreasing, 96 00:05:44,520 --> 00:05:48,870 and so the object is moving in this direction. 97 00:05:48,870 --> 00:05:53,720 So this is our velocity for a circular motion expressed 98 00:05:53,720 --> 00:05:55,790 in polar coordinates.