1 00:00:00,860 --> 00:00:02,870 Let us now discuss an interesting fact about 2 00:00:02,870 --> 00:00:06,360 independence that should enhance our understanding. 3 00:00:06,360 --> 00:00:10,810 Suppose that events A and B are independent. 4 00:00:10,810 --> 00:00:14,620 Intuitively, if I tell you that A occurred, this does not 5 00:00:14,620 --> 00:00:18,810 change your beliefs as to the likelihood that B will occur. 6 00:00:18,810 --> 00:00:22,955 But in that case, this should not change your beliefs as to 7 00:00:22,955 --> 00:00:26,870 the likelihood that B will not occur. 8 00:00:26,870 --> 00:00:30,900 So A should be independent of B complement. 9 00:00:30,900 --> 00:00:35,110 In other words, the occurrence of A tells you nothing about 10 00:00:35,110 --> 00:00:38,140 B, and therefore tells you nothing about 11 00:00:38,140 --> 00:00:40,370 B complement either. 12 00:00:40,370 --> 00:00:43,300 This was an intuitive argument that if A and B are 13 00:00:43,300 --> 00:00:46,590 independent, then A and B complement are also 14 00:00:46,590 --> 00:00:47,990 independent. 15 00:00:47,990 --> 00:00:50,210 But let us now verify this intuition 16 00:00:50,210 --> 00:00:52,180 through a formal proof. 17 00:00:52,180 --> 00:00:54,320 The formal proof goes as follows. 18 00:00:54,320 --> 00:01:02,430 We have the two events, A and B. And event A can be broken 19 00:01:02,430 --> 00:01:04,930 down into two pieces. 20 00:01:04,930 --> 00:01:12,400 One piece is the intersection of A with B. So that's the 21 00:01:12,400 --> 00:01:14,880 first piece. 22 00:01:14,880 --> 00:01:21,470 And the second piece is the part of A which is outside B. 23 00:01:21,470 --> 00:01:25,370 And that piece is A intersection with the 24 00:01:25,370 --> 00:01:30,800 complement of B. So these are the two pieces that together 25 00:01:30,800 --> 00:01:33,720 comprise event A. 26 00:01:33,720 --> 00:01:37,120 Now, these two pieces are disjoint from each other. 27 00:01:37,120 --> 00:01:40,610 And therefore, by the additivity axiom, the 28 00:01:40,610 --> 00:01:46,259 probability of A is equal to the probability of A 29 00:01:46,259 --> 00:01:51,120 intersection B plus the probability of A intersection 30 00:01:51,120 --> 00:01:54,539 with B complement. 31 00:01:54,539 --> 00:02:00,060 Using independence, the first term becomes probability of A 32 00:02:00,060 --> 00:02:07,540 times probability of B. And we leave the second term as is. 33 00:02:07,540 --> 00:02:10,478 Now let us move this term to the other side. 34 00:02:10,478 --> 00:02:14,190 And we obtain that the probability of A intersection 35 00:02:14,190 --> 00:02:19,120 with B complement is the probability of A minus the 36 00:02:19,120 --> 00:02:23,820 probability of A times the probability of B. We factor 37 00:02:23,820 --> 00:02:28,790 out the term probability of A, and we are left with 1 minus 38 00:02:28,790 --> 00:02:35,420 probability of B. And then we recognize that 1 minus the 39 00:02:35,420 --> 00:02:38,750 probability of B is the same as the probability of B 40 00:02:38,750 --> 00:02:40,200 complement. 41 00:02:40,200 --> 00:02:44,920 So we proved that the probability of A and B 42 00:02:44,920 --> 00:02:48,010 complement occurring together is the product of their 43 00:02:48,010 --> 00:02:49,829 individual probabilities. 44 00:02:49,829 --> 00:02:53,230 And that's exactly the definition of A being 45 00:02:53,230 --> 00:02:55,140 independent from B complement. 46 00:02:55,140 --> 00:02:56,980 And this concludes the formal proof.