Unique Primes
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How many prime factors does \(40500\) have?
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How many unique prime factors does \(40500\) have?
The prime factorization of \(40500 = 2^2\cdot 3^4 \cdot 5^3\), so it is composed of \(2+4+3\) (non-unique) prime factors. However, only three of these are unique, namely \(2, 3\) and \(4\).