1 00:00:03,847 --> 00:00:05,680 Let's consider our one-dimensional collision 2 00:00:05,680 --> 00:00:10,420 again, object 1 moving with velocity V1 initial, 3 00:00:10,420 --> 00:00:14,740 and object 2 moving with V2 initial. 4 00:00:14,740 --> 00:00:17,150 Let's call this or i hat direction. 5 00:00:17,150 --> 00:00:21,610 And this is our initial state. 6 00:00:21,610 --> 00:00:30,140 And our final state after the collision, we have object 1. 7 00:00:30,140 --> 00:00:35,170 We'll say it's moving this, V1 final, and object 2 moving 8 00:00:35,170 --> 00:00:37,630 that way, V2 final. 9 00:00:37,630 --> 00:00:43,240 Now recall our principle of impulse and momentum. 10 00:00:43,240 --> 00:00:48,240 We said that if there is an external force 11 00:00:48,240 --> 00:00:53,220 during the time of a collision delta t, then physically that 12 00:00:53,220 --> 00:00:58,260 will cause the momentum of the system final 13 00:00:58,260 --> 00:01:02,130 minus the momentum of the system initial. 14 00:01:02,130 --> 00:01:07,380 Now when we do this analysis, this side was a description 15 00:01:07,380 --> 00:01:10,720 and this side is physics. 16 00:01:10,720 --> 00:01:12,539 Now for our one-dimensional collision, 17 00:01:12,539 --> 00:01:14,580 we need to look at this collision 18 00:01:14,580 --> 00:01:17,370 and ask ourselves are there any external forces 19 00:01:17,370 --> 00:01:21,640 acting on the system, which is consisting of particle 1 20 00:01:21,640 --> 00:01:23,070 and particle 2? 21 00:01:23,070 --> 00:01:25,560 So what we're going to identify here 22 00:01:25,560 --> 00:01:29,789 is that the surface is frictionless. 23 00:01:29,789 --> 00:01:32,340 And we'll ignore all air resistance. 24 00:01:32,340 --> 00:01:42,090 And so by our assumptions that there are no f external is 0. 25 00:01:42,090 --> 00:01:49,780 And therefore, the momentum of the system remains constant. 26 00:01:49,780 --> 00:01:53,370 So here our statement is-- many people call this conservation 27 00:01:53,370 --> 00:01:56,880 of momentum, but we're saying in this example based 28 00:01:56,880 --> 00:02:03,760 on our assumptions that the momentum of the system 29 00:02:03,760 --> 00:02:04,436 is constant. 30 00:02:07,172 --> 00:02:10,780 Now how do we actually write that down? 31 00:02:10,780 --> 00:02:15,250 Well, let's now write it first as vector expressions. 32 00:02:15,250 --> 00:02:23,890 So we have the initial momentum, V1 of the system, m1 m2 V2 33 00:02:23,890 --> 00:02:29,100 initial is equal to the final momentum of the system, 34 00:02:29,100 --> 00:02:34,630 V1 final plus m2 V2 final. 35 00:02:34,630 --> 00:02:38,320 Now, how do we represent these equations? 36 00:02:38,320 --> 00:02:41,020 Well, you could treat them as vectors if you wanted. 37 00:02:41,020 --> 00:02:44,620 But what we're going to do is express them as components. 38 00:02:44,620 --> 00:02:46,780 So if we wrote this as components, 39 00:02:46,780 --> 00:02:55,450 we would have m1 Vx initial i hat plus m2 V2 x initial i hat 40 00:02:55,450 --> 00:03:06,670 equals m1 V1 s final i hat plus m2 V2 x final i hat. 41 00:03:06,670 --> 00:03:09,310 So that's the vector expression expressed 42 00:03:09,310 --> 00:03:10,750 in terms of components. 43 00:03:10,750 --> 00:03:12,940 The advantage of this is that we really 44 00:03:12,940 --> 00:03:16,120 don't know the signs of these two final components. 45 00:03:16,120 --> 00:03:18,100 That's our target quantities. 46 00:03:18,100 --> 00:03:20,200 But we could just write this equation-- 47 00:03:20,200 --> 00:03:22,340 instead of writing it as a vector equation, 48 00:03:22,340 --> 00:03:28,250 let's just now write this as a component equation. 49 00:03:28,250 --> 00:03:31,000 And when we write this equation in terms of components, 50 00:03:31,000 --> 00:03:43,660 we have m1 V1 x initial plus m2 V2 x initial equals m1 V1 x 51 00:03:43,660 --> 00:03:49,540 final plus m2 V2 x final. 52 00:03:49,540 --> 00:03:53,530 And this equation here is the equation 53 00:03:53,530 --> 00:03:56,590 that we use to express the constancy 54 00:03:56,590 --> 00:03:58,420 of the momentum of the system. 55 00:03:58,420 --> 00:04:00,740 We'll call this equation 1. 56 00:04:00,740 --> 00:04:02,620 Now our next approach is to ask are there 57 00:04:02,620 --> 00:04:06,600 any other quantities in the system which are constant?