1 00:00:00,201 --> 00:00:00,700 Good. 2 00:00:00,700 --> 00:00:03,880 So let's do, then, our transitions. 3 00:00:03,880 --> 00:00:06,160 So we do the constant perturbation. 4 00:00:11,930 --> 00:00:15,200 Constant perturbation. 5 00:00:20,740 --> 00:00:25,300 So as we said, delta H is equal to V, 6 00:00:25,300 --> 00:00:27,130 and it's time independent. 7 00:00:27,130 --> 00:00:28,900 It just begins at time 0. 8 00:00:31,780 --> 00:00:37,360 And we'll examine what's going on by time t0. 9 00:00:37,360 --> 00:00:40,680 So what are we going to do? 10 00:00:40,680 --> 00:00:46,720 We're going to examine a transition 11 00:00:46,720 --> 00:00:52,210 to go from some initial state i, initial state, 12 00:00:52,210 --> 00:00:56,110 to a final state f. 13 00:00:56,110 --> 00:00:59,980 So we don't have to say much about what the Hamiltonian is 14 00:00:59,980 --> 00:01:01,330 or anything. 15 00:01:01,330 --> 00:01:03,910 For us, V is going to have a constant. 16 00:01:03,910 --> 00:01:06,280 It's going to have some matrix elements 17 00:01:06,280 --> 00:01:09,570 that once we do an example you can calculate, 18 00:01:09,570 --> 00:01:14,530 but for the time being we need not know too much. 19 00:01:14,530 --> 00:01:18,940 So I'm going to use the key formula 20 00:01:18,940 --> 00:01:24,040 that was derived already about perturbation theory 21 00:01:24,040 --> 00:01:27,800 and how you get the transition amplitude. 22 00:01:27,800 --> 00:01:35,060 So we know that the coefficient c associated to the m state 23 00:01:35,060 --> 00:01:37,810 to first order in perturbation theory 24 00:01:37,810 --> 00:01:47,410 at that time t0 can be computed as a sum over all n integral 25 00:01:47,410 --> 00:02:00,580 from 0 to t0 e to the i omega mn t prime delta Hmn t prime 26 00:02:00,580 --> 00:02:07,900 over ih bar Cn 0 dt prime. 27 00:02:07,900 --> 00:02:10,940 So let me just say a few words. 28 00:02:10,940 --> 00:02:16,800 You may have seen this yesterday in recitation. 29 00:02:16,800 --> 00:02:18,030 Here it is. 30 00:02:18,030 --> 00:02:23,970 The state has described in this usual language 31 00:02:23,970 --> 00:02:35,020 of psi tilde of t was described as a sum of c ms of ts ms. 32 00:02:35,020 --> 00:02:38,980 And we calculate those in perturbation theory. 33 00:02:38,980 --> 00:02:43,950 So Cn's, we know them at time equals 0, 34 00:02:43,950 --> 00:02:45,960 we imagine we know the initial state 35 00:02:45,960 --> 00:02:47,490 and we want to calculate them later. 36 00:02:47,490 --> 00:02:50,700 Well, the first order in perturbation theory, 37 00:02:50,700 --> 00:02:54,000 the Cn's are called Cn's 1's. 38 00:02:54,000 --> 00:02:55,740 And they're given by this formula. 39 00:02:55,740 --> 00:02:57,570 First order in perturbation theory, 40 00:02:57,570 --> 00:03:00,210 because we have a single delta H, 41 00:03:00,210 --> 00:03:04,230 this omega mn is the energy of m minus the energy 42 00:03:04,230 --> 00:03:07,037 of n over h bar. 43 00:03:07,037 --> 00:03:07,620 And that's it. 44 00:03:07,620 --> 00:03:09,105 Those are all our symbols. 45 00:03:12,260 --> 00:03:14,460 So what do we have to do now? 46 00:03:14,460 --> 00:03:20,490 We have a transition from some initial state to a final state. 47 00:03:20,490 --> 00:03:22,980 So what does that mean? 48 00:03:22,980 --> 00:03:31,910 It means that Cn 0, it only exists when 49 00:03:31,910 --> 00:03:34,320 n represents the initial state. 50 00:03:34,320 --> 00:03:38,700 So I'll just write delta ni. 51 00:03:38,700 --> 00:03:50,790 At time equals zero, system is in the state i. 52 00:03:50,790 --> 00:03:56,670 And at time t0, we're asking for the probability 53 00:03:56,670 --> 00:03:58,510 to go into final state. 54 00:03:58,510 --> 00:04:03,600 So instead of using n and m, we're just using f and i. 55 00:04:03,600 --> 00:04:09,540 And therefore, we'll have m equal f. 56 00:04:09,540 --> 00:04:12,900 With these two facts, the formula 57 00:04:12,900 --> 00:04:18,959 becomes cf the amplitude to first order in perturbation 58 00:04:18,959 --> 00:04:27,060 theory to be in the state f at time t0 is the sum is gone, 59 00:04:27,060 --> 00:04:31,050 sum over n just applies for n equals i. 60 00:04:31,050 --> 00:04:34,240 So i will go here. 61 00:04:34,240 --> 00:04:41,670 We'll have one over ih bar 0 to t0 e 62 00:04:41,670 --> 00:04:45,490 to the i omega final state to initial state. 63 00:04:45,490 --> 00:04:54,900 That's m and n t prime Vfi, because the delta H is V, 64 00:04:54,900 --> 00:04:58,350 and we're going from initial to final. 65 00:04:58,350 --> 00:05:02,430 So fi here. 66 00:05:02,430 --> 00:05:06,150 And then the t prime. 67 00:05:06,150 --> 00:05:07,240 It's all gone. 68 00:05:07,240 --> 00:05:10,710 It's all become very simple, though. 69 00:05:10,710 --> 00:05:14,370 You would say too simple. 70 00:05:14,370 --> 00:05:17,270 We have this is time independent, 71 00:05:17,270 --> 00:05:19,050 so it goes out of the interval. 72 00:05:19,050 --> 00:05:22,770 So we just have the interval of an exponential here. 73 00:05:22,770 --> 00:05:26,390 That's very, very easy. 74 00:05:26,390 --> 00:05:31,910 What is Vfi case vi? 75 00:05:35,030 --> 00:05:35,530 So 76 00:05:35,530 --> 00:05:40,930 This goes out, and we just have to integrate this function. 77 00:05:43,960 --> 00:05:49,600 I'll write it in a way that is simpler. 78 00:05:49,600 --> 00:05:51,070 Maybe you skip a line. 79 00:05:51,070 --> 00:05:54,580 I don't want to just count the factors of is 80 00:05:54,580 --> 00:05:55,870 and doing the integral. 81 00:05:55,870 --> 00:05:59,260 When you integrate this, you get another exponential. 82 00:05:59,260 --> 00:06:01,480 You're going to get the exponential at t0 83 00:06:01,480 --> 00:06:04,700 minus the exponential at zero. 84 00:06:04,700 --> 00:06:08,020 All right, so we don't want to do our integral. 85 00:06:08,020 --> 00:06:10,080 So I'll just write the answer. 86 00:06:10,080 --> 00:06:12,790 I was saying we get an exponential here 87 00:06:12,790 --> 00:06:16,630 at t0 minus the value at zero, then 88 00:06:16,630 --> 00:06:21,490 you take half of the exponential out the form a sign. 89 00:06:21,490 --> 00:06:26,560 This are simple matters, so I will not do the integral here. 90 00:06:26,560 --> 00:06:34,690 You get Vfi over Ef minus Ei e to the i omega 91 00:06:34,690 --> 00:06:44,560 fi t0 two minus two i sine of omega fi t0 over two. 92 00:06:49,390 --> 00:06:50,530 You can believe that. 93 00:06:50,530 --> 00:06:53,560 I think you can believe the sine, 94 00:06:53,560 --> 00:07:01,230 and I have everything here. 95 00:07:01,230 --> 00:07:08,550 The h bar helped turn the omega fi into Ef minus Ei. 96 00:07:08,550 --> 00:07:20,460 So we can now compute the transition probability 97 00:07:20,460 --> 00:07:22,950 to go from the initial to the final stage. 98 00:07:22,950 --> 00:07:26,480 So we'll write it like this. 99 00:07:26,480 --> 00:07:31,100 I to f-- it's a little funny. 100 00:07:31,100 --> 00:07:31,980 I don't know. 101 00:07:31,980 --> 00:07:33,930 You can write it whichever way you want. 102 00:07:33,930 --> 00:07:35,520 Some people like it like that. 103 00:07:35,520 --> 00:07:39,150 I'm going to do it in the sense that the initial state always 104 00:07:39,150 --> 00:07:42,680 appears as a cat, the final state as a bra. 105 00:07:42,680 --> 00:07:45,480 So you draw the arrow like that, more or less 106 00:07:45,480 --> 00:07:48,340 to keep the sense of order in your brain. 107 00:07:48,340 --> 00:07:50,190 But if it doesn't help you, write it 108 00:07:50,190 --> 00:07:52,320 whichever way you want. 109 00:07:52,320 --> 00:08:03,300 Pfi at t0 one is the norm squared 110 00:08:03,300 --> 00:08:06,570 of this coefficient, cf one. 111 00:08:06,570 --> 00:08:09,870 The probability to be found in the final state 112 00:08:09,870 --> 00:08:12,970 has to do with the norm squared of this thing. 113 00:08:12,970 --> 00:08:23,070 So it's this that's part of what was reviewed yesterday squared. 114 00:08:26,890 --> 00:08:28,020 So what do we get? 115 00:08:28,020 --> 00:08:30,000 That simplifies quite a bit. 116 00:08:30,000 --> 00:08:38,970 We get Vfi squared times four sine squared omega fi 117 00:08:38,970 --> 00:08:45,220 t0 over two over ef minus ei squared. 118 00:08:47,940 --> 00:08:54,490 And this is unit free. 119 00:08:54,490 --> 00:08:56,890 This has units of energy. 120 00:08:56,890 --> 00:08:59,470 V is a variation of the Hamiltonian. 121 00:08:59,470 --> 00:09:00,700 It has units of energy. 122 00:09:00,700 --> 00:09:04,420 When you put states, states are normalized 123 00:09:04,420 --> 00:09:07,240 so it doesn't change the units. 124 00:09:07,240 --> 00:09:11,020 And this has units of energy squared, this has no units, 125 00:09:11,020 --> 00:09:12,220 and this is the answer. 126 00:09:12,220 --> 00:09:14,620 A little strange. 127 00:09:14,620 --> 00:09:22,140 There's a periodic variation on the transition probability, 128 00:09:22,140 --> 00:09:26,980 and what does it mean to have a weak perturbation we 129 00:09:26,980 --> 00:09:28,210 can ask already? 130 00:09:28,210 --> 00:09:31,780 And the answer in general is quite simple. 131 00:09:31,780 --> 00:09:34,020 It's a pragmatic answer. 132 00:09:34,020 --> 00:09:37,000 A perturbation is weak if this answer 133 00:09:37,000 --> 00:09:39,400 is very little, very small. 134 00:09:39,400 --> 00:09:43,330 Suppose this probability comes out to be three, 135 00:09:43,330 --> 00:09:45,490 you know it's already too big. 136 00:09:45,490 --> 00:09:49,060 But if this is 10 to the minus sixth times this function, 137 00:09:49,060 --> 00:09:50,320 that's reasonable. 138 00:09:50,320 --> 00:09:53,020 You're shining atoms and one in a million 139 00:09:53,020 --> 00:09:55,090 goes and gets ionized. 140 00:09:55,090 --> 00:09:56,710 That's a reasonable thing. 141 00:09:56,710 --> 00:10:01,750 So the perturbation theory is valid for whatever time 142 00:10:01,750 --> 00:10:06,310 you use this formula as long as this number is small, 143 00:10:06,310 --> 00:10:11,410 and this could be arranged by having Vfi sufficiently small. 144 00:10:11,410 --> 00:10:14,470 I want to understand this function better, 145 00:10:14,470 --> 00:10:18,170 because this is a transition from initial state 146 00:10:18,170 --> 00:10:19,840 to final state that looks like that. 147 00:10:19,840 --> 00:10:22,250 So let's understand it better. 148 00:10:22,250 --> 00:10:31,330 Suppose one, Ef is different from Ei, then how does it look? 149 00:10:31,330 --> 00:10:34,630 Well, it looks like this. 150 00:10:34,630 --> 00:10:37,840 I brought some other chalk not that it helps too much. 151 00:10:37,840 --> 00:10:45,600 But it looks like this as a function of time. 152 00:10:49,050 --> 00:10:56,970 The height here is height four Vfi 153 00:10:56,970 --> 00:11:04,350 squared over Ef minus Ei squared, and it's oscillatory. 154 00:11:04,350 --> 00:11:09,900 It goes to zero again at time 2 pi over omega fi. 155 00:11:13,010 --> 00:11:16,250 OK, so this is the oscillation. 156 00:11:16,250 --> 00:11:23,680 Actually for a small time, this grows quadratically, 157 00:11:23,680 --> 00:11:26,400 and then it starts blowing up. 158 00:11:29,060 --> 00:11:32,200 So here while the initial behavior 159 00:11:32,200 --> 00:11:35,470 would be quadratic for small time, 160 00:11:35,470 --> 00:11:39,470 this actually is quadratic as we will see in a second, 161 00:11:39,470 --> 00:11:43,480 but you can more or less see by the expansion of the sine, 162 00:11:43,480 --> 00:11:48,880 then the initial quadratic growth gets tamed and becomes 163 00:11:48,880 --> 00:11:52,630 an oscillation here. 164 00:11:52,630 --> 00:11:58,120 This is valid for all times if this number is relatively small 165 00:11:58,120 --> 00:12:02,830 so that we believe perturbation theory, 166 00:12:02,830 --> 00:12:06,910 and that's that for that case. 167 00:12:06,910 --> 00:12:10,900 It's also interesting that this gets suppressed 168 00:12:10,900 --> 00:12:15,010 as the energy of the final state is different, more 169 00:12:15,010 --> 00:12:17,810 and more different, from the energy of the initial state. 170 00:12:17,810 --> 00:12:22,370 So it always oscillates, but if the state your transition 171 00:12:22,370 --> 00:12:26,380 is very far away, it is going to be extremely suppressed 172 00:12:26,380 --> 00:12:28,040 by the quadratic factors. 173 00:12:28,040 --> 00:12:30,250 So this is an important suppression. 174 00:12:30,250 --> 00:12:36,920 This is saying that transitions that change the energy 175 00:12:36,920 --> 00:12:40,540 are not that favored. 176 00:12:40,540 --> 00:12:45,640 A constant perturbation doesn't supply really 177 00:12:45,640 --> 00:12:50,590 energy to produce transitions that change the energy much, 178 00:12:50,590 --> 00:12:52,390 and they are suppressed. 179 00:12:52,390 --> 00:12:55,450 So they produce them, but they are suppressed. 180 00:12:55,450 --> 00:12:57,550 The other case that is of interest 181 00:12:57,550 --> 00:13:02,420 is the case when Ef is equal to Ei. 182 00:13:02,420 --> 00:13:07,580 I'm not saying that the state f is the same as the state i. 183 00:13:07,580 --> 00:13:08,470 Not at all. 184 00:13:08,470 --> 00:13:10,630 It's a different state but happens 185 00:13:10,630 --> 00:13:16,010 to have the same energy, and in that case, 186 00:13:16,010 --> 00:13:19,590 we must take the limit as Ef goes 187 00:13:19,590 --> 00:13:26,660 to Ei, remember omega fi is Ef minus Ei so over h bar. 188 00:13:26,660 --> 00:13:38,780 So the limit as ef goes to Ei of this Pif is how much. 189 00:13:41,530 --> 00:13:44,390 I'll kind of do it in my head here. 190 00:13:44,390 --> 00:13:50,750 We have an h bar here that is going to be left over. 191 00:13:50,750 --> 00:13:55,010 One over h bar, so h bar squared. 192 00:13:55,010 --> 00:13:56,300 This is going to cancel. 193 00:13:56,300 --> 00:13:59,480 The four is going to cancel with this, 194 00:13:59,480 --> 00:14:04,640 and we're going to get vfi squared 195 00:14:04,640 --> 00:14:11,000 over h squared t0 squared. 196 00:14:11,000 --> 00:14:14,750 OK, so here it is, the quadratic behavior 197 00:14:14,750 --> 00:14:17,480 when the energy of the final state 198 00:14:17,480 --> 00:14:21,390 is the same as the energy of your original state. 199 00:14:21,390 --> 00:14:25,910 Now, the transition probability starts to grow quadratically. 200 00:14:25,910 --> 00:14:30,590 That cannot be valid for too long time, 201 00:14:30,590 --> 00:14:34,880 because eventually that number grows without bound, 202 00:14:34,880 --> 00:14:37,530 and that number could become as big as 1, 203 00:14:37,530 --> 00:14:46,110 and that transition is not reasonable. 204 00:14:46,110 --> 00:14:59,660 So this is valid up to some max t0. 205 00:14:59,660 --> 00:15:03,500 And it's up to you, depends on what Vfi is, 206 00:15:03,500 --> 00:15:05,150 how long you can trust this. 207 00:15:05,150 --> 00:15:06,900 So this is a growth. 208 00:15:06,900 --> 00:15:10,800 This is the same growth we observe here. 209 00:15:10,800 --> 00:15:15,580 The limit as Ef goes to Ei go to zero 210 00:15:15,580 --> 00:15:18,950 is actually the same as the limit as t goes to zero, 211 00:15:18,950 --> 00:15:22,940 so it's the same quadratic behavior. 212 00:15:22,940 --> 00:15:27,150 So finally, what's going to happen? 213 00:15:27,150 --> 00:15:30,950 What are we aiming here? 214 00:15:30,950 --> 00:15:34,850 Well, we're aiming to the case where 215 00:15:34,850 --> 00:15:41,870 we have in the energy line, we have the initial energy Ei 216 00:15:41,870 --> 00:15:49,070 and then we're going to have a continuum of final states 217 00:15:49,070 --> 00:15:50,880 that overlap with Ei. 218 00:15:54,480 --> 00:15:57,040 They're all over there. 219 00:15:57,040 --> 00:16:02,530 That's Ef all over there. 220 00:16:02,530 --> 00:16:06,160 Of course with our box, if you come with your microscope, 221 00:16:06,160 --> 00:16:07,400 you see lines here. 222 00:16:10,080 --> 00:16:11,850 But they're all there. 223 00:16:11,850 --> 00:16:16,170 There is a continuum overlapping with this, 224 00:16:16,170 --> 00:16:21,210 and now we're going to attempt to sum over the continuum. 225 00:16:21,210 --> 00:16:22,755 And what should we observe? 226 00:16:25,590 --> 00:16:29,640 We should observe that when we add the continuum 227 00:16:29,640 --> 00:16:33,310 physically, what do we need? 228 00:16:33,310 --> 00:16:41,430 We need to find what is called a transition rate, in which you 229 00:16:41,430 --> 00:16:47,160 have the probability of transition per unit time 230 00:16:47,160 --> 00:16:48,402 is a constant. 231 00:16:48,402 --> 00:16:49,860 You see, you have a phenom-- you're 232 00:16:49,860 --> 00:16:52,800 shining light on an atom. 233 00:16:52,800 --> 00:16:55,080 OK, you shine light and you wait. 234 00:16:55,080 --> 00:16:57,640 Eventually the atom ionizes-- 235 00:16:57,640 --> 00:17:00,220 photoelectric effect. 236 00:17:00,220 --> 00:17:03,320 But if you have a billion atoms, then you can shine light 237 00:17:03,320 --> 00:17:06,520 and you're going to have a transition rate, basically how 238 00:17:06,520 --> 00:17:10,300 many atoms are going to happen to ionize. 239 00:17:10,300 --> 00:17:13,480 So in order to have a transition rate, 240 00:17:13,480 --> 00:17:18,579 the probability that you transition 241 00:17:18,579 --> 00:17:22,089 has to be proportional to the time 242 00:17:22,089 --> 00:17:25,550 that the perturbation has been acting. 243 00:17:25,550 --> 00:17:33,110 So the probability of transition must grow linear in t. 244 00:17:33,110 --> 00:17:35,660 Therefore, you have a transition rate 245 00:17:35,660 --> 00:17:39,320 which is the probability of transition per unit time, 246 00:17:39,320 --> 00:17:42,770 so you can grow linear in time, so per unit time 247 00:17:42,770 --> 00:17:44,720 you have a transition rate. 248 00:17:44,720 --> 00:17:48,050 So somehow look what's happening here. 249 00:17:48,050 --> 00:17:53,630 When Ef is different than Ei, the transition probability 250 00:17:53,630 --> 00:17:55,460 is not linear in time. 251 00:17:55,460 --> 00:17:57,110 It does this. 252 00:17:57,110 --> 00:18:00,800 When E approaches-- 253 00:18:00,800 --> 00:18:04,430 Ef approaches Ei, the probability of transition 254 00:18:04,430 --> 00:18:07,700 goes quadratic in time, and what we want 255 00:18:07,700 --> 00:18:12,080 is a probability of transition that grows linear in time. 256 00:18:12,080 --> 00:18:15,560 That would define a transition rate. 257 00:18:15,560 --> 00:18:19,530 So how is that going to happen? 258 00:18:19,530 --> 00:18:22,940 Well, we'll see it happen in front of our eyes. 259 00:18:22,940 --> 00:18:26,700 The magic of integration is going to do it. 260 00:18:26,700 --> 00:18:28,400 And moreover, we're going to see that 261 00:18:28,400 --> 00:18:32,480 consistent with this intuition, most of the transitions 262 00:18:32,480 --> 00:18:37,100 that are relevant are happening within Heisenberg's uncertainty 263 00:18:37,100 --> 00:18:43,610 principle of a little energy interval here around Ei. 264 00:18:43,610 --> 00:18:47,720 So this will be considered to be at the end of the day energy 265 00:18:47,720 --> 00:18:50,030 conserving transitions. 266 00:18:50,030 --> 00:18:55,280 The Hamiltonian, the delta V helps the transition happen 267 00:18:55,280 --> 00:18:59,070 but doesn't supply energy at the end of the day. 268 00:18:59,070 --> 00:19:02,290 So this is what we're getting to.