1 00:00:00,560 --> 00:00:02,850 Let us now take stock and summarize 2 00:00:02,850 --> 00:00:05,690 what we have done for these two processes, the Bernoulli 3 00:00:05,690 --> 00:00:08,520 and the Poisson process, and their relation. 4 00:00:08,520 --> 00:00:11,350 The Poisson process runs in continuous time, 5 00:00:11,350 --> 00:00:13,070 whereas, for the Bernoulli process, 6 00:00:13,070 --> 00:00:16,790 time is discrete and is divided into slots. 7 00:00:16,790 --> 00:00:20,440 The Poisson process is defined by a single parameter, lambda, 8 00:00:20,440 --> 00:00:23,220 which is the intensity or arrival rate, 9 00:00:23,220 --> 00:00:27,350 and tells us the expected number of arrivals per unit time. 10 00:00:27,350 --> 00:00:29,460 For the Bernoulli process, we have, again, 11 00:00:29,460 --> 00:00:32,520 one basic parameter, which is the probability of success 12 00:00:32,520 --> 00:00:35,170 at any given trial, or the probability 13 00:00:35,170 --> 00:00:39,790 of an arrival during each one of the slots. 14 00:00:39,790 --> 00:00:43,950 Based on our model, we were interested in three kinds 15 00:00:43,950 --> 00:00:45,470 of quantities. 16 00:00:45,470 --> 00:00:47,810 And we found the distributions of them. 17 00:00:47,810 --> 00:00:50,620 The first quantity is the number of arrivals 18 00:00:50,620 --> 00:00:52,820 during a certain time interval. 19 00:00:52,820 --> 00:00:55,630 For the discrete case, the number of arrivals 20 00:00:55,630 --> 00:00:58,730 has a binomial distribution, whereas for the one Poisson 21 00:00:58,730 --> 00:01:03,740 case, the distribution is that of a Poisson random variable. 22 00:01:03,740 --> 00:01:07,880 Then we looked at the time until the first arrival, 23 00:01:07,880 --> 00:01:11,000 or the time between consecutive arrivals. 24 00:01:11,000 --> 00:01:13,820 For the Bernoulli process, that distribution is geometric. 25 00:01:13,820 --> 00:01:17,180 For the Poisson process, that distribution is exponential. 26 00:01:17,180 --> 00:01:18,630 Note that in this instance, we're 27 00:01:18,630 --> 00:01:20,500 dealing with a discrete random variable, 28 00:01:20,500 --> 00:01:23,060 but, here, with a continuous random variable. 29 00:01:23,060 --> 00:01:24,970 And then, as a generalization, we 30 00:01:24,970 --> 00:01:29,570 could find the time until a kth arrival, which, in the Poisson 31 00:01:29,570 --> 00:01:33,090 case, is given by an Erlang distribution. 32 00:01:33,090 --> 00:01:35,140 And for the Bernoulli case, we developed 33 00:01:35,140 --> 00:01:36,500 one particular formula. 34 00:01:36,500 --> 00:01:38,220 And that formula is actually known 35 00:01:38,220 --> 00:01:42,420 under the name of the Pascal distribution. 36 00:01:42,420 --> 00:01:46,060 All of these results, for the Poisson case, 37 00:01:46,060 --> 00:01:50,530 were obtained because we used an approximation argument. 38 00:01:50,530 --> 00:01:53,960 That is, we had the results for the Bernoulli case. 39 00:01:53,960 --> 00:01:56,360 But then we argued that the Poisson process 40 00:01:56,360 --> 00:01:59,850 is a limiting case of the Bernoulli process 41 00:01:59,850 --> 00:02:05,080 in which we take time, divide it into a large number of slots, 42 00:02:05,080 --> 00:02:06,870 during each one of the slots, however, 43 00:02:06,870 --> 00:02:09,560 we have a small probability of an arrival. 44 00:02:09,560 --> 00:02:12,970 And this is done in a way so that the product of these two 45 00:02:12,970 --> 00:02:15,500 numbers stays a constant. 46 00:02:15,500 --> 00:02:18,590 By using a finer and finer discretization, 47 00:02:18,590 --> 00:02:22,990 we could approach the Poisson process arbitrarily 48 00:02:22,990 --> 00:02:25,250 close by a Bernoulli process. 49 00:02:25,250 --> 00:02:27,360 And then we used the Bernoulli formulas 50 00:02:27,360 --> 00:02:31,130 in which we took the limit as delta was going to zero. 51 00:02:31,130 --> 00:02:34,740 And this gave us the result for the Poisson case.