1 00:00:03,830 --> 00:00:07,280 Now that we've calculated the change in potential energy 2 00:00:07,280 --> 00:00:11,120 between some initial and final heights 3 00:00:11,120 --> 00:00:18,080 for the gravitational problem, mg of y final minus y initial. 4 00:00:18,080 --> 00:00:23,240 For this conservative force of gravity, 5 00:00:23,240 --> 00:00:25,460 and we had our coordinate system like that, 6 00:00:25,460 --> 00:00:28,890 we were able to calculate the change in potential energy. 7 00:00:28,890 --> 00:00:34,970 And remember our theorem is that non-conservative work equals 8 00:00:34,970 --> 00:00:38,240 Delta K plus Delta U. 9 00:00:38,240 --> 00:00:40,250 Now what we'd like to do is establish 10 00:00:40,250 --> 00:00:44,540 the concept of a reference point for potential energy. 11 00:00:44,540 --> 00:00:47,240 And we'll do that as follows, see 12 00:00:47,240 --> 00:00:50,480 the change in potential energy only depended 13 00:00:50,480 --> 00:00:56,690 on say, our initial state and our final state. 14 00:00:56,690 --> 00:00:59,030 What we'd like to do is introduce the concept 15 00:00:59,030 --> 00:01:00,380 of a reference point. 16 00:01:00,380 --> 00:01:08,520 So let's identify some point Yp to be our reference point. 17 00:01:08,520 --> 00:01:17,180 And we'll define a potential Yp to be the reference potential. 18 00:01:17,180 --> 00:01:20,660 And if we want to talk about the potential energy 19 00:01:20,660 --> 00:01:24,289 in a final state, we'll always refer it 20 00:01:24,289 --> 00:01:28,710 to the difference between that and the reference point. 21 00:01:28,710 --> 00:01:32,810 So this is Delta U between the final state and the reference 22 00:01:32,810 --> 00:01:33,890 point. 23 00:01:33,890 --> 00:01:36,920 Likewise, for the initial state, we'll 24 00:01:36,920 --> 00:01:40,970 always refer that with respect to our reference point. 25 00:01:40,970 --> 00:01:44,390 So any state that we have, we can always 26 00:01:44,390 --> 00:01:49,130 refer the potential energy difference between some state 27 00:01:49,130 --> 00:01:50,570 and some reference point. 28 00:01:50,570 --> 00:01:51,890 Why do we do this? 29 00:01:51,890 --> 00:01:59,000 Because notice that if we look at U final minus U reference 30 00:01:59,000 --> 00:02:05,840 point, and we subtract from that U initial minus U reference 31 00:02:05,840 --> 00:02:10,550 point, then the difference-- the reference 32 00:02:10,550 --> 00:02:12,980 points here we have a minus, here we have a plus-- 33 00:02:12,980 --> 00:02:16,190 this is just equal to U final minus U 34 00:02:16,190 --> 00:02:19,310 initial, which is Delta U. 35 00:02:19,310 --> 00:02:23,630 So the change in potential energy between any two states 36 00:02:23,630 --> 00:02:27,530 is independent of how we choose our reference potential. 37 00:02:27,530 --> 00:02:30,470 But it can make calculations easier 38 00:02:30,470 --> 00:02:32,960 when we can identify what the potential energy is 39 00:02:32,960 --> 00:02:33,800 for a little state. 40 00:02:33,800 --> 00:02:36,290 Now let's look at our example. 41 00:02:36,290 --> 00:02:38,630 So for our gravitational problem we 42 00:02:38,630 --> 00:02:43,550 will choose y reference point to be 0. 43 00:02:43,550 --> 00:02:49,190 And we'll choose the potential energy at this reference point 44 00:02:49,190 --> 00:02:50,300 also to be 0. 45 00:02:50,300 --> 00:02:54,260 So our reference potential at the origin is 0, 46 00:02:54,260 --> 00:02:56,720 and I'll denote it like that. 47 00:02:56,720 --> 00:03:01,940 Then the potential energy at some initial state 48 00:03:01,940 --> 00:03:04,310 minus the reference point-- well, 49 00:03:04,310 --> 00:03:07,670 we can use our formula here, because this 50 00:03:07,670 --> 00:03:10,380 is between any two states. 51 00:03:10,380 --> 00:03:17,240 So this is mg y initial minus the reference point. 52 00:03:17,240 --> 00:03:20,150 But our reference point was 0, and so we 53 00:03:20,150 --> 00:03:25,040 see that U initial minus y reference point, which was also 54 00:03:25,040 --> 00:03:29,700 0, is just equal to mg Yi. 55 00:03:29,700 --> 00:03:32,540 And so we have this statement that the potential energy 56 00:03:32,540 --> 00:03:38,660 difference between our initial state and the reference point 57 00:03:38,660 --> 00:03:43,230 is just mg where Yi is the height 58 00:03:43,230 --> 00:03:46,270 that the initial state is above the reference point. 59 00:03:46,270 --> 00:03:51,890 In a similar way, we have U final is mg y final. 60 00:03:51,890 --> 00:03:54,860 And so we see we recover what we expect. 61 00:03:54,860 --> 00:04:00,740 This is just mg y final minus y initial. 62 00:04:00,740 --> 00:04:03,890 Now this we can generalize just a little bit 63 00:04:03,890 --> 00:04:09,590 by saying that for any-- let's write 64 00:04:09,590 --> 00:04:18,769 that for us our mass, which is for any height y 65 00:04:18,769 --> 00:04:21,649 our potential energy function for the gravitational force 66 00:04:21,649 --> 00:04:25,370 U(y) is equal to mg y. 67 00:04:25,370 --> 00:04:28,400 That's a formula that many of you have seen before. 68 00:04:28,400 --> 00:04:33,650 But it's very important to note that with this formula, U of 0 69 00:04:33,650 --> 00:04:36,780 equals 0, because that's our reference point. 70 00:04:36,780 --> 00:04:41,400 And that becomes our potential energy function 71 00:04:41,400 --> 00:04:43,860 for the gravitational force. 72 00:04:43,860 --> 00:04:47,630 Now our next step will be to do the same thing 73 00:04:47,630 --> 00:04:52,250 for spring forces and inverse square gravitational forces. 74 00:04:52,250 --> 00:04:56,162 And we'll also look at graphical analysis of this function.