1 00:00:00,500 --> 00:00:02,230 PROFESSOR: OK, so we're good to consider, 2 00:00:02,230 --> 00:00:03,960 therefore, the two cases. 3 00:00:03,960 --> 00:00:08,109 So let's consider the first case, 4 00:00:08,109 --> 00:00:10,420 that this can be pretty important, 5 00:00:10,420 --> 00:00:19,380 this case one, when omega fi plus omega is nearly 0. 6 00:00:19,380 --> 00:00:22,560 In this case, what's happening? 7 00:00:22,560 --> 00:00:32,340 You have Ef minus Ei plus h bar omega is nearly 0, 8 00:00:32,340 --> 00:00:41,700 or Ef roughly equal to Ei minus h bar omega. 9 00:00:41,700 --> 00:00:46,900 So what has happened if you have a number-- so the question is, 10 00:00:46,900 --> 00:00:51,540 when this happens, which means that your omega-- 11 00:00:51,540 --> 00:00:53,550 that is, your perturbation-- 12 00:00:53,550 --> 00:01:00,000 is tailored to produce this, then Ef is Ei minus h omega. 13 00:01:00,000 --> 00:01:03,450 So you can think of the energy scale here. 14 00:01:03,450 --> 00:01:06,200 And Ef is lower than Ei. 15 00:01:09,270 --> 00:01:12,340 And the difference is h bar omega. 16 00:01:12,340 --> 00:01:13,780 So what is this process? 17 00:01:16,790 --> 00:01:21,760 This process is called stimulated emission. 18 00:01:21,760 --> 00:01:25,000 And why is that called stimulated emission? 19 00:01:25,000 --> 00:01:29,830 Because you're going from a state of energy Ei 20 00:01:29,830 --> 00:01:33,790 to a state of energy Ef that has lower energy. 21 00:01:33,790 --> 00:01:40,270 In that process, you're releasing energy h bar omega 22 00:01:40,270 --> 00:01:43,780 to the perturbation. 23 00:01:43,780 --> 00:01:49,350 So it's almost-- you would say it's 24 00:01:49,350 --> 00:01:52,660 stimulated because the perturbation did it. 25 00:01:52,660 --> 00:01:55,750 Still, it almost seems like something the system 26 00:01:55,750 --> 00:01:58,480 would do by itself. 27 00:01:58,480 --> 00:01:59,770 It has higher energy. 28 00:01:59,770 --> 00:02:04,330 It can go to lower energy and emit something with frequency 29 00:02:04,330 --> 00:02:06,430 with energy h omega. 30 00:02:06,430 --> 00:02:10,180 But it does that only because there is a perturbation. 31 00:02:10,180 --> 00:02:15,050 If there was no perturbation, this would not happen. 32 00:02:15,050 --> 00:02:19,130 That's why, say if you consider a hydrogen atom or a system, 33 00:02:19,130 --> 00:02:22,720 it's not that the electron that is in a higher state just 34 00:02:22,720 --> 00:02:26,020 jumps by itself down. 35 00:02:26,020 --> 00:02:29,230 It jumps by itself out because it can couple 36 00:02:29,230 --> 00:02:30,910 to other degrees of freedom. 37 00:02:30,910 --> 00:02:34,090 And in particular, it can couple to an electromagnetic field 38 00:02:34,090 --> 00:02:35,450 and send out the photon. 39 00:02:35,450 --> 00:02:41,650 So here, you have stimulated emission of energy h bar omega. 40 00:02:41,650 --> 00:02:47,680 So stimulated emission-- emission. 41 00:02:54,720 --> 00:03:00,630 And then the other term corresponds to the case 42 00:03:00,630 --> 00:03:08,450 when omega fi minus omega is equal to 0, in which case 43 00:03:08,450 --> 00:03:14,610 Ef is equal Ei plus h bar omega. 44 00:03:14,610 --> 00:03:23,460 This time, Ef is higher than Ei h bar omega. 45 00:03:23,460 --> 00:03:25,890 And this process is called absorption-- 46 00:03:28,750 --> 00:03:29,750 absorption. 47 00:03:34,160 --> 00:03:39,900 You absorb energy h bar omega from the perturbation. 48 00:03:39,900 --> 00:03:46,790 The perturbation is capable of giving the system energy h bar 49 00:03:46,790 --> 00:03:53,720 omega to enable a transition between Ei and Ef. 50 00:03:53,720 --> 00:04:00,600 So this harmonic perturbation has two tricks up its sleeve. 51 00:04:00,600 --> 00:04:05,900 It can push you up by giving you energy, 52 00:04:05,900 --> 00:04:10,520 or it can stimulate you to go to a lower state 53 00:04:10,520 --> 00:04:14,060 and give energy to the system represented 54 00:04:14,060 --> 00:04:16,670 by the perturbation. 55 00:04:16,670 --> 00:04:21,230 So two good things it can do, and both cases 56 00:04:21,230 --> 00:04:22,440 are pretty important. 57 00:04:22,440 --> 00:04:26,190 So we're going to develop one of these cases. 58 00:04:26,190 --> 00:04:28,670 The other one has exactly the same formulas. 59 00:04:28,670 --> 00:04:32,790 And we need the Fermi golden rule for this situation. 60 00:04:32,790 --> 00:04:35,510 So that's what I'll do right now. 61 00:04:35,510 --> 00:04:39,680 To fix our notation, let's just do the case of absorption. 62 00:04:42,200 --> 00:04:46,190 But both are going to be taken care simultaneously. 63 00:04:46,190 --> 00:04:54,980 So absorption-- so what is C? 64 00:04:54,980 --> 00:04:59,210 So when you're doing absorption, you're saying, OK. 65 00:04:59,210 --> 00:05:03,510 I'm basically having this process in which Ef 66 00:05:03,510 --> 00:05:07,730 is related to Ei in this way. 67 00:05:07,730 --> 00:05:12,040 This term is becoming 0. 68 00:05:12,040 --> 00:05:14,310 And this term is negligible. 69 00:05:14,310 --> 00:05:18,822 So you can completely ignore one term 70 00:05:18,822 --> 00:05:20,030 when you're doing absorption. 71 00:05:20,030 --> 00:05:22,010 And you can ignore the other term 72 00:05:22,010 --> 00:05:24,770 when you're doing a stimulated emission. 73 00:05:24,770 --> 00:05:27,080 You would say, oh, but it's not exact. 74 00:05:27,080 --> 00:05:28,540 What about if I keep it? 75 00:05:28,540 --> 00:05:33,140 Well, there are many things that we don't do exact. 76 00:05:33,140 --> 00:05:37,520 This term is much bigger than the other-- 77 00:05:37,520 --> 00:05:39,680 in principle, infinitely bigger-- 78 00:05:39,680 --> 00:05:41,430 because we're going to be integrated 79 00:05:41,430 --> 00:05:43,360 over a narrow set of states. 80 00:05:43,360 --> 00:05:47,270 So it would make no sense to keep those other things. 81 00:05:47,270 --> 00:05:50,720 Those other terms would be much smaller, probably, 82 00:05:50,720 --> 00:05:53,970 at even the next order of perturbation theory. 83 00:05:53,970 --> 00:05:59,040 So we keep, therefore, the second term. 84 00:05:59,040 --> 00:06:01,110 And so what do we have? 85 00:06:01,110 --> 00:06:13,130 Cf of t naught 1 minus H fi prime over h bar, e 86 00:06:13,130 --> 00:06:21,800 to the i omega fi minus omega t over 2. 87 00:06:21,800 --> 00:06:24,240 You don't see that term, of course. 88 00:06:24,240 --> 00:06:29,030 But I'm going to take out half of this phase 89 00:06:29,030 --> 00:06:33,880 so that I get a sine function out here. 90 00:06:33,880 --> 00:06:35,700 So I took out half of the phase. 91 00:06:35,700 --> 00:06:44,910 And then I get 2i sine omega fi minus omega t over 2. 92 00:06:48,660 --> 00:06:52,140 OK, that's this thing. 93 00:06:52,140 --> 00:06:56,870 So the probability to go from initial to final state 94 00:06:56,870 --> 00:07:07,580 at time t naught would be the C f1 of t naught squared. 95 00:07:07,580 --> 00:07:18,590 And that's 4H fi prime, because of the two here. 96 00:07:18,590 --> 00:07:24,660 It's 4H fi prime squared over h squared 97 00:07:24,660 --> 00:07:34,130 sine squared of omega fi minus omega over 2 times time 98 00:07:34,130 --> 00:07:40,260 over omega fi minus omega squared. 99 00:07:40,260 --> 00:07:50,320 And this is all for Ef roughly equal to Ei plus h bar omega. 100 00:07:50,320 --> 00:07:51,760 So I didn't do much. 101 00:07:51,760 --> 00:07:55,270 I really didn't do all that much so far. 102 00:07:55,270 --> 00:08:00,370 I just took the second term, rewrote it with a sine, 103 00:08:00,370 --> 00:08:02,410 and calculated its norm squared. 104 00:08:02,410 --> 00:08:06,340 That's the probability to go from initial to final states. 105 00:08:14,510 --> 00:08:20,160 So the last step is integrating over a final state. 106 00:08:20,160 --> 00:08:24,960 So you have this sum over final states of this probability 107 00:08:24,960 --> 00:08:27,960 to go to the final state. 108 00:08:27,960 --> 00:08:32,730 And we'll write it as the integral over the set of states 109 00:08:32,730 --> 00:08:39,840 rho of e final dE final probability 110 00:08:39,840 --> 00:08:44,505 final to initial of t naught. 111 00:08:47,930 --> 00:08:50,940 And this is the same calculation we were doing before. 112 00:08:54,040 --> 00:09:02,130 And for this calculation, we just substitute what P fi is. 113 00:09:02,130 --> 00:09:06,480 We assume that as we integrate, we're 114 00:09:06,480 --> 00:09:11,280 going to have a narrow range so that this function, rho 115 00:09:11,280 --> 00:09:17,630 of Ef and h prime fi can go out of the integral. 116 00:09:17,630 --> 00:09:19,465 So what are we going to have? 117 00:09:22,280 --> 00:09:24,050 I'll write it here. 118 00:09:24,050 --> 00:09:30,790 4-- from the matrix element, from this thing-- 119 00:09:30,790 --> 00:09:35,240 H fi prime squared over h squared. 120 00:09:39,960 --> 00:09:42,430 That goes out. 121 00:09:42,430 --> 00:09:45,020 Then the rho of Ef goes out. 122 00:09:45,020 --> 00:09:48,840 So I'll write it rho of Ef. 123 00:09:48,840 --> 00:09:51,070 And rather than leaving it like Ef, 124 00:09:51,070 --> 00:09:56,040 like that, because it seems like a variable, still, 125 00:09:56,040 --> 00:09:58,050 of integration-- if I take it out, 126 00:09:58,050 --> 00:10:00,900 I should be explicit what this Ef is. 127 00:10:00,900 --> 00:10:03,015 And in this case, Ef-- 128 00:10:03,015 --> 00:10:04,720 we're doing absorption. 129 00:10:04,720 --> 00:10:10,590 So this is equal to Ei plus h bar omega. 130 00:10:10,590 --> 00:10:13,290 That's this central contribution. 131 00:10:13,290 --> 00:10:16,440 And that's where you're taking rho out. 132 00:10:16,440 --> 00:10:20,790 So this is pretty important. 133 00:10:20,790 --> 00:10:24,840 This rho is evaluated at the final energy, 134 00:10:24,840 --> 00:10:31,560 which in this process is h omega in addition to Ei. 135 00:10:31,560 --> 00:10:37,185 And then the rest of the integral dE f-- 136 00:10:37,185 --> 00:10:40,500 you still have dE f-- and the sine function. 137 00:10:40,500 --> 00:10:49,500 So sine squared of omega fi minus omega t over-- 138 00:10:49,500 --> 00:10:50,780 t naught, I'm sorry. 139 00:10:50,780 --> 00:10:54,150 I'm missing t naught everywhere. 140 00:10:54,150 --> 00:10:56,770 But I did copy it. 141 00:10:56,770 --> 00:10:58,890 t naught and t naught's up there. 142 00:11:02,440 --> 00:11:10,150 Over 2 over omega fi minus omega squared. 143 00:11:10,150 --> 00:11:14,270 And this is the story of the lobes. 144 00:11:14,270 --> 00:11:20,410 This is the function that has the lobes as a function of Ef. 145 00:11:20,410 --> 00:11:23,020 As a function of Ef, this quantity 146 00:11:23,020 --> 00:11:26,440 varies and starts developing the lobes. 147 00:11:26,440 --> 00:11:33,620 And the lobes happen for values of Ef 148 00:11:33,620 --> 00:11:38,310 that are separated by some h bar divided by t naught. 149 00:11:38,310 --> 00:11:41,970 So this is the exact same integral 150 00:11:41,970 --> 00:11:45,480 we analyzed for the constant transitions. 151 00:11:45,480 --> 00:11:47,400 And it is the same integral that we 152 00:11:47,400 --> 00:11:53,370 argued that could be done as a sine squared x over x squared. 153 00:11:53,370 --> 00:11:56,770 So I will not do it again. 154 00:11:56,770 --> 00:12:02,440 This integral gives h bar linear in t naught over 2 pi. 155 00:12:05,670 --> 00:12:08,190 When you study this, you will have the notes 156 00:12:08,190 --> 00:12:09,570 and you can review it. 157 00:12:09,570 --> 00:12:11,850 If you've taken notes, you will see 158 00:12:11,850 --> 00:12:14,460 that is exactly the same integral 159 00:12:14,460 --> 00:12:20,850 we had last time, except that we didn't have the omega, which 160 00:12:20,850 --> 00:12:22,650 really doesn't change things. 161 00:12:22,650 --> 00:12:25,680 It just shifts the zero. 162 00:12:25,680 --> 00:12:28,920 So the peak of this contribution is when 163 00:12:28,920 --> 00:12:31,620 omega fi is equal to omega. 164 00:12:31,620 --> 00:12:36,930 Before when we did it was when omega fi was equal to 0. 165 00:12:36,930 --> 00:12:39,690 That's why, in the constant transitions 166 00:12:39,690 --> 00:12:42,780 you conserved energy. 167 00:12:42,780 --> 00:12:49,950 So with this result in there, the whole answer 168 00:12:49,950 --> 00:12:53,235 here is 2 pi over h bar-- 169 00:12:59,820 --> 00:13:04,050 h bar only because one h bar cancels, indeed-- 170 00:13:04,050 --> 00:13:16,690 rho at Ef equal Ei plus h omega H fi prime 171 00:13:16,690 --> 00:13:19,840 squared times t naught. 172 00:13:19,840 --> 00:13:26,300 That's all that is left, which is great because that 173 00:13:26,300 --> 00:13:29,270 is our Fermi's golden rule. 174 00:13:29,270 --> 00:13:32,510 Remember, that's a transition probability. 175 00:13:32,510 --> 00:13:36,350 And the rate is obtained by dividing this 176 00:13:36,350 --> 00:13:41,150 by the time that has elapsed to find the probability per unit 177 00:13:41,150 --> 00:13:41,930 time. 178 00:13:41,930 --> 00:13:44,550 That's the rate. 179 00:13:44,550 --> 00:13:47,330 It's probability for transition per unit, 180 00:13:47,330 --> 00:13:58,970 times 2 pi over h bar rho at Ef equal Ei plus h bar 181 00:13:58,970 --> 00:14:10,670 omega times the matrix element f H prime initial squared. 182 00:14:10,670 --> 00:14:16,490 That's Fermi's golden rule for harmonic transitions, 183 00:14:16,490 --> 00:14:19,700 and in particular, for absorption. 184 00:14:19,700 --> 00:14:24,650 But stimulated emission, the calculation 185 00:14:24,650 --> 00:14:26,720 is completely analogous. 186 00:14:26,720 --> 00:14:32,300 So the end result for stimulated emission is just minus H omega. 187 00:14:32,300 --> 00:14:35,850 The final energy now is this one. 188 00:14:35,850 --> 00:14:38,150 So the top sine-- 189 00:14:38,150 --> 00:14:46,630 plus is for absorption, minus for stimulated emission. 190 00:14:56,490 --> 00:14:59,910 And if you want a reminder here, it 191 00:14:59,910 --> 00:15:10,350 was that delta H was 2H prime cosine omega t. 192 00:15:10,350 --> 00:15:16,710 So this reminds you that this H prime you have here 193 00:15:16,710 --> 00:15:19,620 is the matrix element of the perturbation 194 00:15:19,620 --> 00:15:20,820 with this convention. 195 00:15:20,820 --> 00:15:23,670 This omega you have here is the frequency 196 00:15:23,670 --> 00:15:26,040 of the perturbing Hamiltonian. 197 00:15:26,040 --> 00:15:27,510 And that's what has happened. 198 00:15:30,810 --> 00:15:34,920 So this is Fermi's golden rule. 199 00:15:34,920 --> 00:15:35,610 It's over. 200 00:15:35,610 --> 00:15:40,050 We've done it, done it basically for two cases-- 201 00:15:40,050 --> 00:15:44,010 the constant perturbation and the harmonic perturbation. 202 00:15:44,010 --> 00:15:45,640 And there's a lot of physics here 203 00:15:45,640 --> 00:15:51,750 that we will be exploring starting now, but continuing 204 00:15:51,750 --> 00:15:58,260 with atoms and radiation in general, atomic transitions. 205 00:15:58,260 --> 00:16:00,870 W is the rate. 206 00:16:00,870 --> 00:16:05,484 So this is called the transition rate per unit time-- 207 00:16:05,484 --> 00:16:14,290 transition rate per unit time. 208 00:16:14,290 --> 00:16:18,940 So the probability of transition or probability 209 00:16:18,940 --> 00:16:23,060 of transition per unit time-- 210 00:16:23,060 --> 00:16:30,130 probability of transition per unit time-- 211 00:16:33,510 --> 00:16:36,060 that's probably more understandable than the word 212 00:16:36,060 --> 00:16:37,260 rate. 213 00:16:37,260 --> 00:16:43,020 So this P fi gives you the probability of transition 214 00:16:43,020 --> 00:16:46,200 after a time t naught. 215 00:16:46,200 --> 00:16:48,570 Happily, it's proportional to t naught, 216 00:16:48,570 --> 00:16:52,020 so you divide by the time that has elapsed, 217 00:16:52,020 --> 00:16:55,710 and it's a probability of transition per unit time. 218 00:16:55,710 --> 00:16:58,290 So once you compute this number, you 219 00:16:58,290 --> 00:17:01,770 get the probability of transition per unit time. 220 00:17:01,770 --> 00:17:06,150 So if this W is something and you have a billion atoms, 221 00:17:06,150 --> 00:17:09,500 you multiply that probability by the number of atoms you have, 222 00:17:09,500 --> 00:17:12,590 and you know how many have decayed already.